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		<title>Measurement of Temperature</title>
		<link>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/temperature-measurement/21256/</link>
					<comments>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/temperature-measurement/21256/#respond</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Sun, 04 Feb 2024 07:37:29 +0000</pubDate>
				<category><![CDATA[Thermodynamics]]></category>
		<category><![CDATA[Constant Pressure Gas Thermometer]]></category>
		<category><![CDATA[Constant Volume Gas Thermometer]]></category>
		<category><![CDATA[CPGT]]></category>
		<category><![CDATA[CVGT]]></category>
		<category><![CDATA[Liquid Crystal Thermometer]]></category>
		<category><![CDATA[Measurement of Temperature]]></category>
		<category><![CDATA[Mercury Thermometer]]></category>
		<category><![CDATA[Platinum Resistance Thermometer]]></category>
		<category><![CDATA[PRT]]></category>
		<category><![CDATA[Pyrometer]]></category>
		<category><![CDATA[Temperature]]></category>
		<category><![CDATA[Thermistors]]></category>
		<category><![CDATA[Thermocouple]]></category>
		<category><![CDATA[Thermometer]]></category>
		<guid isPermaLink="false">https://thefactfactor.com/?p=21256</guid>

					<description><![CDATA[<p>Science &#62; Physics &#62; Thermal Properties of Matter and Thermodynamics &#62; Measurement of Temperature LIST OF SUB-TOPICS: In last article, we have studied different temperature scales. In this article, we shall discuss methods of measurement of temperature and thermometers. Temperature can be defined in several ways: It is measured in °C (centigrade or Celsius) or [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/temperature-measurement/21256/">Measurement of Temperature</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
]]></description>
										<content:encoded><![CDATA[
<h6 class="wp-block-heading"><strong>Science &gt; <a href="https://thefactfactor.com/physics/" target="_blank" rel="noreferrer noopener">Physics</a> &gt; </strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/" target="_blank" rel="noreferrer noopener">Thermal Properties of Matter and Thermodynamics</a><strong> &gt; Measurement of Temperature</strong></h6>



<p class="has-primary-color has-text-color has-link-color wp-elements-2cc6b0efd2e8235f351df7ecd019ac00" id="Back"><strong>LIST OF SUB-TOPICS:</strong></p>



<ul class="wp-block-list">
<li><strong><a href="#Introduction">Introduction</a></strong></li>



<li><strong><a href="#Thermometer">Thermometer</a></strong></li>



<li><strong><a href="#MercuryThermometer">Mercury Thermometer</a></strong></li>



<li><strong><a href="#CVGT">Constant Volume Gas Thermometer (CVGT)</a></strong></li>



<li><strong><a href="#CPGT">Constant Pressure Gas Thermometer (CPGT)</a></strong></li>



<li><strong><a href="#PRT">Platinum Resistance Thermometer (PRT)</a></strong></li>



<li><strong><a href="#Thermocouple">Thermocouple</a></strong></li>



<li><strong><a href="#Pyrometer">Pyrometer</a></strong></li>



<li><a href="#Thermistor"><strong>Thermistors</strong></a></li>



<li><strong><a href="#LCT">Liquid Crystal Thermometer</a></strong></li>
</ul>



<p id="Introduction">In last article, we have studied different temperature scales. In this article, we shall discuss methods of measurement of temperature and thermometers.</p>



<p>Temperature can be defined in several ways:</p>



<ul class="wp-block-list">
<li>The temperature may be defined as the degree of hotness or coldness of a body.</li>



<li>The temperature of a body is an indicator of the average thermal energy (Kinetic energy) of the molecules of the body.</li>



<li>It is that physical quantity which decides the flow of heat in bodies brought in contact. Heat always flow from the body at higher temperature to the body at the lower temperature.</li>
</ul>



<p>It is measured in °C (centigrade or Celsius) or K (Kelvin). It is measured by a device called a thermometer. The common thermometer is a mercury thermometer.</p>



<p>The branch of Physics that deals with the measurement of temperature is called Thermometry.</p>



<p class="has-text-align-right"><strong><a href="#Back">Back to List of Sub-Topics</a></strong></p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-9e0486ffa69826b87ad049f1d823a3f3" id="Thermometer"><strong>Thermometer:</strong></p>



<p>A thermometer is an instrument used to measure temperature. It works based on the principle that certain physical properties of materials change with temperature. Thermometers typically contain a temperature-sensitive element, such as mercury, alcohol, or a thermocouple, which expands or contracts in response to temperature changes. Thermometers are widely used in various fields, including meteorology, medicine, food processing, and industrial processes, to monitor and control temperature.</p>



<p>Temperature is often measured with the use of a thermometer. To understand how thermometers work, one must first understand the concept of thermal equilibrium. Two bodies are said to be in thermal equilibrium with each other if no transfer of heat takes place when they are brought in contact, clearly, the two bodies are at the same temperature.</p>



<p class="has-text-align-right"><strong><a href="#Back">Back to List of Sub-Topics</a></strong></p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-c4429584c223e01a6a026e3eb84d9ae3" id="MercuryThermometer"><strong>Mercury Thermometer:</strong></p>



<p>A Mercury thermometer is a type of thermometer that uses mercury as the temperature-sensitive element. Mercury thermometer work on the principle of thermal expansion of liquids. In case of mercury thermometer, mercury (liquid) expands when the temperature increases. This rise in the level of mercury in the capillary gives the temperature readings.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-a11056d461c1215d9e565943a2f73d6c"><strong>Elements of Mercury Thermometer:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img fetchpriority="high" decoding="async" width="386" height="131" src="https://thefactfactor.com/wp-content/uploads/2024/02/Mercury-Thermometer.jpg" alt="Measurement of Temperature" class="wp-image-21260" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/Mercury-Thermometer.jpg 386w, https://thefactfactor.com/wp-content/uploads/2024/02/Mercury-Thermometer-300x102.jpg 300w" sizes="(max-width: 386px) 100vw, 386px" /></figure>
</div>


<ul class="wp-block-list">
<li><strong>Mercury as the Temperature-Sensitive Element:</strong> In a mercury thermometer, the temperature-sensitive element is a column of mercury contained within a glass capillary tube. Mercury is a suitable choice for thermometers because it expands and contracts in a uniform manner with changes in temperature and it does not stick to the glass.</li>



<li><strong>Glass Capillary Tube:</strong> The thermometer consists of a sealed glass tube with a small bulb at one end and a narrow capillary tube. The capillary tube contains the mercury column, and the bulb serves as a reservoir for the mercury.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-cbaccbf2d8136e8f8b14d5772cc95b93"><strong>Working of Mercury Thermometer</strong>:</p>



<p>As the temperature increases, the mercury inside the thermometer expands and rises up the capillary tube. Conversely, when the temperature decreases, the mercury contracts and retreats back into the bulb.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-6cc8b013b796e259faeb69f743977aca"><strong>Calibration:</strong></p>



<p>Mercury thermometers are calibrated to provide accurate temperature readings. The glass tube is marked with a scale that correlates the height of the mercury column with specific temperature values. The scale is often marked in Celsius (°C) or Fahrenheit (°F) degrees.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-a238740b266b9058ac9457f98fb09f7a"><strong>Advantages of Mercury Thermometer:</strong></p>



<p>Mercury thermometers have been widely used for temperature measurement in various fields for several reasons, which include the following advantages:</p>



<ul class="wp-block-list">
<li><strong>Accuracy:</strong> Mercury thermometers provide accurate temperature readings over a wide range of temperatures. Mercury expands and contracts uniformly with changes in temperature, allowing for precise measurement.</li>



<li><strong>Wide Range:</strong> Mercury thermometers cover a wide temperature range from −37 to 356 °C (−35 to 673 °F); the instrument&#8217;s upper temperature range may be extended through the introduction of an inert gas such as nitrogen.</li>



<li><strong>Thermal Conductivity:</strong> Mercury has a high thermal conductivity, meaning it responds quickly to changes in temperature. This characteristic enables mercury thermometers to provide relatively fast temperature readings compared to some other types of thermometers.</li>



<li><strong>Versatility:</strong> Mercury thermometers can measure temperatures across a broad range, making them suitable for various applications in laboratories, medical settings, and industrial environments.</li>



<li><strong>Linear Expansion:</strong> Mercury expands and contracts in a linear manner with changes in temperature, making it relatively easy to calibrate mercury thermometers for accurate temperature measurement.</li>



<li><strong>Ease of Reading:</strong> Mercury is opaque and shining. It does not stick to glass-sides. &nbsp;The clear glass tube and mercury column make it easy to read the temperature on a mercury thermometer. The markings on the scale are visible and straightforward to interpret.</li>



<li><strong>Longevity:</strong> When handled properly, mercury thermometers can last a long time without significant degradation in accuracy or performance.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-df877fa37cc98b96d476ea82add08044"><strong>Disadvantages of Mercury Thermometer:</strong></p>



<p>While mercury thermometers are accurate and reliable, they pose potential health and environmental hazards due to the toxicity of mercury. Accidental breakage of a mercury thermometer can release mercury vapour, which is harmful if inhaled. For this reason, many countries have phased out the use of mercury thermometers in favour of safer alternatives, such as digital thermometers or alcohol-filled thermometers.</p>



<p>Despite safety concerns, mercury thermometers have been widely used and have played a significant role in temperature measurement in various fields. However, their use is decreasing due to environmental and health considerations, and alternative thermometer technologies are becoming more prevalent.</p>



<p class="has-text-align-right"><strong><a href="#Back">Back to List of Sub-Topics</a></strong></p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-435bfc06694fca7e283d79ff0ab36025" id="CVGT"><strong>Constant Volume Gas Thermometer:</strong></p>



<p>A Constant Volume Gas Thermometer (CVGT), is a device used to measure temperature based on the principles of ideal gas behaviour. CVGT work on principle of Gay-Lussac’s law. Gay- Lussac&#8217;s Law states that when volume of a gas is constant, the pressure of the gas is directly proportional to its absolute temperature. As the temperature changes, the pressure changes accordingly. Measuring the pressure, temperature can be measured.</p>



<p>Constant volume gas thermometers are used primarily in scientific research and metrology (the science of measurement) for precise temperature measurements. They are often employed in situations where high accuracy and precision are required, such as in fundamental scientific experiments and calibration laboratories.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img decoding="async" width="351" height="230" src="https://thefactfactor.com/wp-content/uploads/2024/02/CVGT.jpg" alt="Measurement of Temperature" class="wp-image-21261" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/CVGT.jpg 351w, https://thefactfactor.com/wp-content/uploads/2024/02/CVGT-300x197.jpg 300w" sizes="(max-width: 351px) 100vw, 351px" /></figure>
</div>


<p class="has-accent-color has-text-color has-link-color wp-elements-d85ad7b5193b6feb6101c2f31129107b"><strong>Construction:</strong></p>



<p>The components of the apparatus are as follows:</p>



<ul class="wp-block-list">
<li><strong>Container:</strong> The CVGT consists of a container with a fixed volume. This container is typically made of a material that does not react with the gas being used and can withstand high pressures and temperature changes.</li>



<li><strong>Gas:</strong> The container is filled with a gas, often a noble gas like helium or argon, at a known pressure and temperature. The gas is chosen for its inert properties and its ability to follow the ideal gas law accurately over a wide range of temperatures and pressures.</li>



<li><strong>Pressure Measurement System:</strong> A pressure measurement system is integrated into the CVGT to measure the pressure of the gas inside the container. This system may include a manometer, Bourdon gauge, or other pressure sensing devices capable of accurately measuring the pressure of the gas.</li>



<li><strong>Thermometer:</strong> A thermometer is used to measure the temperature of the gas inside the container. This thermometer may be a separate device inserted into the container or integrated directly into the CVGT.</li>



<li><strong>Sealing Mechanism:</strong> The container of the CVGT must be tightly sealed to prevent gas leaks and maintain a constant volume. The sealing mechanism may involve O-rings, gaskets, or other sealing materials capable of withstanding high pressures and temperature changes.</li>



<li><strong>Supporting Components:</strong> Various supporting components such as valves, fittings, and pressure regulators may be included in the construction of the CVGT to facilitate gas handling, pressure control, and temperature measurement.</li>



<li><strong>Calibration:</strong> The CVGT is calibrated by measuring the pressure of the gas at two known temperature points, typically at the freezing and boiling points of water under standard atmospheric pressure. These temperature-pressure data points are then used to establish a temperature-pressure relationship for the gas.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-528bad42817701d711e93b832a43bf14"><strong>Measurement of Temperature:</strong></p>



<p>Once calibrated, the CVGT can be used to measure temperatures by measuring the pressure of the gas at the temperature of interest and using the established temperature-pressure relationship to determine the corresponding temperature.</p>



<p class="has-text-align-center">By Gay Lussac’s Law at constant volume of a gas</p>



<p class="has-text-align-center">P α T</p>



<p class="has-text-align-center">Thus</p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img decoding="async" width="166" height="94" src="https://thefactfactor.com/wp-content/uploads/2021/06/Pressure-Temperature-Relation-02.png" alt="" class="wp-image-16895" style="width:86px;height:auto"/></figure>
</div>


<p class="has-text-align-center">Where, P<sub>1</sub> = Initial Pressure (Known)</p>



<p class="has-text-align-center">T<sub>1</sub> = Initial Absolute Temperature (Known)</p>



<p class="has-text-align-center">P<sub>2</sub> = Final Pressure (To be measured)</p>



<p class="has-text-align-center">T<sub>2</sub> = Final Absolute Temperature (To be calculated)</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-f966ee93486528980c59eabac62f53fa"><strong>Advantages of CVGT:</strong></p>



<p>CVGTs offer several advantages in temperature measurement, especially in situations where high accuracy and precision are required. Here are some of the key advantages:</p>



<ul class="wp-block-list">
<li>High Accuracy: CVGTs provide highly accurate temperature measurements. They operate based on the ideal gas law, which establishes a direct relationship between the pressure of the gas and the absolute temperature. This relationship allows for precise temperature determination.</li>



<li><strong>Wide Temperature Range:</strong> CVGTs can measure temperatures across a wide range, from cryogenic temperatures to very high temperatures. This versatility makes them suitable for various applications in scientific research, metrology, and industrial processes.</li>



<li><strong>Direct Measurement:</strong> CVGTs directly measure the temperature of the gas by measuring its pressure at constant volume. This direct measurement approach eliminates the need for complex conversions or corrections, leading to more straightforward and accurate temperature readings.</li>



<li><strong>Insensitive to Gas Composition:</strong> CVGTs are relatively insensitive to the composition of the gas used inside the thermometer. As long as the gas behaves ideally, its composition does not significantly affect temperature measurements, enhancing the reliability and universality of CVGTs.</li>



<li><strong>Stable Calibration:</strong> Once calibrated, CVGTs maintain stable and consistent temperature-pressure relationships over time. This stability allows for long-term use without frequent recalibration, reducing maintenance requirements and ensuring reliable temperature measurements.</li>



<li><strong>High Precision:</strong> CVGTs can achieve high precision in temperature measurement, especially when using sensitive pressure measurement devices. This precision is essential in scientific research, quality control, and other applications where precise temperature control is critical.</li>



<li><strong>Minimal Thermal Lag:</strong> CVGTs typically exhibit minimal thermal lag, meaning they respond quickly to temperature changes. This rapid response time is advantageous in dynamic temperature measurement applications and experiments requiring real-time temperature monitoring.</li>



<li><strong>Suitability for Fundamental Studies:</strong> CVGTs are often used in fundamental scientific studies and metrological applications where precise temperature measurement is essential. They provide a basis for establishing temperature scales and calibrating other temperature measurement devices.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-33ab004d9e883c295ce341f7c9c057e4"><strong>Disadvantages of CVGT:</strong></p>



<p>While Constant Volume Gas Thermometers (CVGTs) offer many advantages, they also have some notable disadvantages and limitations:</p>



<ul class="wp-block-list">
<li><strong>Complexity:</strong> CVGTs can be relatively complex to construct and operate compared to simpler temperature measurement devices like liquid-in-glass thermometers or electronic thermometers. They require precise calibration and careful handling to ensure accurate temperature measurements.</li>



<li><strong>Specialized Equipment:</strong> The construction and calibration of CVGTs often require specialized equipment and expertise, making them less accessible and practical for everyday temperature measurement tasks.</li>



<li><strong>Pressure Sensitivity:</strong> CVGTs are highly sensitive to changes in pressure, which can affect the accuracy of temperature measurements. Variations in ambient pressure or pressure within the gas chamber can introduce errors in temperature readings.</li>



<li><strong>Limited Practicality:</strong> While CVGTs offer high accuracy and precision, they may not always be the most practical choice for temperature measurement in certain applications. They are typically used in laboratory settings or metrology applications where precise temperature control is required.</li>



<li><strong>Safety Concerns:</strong> Some gases used in CVGTs, such as helium or argon, can pose safety risks if mishandled or released into the environment. Additionally, the high pressures involved in CVGTs can present safety hazards if proper precautions are not taken.</li>



<li><strong>Inertia and Response Time:</strong> CVGTs may exhibit inertia and response time delays, especially when compared to more modern temperature measurement devices like electronic thermometers. This slower response time can be a limitation in applications requiring rapid temperature changes.</li>



<li><strong>Environmental Impact:</strong> The use of certain gases in CVGTs, particularly if they are released into the environment, can have environmental implications. Gases such as helium and argon are finite resources, and their extraction and use contribute to environmental impacts.</li>



<li><strong>Cost:</strong> CVGTs can be costly to manufacture, calibrate, and maintain, particularly when compared to other types of thermometers. The specialized equipment and expertise required for CVGTs can contribute to higher costs associated with their use.</li>
</ul>



<p>While CVGTs remain important tools for precise temperature measurement in certain applications, it&#8217;s essential to consider their limitations and weigh them against the specific requirements of the measurement task at hand. In many cases, alternative temperature measurement methods may offer a more practical and cost-effective solution.</p>



<p class="has-text-align-right"><strong><a href="#Back">Back to List of Sub-Topics</a></strong></p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-103ce6de0800e6413ed3bc7ea43c7f9f" id="CPGT"><strong>Constant Pressure Gas Thermometer:</strong></p>



<p>A Constant Pressure Gas Thermometer (CPGT), is a device used to measure temperature based on the principles of ideal gas behaviour. CPGT work on principle of Charle’s law. Charle&#8217;s Law states that when pressure of a gas is constant, the volume of the gas is directly proportional to its absolute temperature. As the temperature changes, the volume changes accordingly. Measuring the volume, temperature can be measured.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-d85ad7b5193b6feb6101c2f31129107b"><strong>Construction:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="766" height="408" src="https://thefactfactor.com/wp-content/uploads/2024/02/CPGT.jpg" alt="Measurement of Temperature" class="wp-image-21265" style="width:470px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/CPGT.jpg 766w, https://thefactfactor.com/wp-content/uploads/2024/02/CPGT-300x160.jpg 300w" sizes="auto, (max-width: 766px) 100vw, 766px" /></figure>
</div>


<p>The thermometric part consists of a silica bulb A (thermometer Bulb) connected to exactly similar bulb R through capillary tube ab. Bulb R is filled with mercury, this mercury can be drained out by operating draining knob at the bottom of bulb R.</p>



<p>The compensating part consists of another bulb B exactly similar bulbs A and R is connected to the system using capillary tube cd exactly similar to capillary tube ab (same length and same bore). The two capillary tubes ab and cd are always kept side by side to remain at the same temperature.</p>



<p>The thermometric part and the compensating part are connected to each other through manometer M.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-018ed626348b99fbc258444a264a3036"><strong>Working:</strong></p>



<p>All the three bulbs A, R, and B are kept in melting ice and ends of capillary tube are opened so that all parts of system are at atmospheric pressure. Bulb R is filled with mercury and the ends of capillary tubes are sealed and system is made air tight.</p>



<p>Bulb A is immersed in a bath of unknown temperature, while bulbs R and B are still maintained in melting ice. The pressure of air in bulb A increases thus there is difference in the level of mercury in the manometer M. The mercury in Bulb R is drained out by operating draining knob till the level in arms of manometer is equal again. The volume of drained mercury is measured.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-c05a869b5cbf6c0c7ef36ece03f8b984"><strong>Calculation</strong></p>



<p class="has-text-align-center">Θ = vT<sub>o</sub>/(V-v)</p>



<p class="has-text-align-center">Where Θ = Temperature to be measured</p>



<p class="has-text-align-center">T<sub>o</sub> = Temperature of air in bulbs B and R</p>



<p class="has-text-align-center">&nbsp;v = Volume of mercury taken out</p>



<p class="has-text-align-center">V = Volume of air in each capillary tube ab and cd</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-4625c1ba7080f7d9cc0d5d9f21a6656e"><strong>Advantages of CPGT:</strong></p>



<p>Constant Pressure Gas Thermometers (CPGTs) offer several advantages in temperature measurement, particularly in situations where high accuracy and stability are required. Here are some of the key advantages of CPGTs:</p>



<ul class="wp-block-list">
<li><strong>High Accuracy:</strong> CPGTs provide highly accurate temperature measurements. They operate based on the principle of constant pressure gas behaviour, which allows for precise determination of temperature based on the volume of the gas.</li>



<li><strong>Stability:</strong> CPGTs maintain stable temperature-volume relationships over time. Once calibrated, they exhibit consistent and predictable responses to changes in temperature, making them reliable instruments for temperature measurement.</li>



<li><strong>Direct Measurement:</strong> CPGTs directly measure temperature based on the volume of the gas at constant pressure. This direct measurement approach eliminates the need for complex conversions or corrections, leading to more straightforward and accurate temperature readings.</li>



<li><strong>Wide Temperature Range:</strong> CPGTs can measure temperatures across a wide range, from cryogenic temperatures to very high temperatures. This versatility makes them suitable for various applications in scientific research, metrology, and industrial processes.</li>



<li><strong>Insensitivity to Gas Composition:</strong> CPGTs are relatively insensitive to the composition of the gas used inside the thermometer. As long as the gas behaves ideally, its composition does not significantly affect temperature measurements, enhancing the reliability and universality of CPGTs.</li>



<li><strong>Minimal Thermal Lag:</strong> CPGTs typically exhibit minimal thermal lag, meaning they respond quickly to temperature changes. This rapid response time is advantageous in applications requiring real-time temperature monitoring and control.</li>



<li><strong>Practicality in Controlled Environments:</strong> CPGTs are well-suited for use in controlled laboratory environments where precise temperature control is required. They offer high accuracy and stability under controlled conditions, making them valuable tools for scientific research and experimentation.</li>



<li><strong>Long-Term Stability:</strong> Once calibrated, CPGTs maintain stable temperature-volume relationships over extended periods. This long-term stability allows for continuous and reliable temperature measurement without the need for frequent recalibration.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-3da03b438e14ab9d613599bd4bcc2917"><strong>Disadvantages of CPGT:</strong></p>



<p>Constant Pressure Gas Thermometers (CPGTs) have several disadvantages and limitations despite their accuracy and stability. Some of the main disadvantages include:</p>



<ul class="wp-block-list">
<li><strong>Complexity and Cost:</strong> CPGTs can be complex and expensive to construct, calibrate, and maintain. They require precise engineering and calibration procedures, as well as specialized equipment and expertise, which can increase their cost and complexity compared to other types of thermometers.</li>



<li><strong>Pressure Sensitivity:</strong> CPGTs are highly sensitive to changes in pressure, which can affect the accuracy of temperature measurements. Variations in ambient pressure or pressure within the gas chamber can introduce errors in temperature readings, requiring careful pressure control and compensation.</li>



<li><strong>Limited Practicality:</strong> While CPGTs offer high accuracy and stability, they may not always be the most practical choice for temperature measurement in certain applications. They are typically used in laboratory settings or metrology applications where precise temperature control is required, but they may not be suitable for field or industrial applications due to their complexity and cost.</li>



<li><strong>Susceptibility to Contamination:</strong> CPGTs are susceptible to contamination of the gas chamber, which can affect the accuracy and stability of temperature measurements. Contaminants such as moisture, gases, or particulate matter can introduce errors and require thorough cleaning and maintenance procedures.</li>



<li><strong>Limited Range of Gas:</strong> CPGTs are typically designed to operate with specific gases that behave ideally over a wide range of temperatures and pressures. The choice of gas can limit the temperature range and applicability of CPGTs in certain situations.</li>



<li><strong>Safety Concerns:</strong> The use of certain gases in CPGTs, such as helium or argon, can pose safety risks if mishandled or released into the environment. Additionally, the high pressures involved in CPGTs can present safety hazards if proper precautions are not taken. The vapours of mercury used is poisonous.</li>



<li><strong>Response Time:</strong> CPGTs may exhibit slower response times compared to other types of thermometers, especially in situations where rapid temperature changes occur. This slower response time can be a limitation in applications requiring real-time temperature monitoring and control.</li>
</ul>



<p>Despite these disadvantages, CPGTs remain valuable tools for precise temperature measurement in controlled laboratory environments and metrology applications where accuracy and stability are paramount. However, it&#8217;s essential to consider their limitations and weigh them against the specific requirements of the measurement task at hand. In many cases, alternative temperature measurement methods may offer more practical and cost-effective solutions.</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-cd43209619ef0abc7402ecd536bd3431" id="PRT"><strong>Platinum Resistance Thermometer:</strong></p>



<p>A Platinum Resistance Thermometer (PRT), also known as a platinum resistance temperature detector (RTD), is a type of thermometer that utilizes the change in electrical resistance of platinum wire with temperature to measure temperature accurately. The Platinum Resistance Thermometer works on the principle that the resistance of a platinum wire changes in a predictable manner as the temperature changes. Platinum is chosen for its linear resistance-temperature relationship, high stability, and repeatability over a wide temperature range.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-d85ad7b5193b6feb6101c2f31129107b"><strong>Construction:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="177" height="188" src="https://thefactfactor.com/wp-content/uploads/2024/02/PRT.jpg" alt="Measurement of Temperature" class="wp-image-21268" style="width:329px;height:auto"/></figure>
</div>


<p>The construction of a Platinum Resistance Thermometer (PRT) involves several key components and considerations to ensure accurate temperature measurement. The construction of a typical PRT is as follows:</p>



<ul class="wp-block-list">
<li><strong>Platinum Wire:</strong> The heart of a PRT is a fine platinum wire that exhibits a predictable change in electrical resistance with temperature variations. Platinum is chosen for its linear resistance-temperature relationship, stability, and repeatability over a wide temperature range.</li>



<li><strong>Support Structure:</strong> The platinum wire is typically wound around a support structure made of a non-conductive material, such as ceramic or glass. This support structure provides mechanical stability and protection for the platinum wire.</li>



<li><strong>Lead Wires:</strong> Electrical lead wires are attached to the platinum wire to allow for connection to a measurement circuit. The lead wires should be made of a conductive material that does not introduce significant resistance or interference.</li>



<li><strong>Encapsulation:</strong> The platinum wire and support structure are often encapsulated in a protective sheath or housing. This encapsulation helps to shield the PRT from external factors such as moisture, contaminants, and mechanical damage.</li>



<li><strong>Calibration Markers:</strong> PRTs are calibrated at specific reference temperatures to establish the relationship between resistance and temperature. Calibration markers or reference points may be added to the PRT to aid in calibration and temperature measurement.</li>



<li><strong>Terminal Connection:</strong> The terminal connection point where the lead wires are connected to the external measurement circuit is usually located on the housing or sheath of the PRT. This connection point should be securely sealed to prevent moisture ingress and ensure reliable electrical contact.</li>



<li><strong>Measurement Circuit (External):</strong> PRTs are typically used in a Wheatstone bridge circuit configuration. A known current is passed through the platinum wire, and the voltage drop across the wire is measured. The resistance of the wire, and thus the temperature, can be calculated using the voltage and the known current.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-018ed626348b99fbc258444a264a3036"><strong>Working:</strong></p>



<p>The resistance of the platinum wire changes with temperature following the Callendar-Van Dusen equation or the ITS-90 (International Temperature Scale of 1990) standard. This change is typically very linear over a wide range of temperatures, providing excellent accuracy and stability.</p>



<p>Once calibrated, the PRT can be used to measure temperatures by measuring the resistance of the platinum wire and using the calibration coefficients to calculate the corresponding temperature. The temperature measurement can be displayed directly on a digital thermometer or transmitted to a data acquisition system for further processing.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-6012e9a76172b553115988969512190f"><strong>Advantages of PTR:</strong></p>



<p>Platinum Resistance Thermometers (PRTs) offer several advantages compared to other types of temperature sensors. Here are some of the key advantages:</p>



<ul class="wp-block-list">
<li><strong>High Accuracy:</strong> PRTs provide highly accurate temperature measurements over a wide range of temperatures. Platinum has a linear resistance-temperature relationship, allowing for precise and reliable temperature readings.</li>



<li><strong>Stability:</strong> PRTs offer excellent long-term stability and repeatability. The resistance-temperature characteristics of platinum are well-defined and consistent, resulting in stable and reliable temperature measurements over time.</li>



<li><strong>Wide Temperature Range:</strong> PRTs can measure temperatures ranging from cryogenic temperatures to several hundred degrees Celsius or higher. They offer a wide temperature range of operation, making them suitable for various applications across different industries.</li>



<li><strong>Linear Response:</strong> The resistance of platinum in PRTs changes linearly with temperature variations, simplifying calibration and temperature compensation processes.</li>



<li><strong>Repeatability:</strong> PRTs provide repeatable temperature measurements, allowing for consistent results in laboratory experiments, industrial processes, and other applications.</li>



<li><strong>Low Drift:</strong> PRTs exhibit minimal drift over time, ensuring that temperature measurements remain accurate and reliable over extended periods.</li>



<li><strong>High Sensitivity:</strong> Platinum has a relatively high temperature coefficient of resistance (TCR), resulting in high sensitivity to temperature changes. This high sensitivity enables PRTs to detect small temperature variations accurately.</li>



<li><strong>Interchangeability:</strong> PRTs are highly interchangeable, meaning that different PRTs of the same type can be used interchangeably without significant calibration adjustments. This interchangeability simplifies instrument calibration and maintenance procedures.</li>



<li><strong>Low Self-Heating:</strong> PRTs generate minimal self-heating when subjected to an electrical current, reducing the impact of self-heating on temperature measurements.</li>



<li><strong>Compatibility with Standardization:</strong> PRTs are widely used as reference standards in laboratories and industries due to their high accuracy, stability, and compatibility with standardization efforts such as the International Temperature Scale of 1990 (ITS-90).</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-7c97df227fd2735927e6a606c4ff6d24"><strong>Disadvantages of PRT:</strong></p>



<p>While Platinum Resistance Thermometers (PRTs) offer many advantages, they also have some disadvantages and limitations. Here are some of the main drawbacks of PRTs:</p>



<ul class="wp-block-list">
<li><strong>Cost:</strong> PRTs can be relatively expensive compared to other types of temperature sensors. The cost of platinum, as well as the precision manufacturing required to produce accurate PRTs, contributes to their higher price.</li>



<li><strong>Fragility:</strong> PRTs can be fragile due to their fine platinum wire construction and delicate support structures. They may be more susceptible to mechanical damage, such as bending or breaking, compared to some other types of temperature sensors.</li>



<li><strong>Slow Response Time:</strong> PRTs generally have a slower response time compared to some other temperature sensors, such as thermocouples. The time required for the platinum wire to reach thermal equilibrium with the surrounding environment can result in slower temperature response times.</li>



<li><strong>Limited Temperature Range:</strong> While PRTs can measure temperatures over a wide range, they may not be suitable for extreme temperature conditions, such as those encountered in very high-temperature industrial processes or in cryogenic applications. Extreme temperatures can affect the performance and accuracy of PRTs.</li>



<li><strong>Susceptibility to Contamination:</strong> PRTs can be sensitive to contamination of the platinum wire, which can affect their accuracy and stability. Contaminants such as moisture, gases, or particulate matter can introduce errors and require thorough cleaning and maintenance procedures.</li>



<li><strong>Electrical Excitation Required:</strong> PRTs require an external electrical excitation source to measure temperature accurately. This requirement for electrical excitation can introduce additional complexity and potential sources of error in temperature measurement systems.</li>



<li><strong>Limited Flexibility:</strong> The physical construction and design of PRTs may limit their flexibility in certain applications. They may not be as adaptable to harsh environments or space-constrained installations compared to some other types of temperature sensors.</li>



<li><strong>Calibration Requirements:</strong> PRTs require periodic calibration to maintain accurate temperature measurements over time. Calibration procedures can be time-consuming and may require specialized equipment and expertise.</li>
</ul>



<p>Despite these disadvantages, PRTs remain widely used in many industries and applications where high accuracy, stability, and repeatability are essential for precise temperature measurement. It&#8217;s important to consider the specific requirements of each application when selecting a temperature sensor and to weigh the advantages and disadvantages of different sensor types accordingly.</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-e44984fc1607b808a1b07ebce6a466da" id="Thermocouple"><strong>Thermocouple:</strong></p>



<p>A thermocouple is a type of temperature sensor that consists of two different metal wires joined together at one end, called the junction. When there is a temperature gradient along the length of the thermocouple, it generates a voltage proportional to the temperature difference between the two ends. This phenomenon is known as the Seebeck effect.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="337" height="187" src="https://thefactfactor.com/wp-content/uploads/2024/02/Thermocouple.jpg" alt="" class="wp-image-21269" style="width:431px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/Thermocouple.jpg 337w, https://thefactfactor.com/wp-content/uploads/2024/02/Thermocouple-300x166.jpg 300w" sizes="auto, (max-width: 337px) 100vw, 337px" /></figure>
</div>


<p class="has-accent-color has-text-color has-link-color wp-elements-d85ad7b5193b6feb6101c2f31129107b"><strong>Construction:</strong></p>



<p>A thermocouple is a temperature sensor that operates based on the Seebeck effect, which describes the generation of a voltage when two dissimilar metals are joined together at a junction and there is a temperature gradient along the length of the metals.</p>



<ul class="wp-block-list">
<li><strong>Metal Wires:</strong> Thermocouples consist of two different metal wires joined together at one end to form the sensing junction. The metals used in the wires determine the thermocouple type and its temperature range. Common metal combinations include chromel-alumel (Type K), iron-constantan (Type J), and copper-constantan (Type T), among others.</li>



<li><strong>Insulation:</strong> The metal wires are typically insulated from each other along their length to prevent electrical shorting. The insulation material is chosen to withstand the temperature and environmental conditions of the application.</li>



<li><strong>Protection Sheath:</strong> In many applications, the thermocouple wires are housed within a protective sheath made of stainless steel, ceramic, or other suitable materials. The sheath shields the thermocouple from mechanical damage, corrosion, and environmental factors.</li>



<li><strong>Connection Head:</strong> At the end opposite the sensing junction, the thermocouple wires are connected to a termination point, usually within a connection head. The connection head provides a secure enclosure for the wiring connections and allows for easy access for calibration and maintenance.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-018ed626348b99fbc258444a264a3036"><strong>Working:</strong></p>



<ul class="wp-block-list">
<li><strong>Seebeck Effect:</strong> When there is a temperature gradient along the length of the two dissimilar metal wires forming the sensing junction, a voltage is generated. This voltage is proportional to the temperature difference between the sensing junction and the reference (cold) junction, usually located at or near the termination point.</li>



<li><strong>Measurement Circuit:</strong> The voltage generated by the thermocouple is measured using a voltmeter or a temperature measurement device. The voltage is typically very small, so the measurement circuit needs to be sensitive to detect it accurately. Generally wheatstone’s bridge is used.</li>



<li><strong>Cold Junction Compensation:</strong> Accurate temperature measurement with a thermocouple requires compensation for the temperature of the reference (cold) junction. Specialized circuits or techniques are used to measure the temperature at the reference junction and compensate for its effect on the thermocouple output.</li>



<li><strong>Temperature Calculation:</strong> Once the voltage generated by the thermocouple is measured and compensated for the reference junction temperature, it is converted into a temperature reading using calibration tables or equations specific to the thermocouple type and temperature range.</li>
</ul>



<p>Overall, thermocouples are widely used temperature sensors in various industries and applications due to their wide temperature range, fast response time, durability, and simplicity of construction.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-392a6dd77df12bd9a7a82f9c931b6d3b"><strong>Types of Thermocouples:</strong></p>



<figure class="wp-block-table aligncenter is-style-stripes"><table><tbody><tr><td class="has-text-align-center" data-align="center">Type of Thermocouple</td><td class="has-text-align-center" data-align="center">Wires Used</td><td class="has-text-align-center" data-align="center">Temperature Range in <sup>o</sup>C</td></tr><tr><td class="has-text-align-center" data-align="center">B</td><td class="has-text-align-center" data-align="center">Platinum (6% Rhodium) and Platinum (30% Rhodium)</td><td class="has-text-align-center" data-align="center">1370 to 1700</td></tr><tr><td class="has-text-align-center" data-align="center">E</td><td class="has-text-align-center" data-align="center">Chromel and Constantan</td><td class="has-text-align-center" data-align="center">0 to 870</td></tr><tr><td class="has-text-align-center" data-align="center">J</td><td class="has-text-align-center" data-align="center">Iron and Constantan</td><td class="has-text-align-center" data-align="center">0 to 760</td></tr><tr><td class="has-text-align-center" data-align="center">K</td><td class="has-text-align-center" data-align="center">Chromel and Alumel</td><td class="has-text-align-center" data-align="center">95 to 1260</td></tr><tr><td class="has-text-align-center" data-align="center">N</td><td class="has-text-align-center" data-align="center">Nicrosil and Nisil</td><td class="has-text-align-center" data-align="center">650 to 1260</td></tr><tr><td class="has-text-align-center" data-align="center">R</td><td class="has-text-align-center" data-align="center">Platinum (13% Rhodium) and Platinum</td><td class="has-text-align-center" data-align="center">870 to 1450</td></tr><tr><td class="has-text-align-center" data-align="center">S</td><td class="has-text-align-center" data-align="center">Platinum (10% Rhodium) and Platinum</td><td class="has-text-align-center" data-align="center">980 to 1450</td></tr><tr><td class="has-text-align-center" data-align="center">T</td><td class="has-text-align-center" data-align="center">Copper and Constantan</td><td class="has-text-align-center" data-align="center">-200 to 370</td></tr></tbody></table></figure>



<p class="has-accent-color has-text-color has-link-color wp-elements-dbe843419d0d1d733fc2408d32bb42da"><strong>Advantages of Thermocouple:</strong></p>



<p>Thermocouples offer several advantages that make them widely used for temperature measurement in various industries and applications.</p>



<ul class="wp-block-list">
<li><strong>Wide Temperature Range:</strong> Thermocouples can measure temperatures ranging from cryogenic temperatures to extremely high temperatures (up to around 2300°C or 4172°F), depending on the type of thermocouple and the materials used. This wide temperature range makes thermocouples suitable for a broad range of applications across different industries.</li>



<li><strong>Fast Response Time:</strong> Thermocouples have a fast response time, allowing for rapid temperature measurement and monitoring. This makes them well-suited for applications where quick temperature changes need to be detected or controlled.</li>



<li><strong>Robustness and Durability:</strong> Thermocouples are relatively robust and durable temperature sensors. They can withstand harsh environments, mechanical vibrations, and high electromagnetic interference, making them suitable for use in industrial environments and challenging conditions.</li>



<li><strong>Simple Construction:</strong> Thermocouples consist of only two wires joined together at one end, making them simple in construction and easy to install. Their simplicity makes them cost-effective and versatile for various applications.</li>



<li><strong>Wide Variety of Types and Materials:</strong> Thermocouples are available in a wide variety of types and materials, each offering different temperature ranges, accuracies, and characteristics. Common types include Type K, Type J, Type T, and Type E thermocouples, each suitable for specific temperature ranges and environments.</li>



<li><strong>Compatibility with Many Environments:</strong> Thermocouples are compatible with many different environments and can be used in various gases, liquids, and solids. They are widely used in industrial processes, HVAC systems, automotive applications, and scientific research.</li>



<li><strong>No External Power Required:</strong> Thermocouples generate their own voltage signal when subjected to a temperature gradient, eliminating the need for external power sources. This makes them suitable for remote or portable applications where power may be limited or unavailable.</li>



<li><strong>Interchangeability:</strong> Thermocouples are highly interchangeable, meaning that different thermocouples of the same type can be used interchangeably without significant calibration adjustments. This interchangeability simplifies instrument calibration and maintenance procedures.</li>



<li><strong>Cost-Effective:</strong> Thermocouples are generally more cost-effective compared to some other types of temperature sensors, such as resistance temperature detectors (RTDs) and infrared thermometers. Their simple construction, durability, and versatility contribute to their cost-effectiveness.</li>
</ul>



<p>Overall, thermocouples offer many advantages, including wide temperature range, fast response time, robustness, simplicity, compatibility with various environments, and cost-effectiveness, making them one of the most commonly used temperature sensors in numerous industrial, commercial, and scientific applications.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-c2d230f3be4ca579a09249910d4fd09b"><strong>Disadvantages of Thermocouple:</strong></p>



<p>While thermocouples offer many advantages, they also have some disadvantages and limitations. Here are some of the key disadvantages of thermocouples:</p>



<ul class="wp-block-list">
<li><strong>Non-Linear Output:</strong> The voltage output of a thermocouple is non-linear with temperature, especially over wide temperature ranges. This non-linearity can introduce errors in temperature measurements, requiring compensation and correction techniques to achieve accurate readings.</li>



<li><strong>Cold Junction Compensation:</strong> Accurate temperature measurement with thermocouples requires compensation for the temperature of the reference junction (cold junction). Specialized equipment or compensation techniques are used to account for temperature variations at the cold junction, adding complexity to temperature measurement systems.</li>



<li><strong>Limited Accuracy:</strong> While thermocouples offer good accuracy for many industrial applications, they may not be as accurate as some other temperature sensors, such as resistance temperature detectors (RTDs), especially at lower temperatures. The accuracy of thermocouples can be affected by factors such as wire quality, calibration, and environmental conditions.</li>



<li><strong>Sensitivity to Electrical Noise:</strong> Thermocouples are susceptible to electrical noise and interference, which can affect the accuracy and stability of temperature measurements. Proper shielding and grounding techniques are required to minimize the impact of electrical noise on thermocouple signals.</li>



<li><strong>Limited Resolution:</strong> Thermocouples have limited resolution compared to some other temperature sensors, such as RTDs and thermistors. The resolution of a thermocouple is determined by the sensitivity of the thermocouple and the accuracy of the measurement system.</li>



<li><strong>Limited Temperature Range for Some Types:</strong> While thermocouples offer a wide temperature range overall, some specific types of thermocouples have limited temperature ranges. For example, Type T thermocouples have a relatively narrow temperature range compared to other types, making them unsuitable for high-temperature applications.</li>



<li><strong>Susceptibility to Corrosion and Contamination:</strong> Certain environments can cause corrosion or contamination of thermocouple materials, affecting their accuracy and reliability over time. Protective sheaths or coatings may be required to protect thermocouples in corrosive or contaminating environments.</li>



<li><strong>Heterogeneity and Stability Issues:</strong> Thermocouples made from different materials may exhibit heterogeneity in their characteristics, leading to variations in temperature measurements. Additionally, thermocouples may suffer from stability issues over time, resulting in drift and changes in calibration.</li>
</ul>



<p>Despite these disadvantages, thermocouples remain widely used for temperature measurement in various industries and applications due to their versatility, ruggedness, wide temperature range, and suitability for harsh environments. It&#8217;s important to consider the specific requirements of each application and weigh the advantages and disadvantages of different temperature sensors accordingly.</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-81eb002124249e9234c97a1e724b4b6a" id="Pyrometer"><strong>Pyrometers:</strong></p>



<p>A pyrometer is a device used to measure the temperature of objects or surfaces without making physical contact. Pyrometers work based on the principle of measuring the thermal radiation emitted by an object, which is related to its temperature according to the laws of blackbody radiation. One of the primary advantages of pyrometers is that they can measure the temperature of objects without physical contact. This is particularly useful for measuring the temperature of objects that are moving, inaccessible, or hazardous to touch. Pyrometers are used in a wide range of industrial, scientific, and commercial applications, including metal processing, glass manufacturing, ceramics, automotive, aerospace, and research laboratories. They are particularly useful for monitoring and controlling temperatures in high-temperature processes and environments</p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="310" height="162" src="https://thefactfactor.com/wp-content/uploads/2024/02/Pyrometer.jpg" alt="" class="wp-image-21273" style="width:460px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/Pyrometer.jpg 310w, https://thefactfactor.com/wp-content/uploads/2024/02/Pyrometer-300x157.jpg 300w" sizes="auto, (max-width: 310px) 100vw, 310px" /></figure>
</div>


<ul class="wp-block-list">
<li><strong>Principle of Operation:</strong> Pyrometers measure the intensity of thermal radiation emitted by an object, usually within the infrared spectrum. The intensity of thermal radiation emitted by an object is directly related to its temperature, according to the Stefan-Boltzmann law and Planck&#8217;s law of blackbody radiation.</li>



<li><strong>Optical System:</strong> Pyrometers typically employ an optical system to focus the thermal radiation emitted by the object onto a detector. The optical system may include lenses, mirrors, or fibre optics to collect and direct the radiation to the detector.</li>



<li><strong>Detector:</strong> The detector in a pyrometer converts the incoming thermal radiation into an electrical signal. Different types of detectors may be used, including thermopiles, bolometers, and photodiodes, depending on the specific application and temperature range.</li>



<li><strong>Accuracy and Calibration:</strong> The accuracy of temperature measurements with pyrometers depends on various factors, including the calibration of the instrument, the stability of the detector, and the emissivity of the object being measured. Calibration standards and procedures are used to ensure accurate temperature measurements.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-550ee205914bc5e058edda4dc23e529a"><strong>Advantages of Pyrometer:</strong></p>



<p>Pyrometers offer several advantages in temperature measurement, particularly in situations where non-contact measurement and high-temperature sensing are required. Here are some key advantages of pyrometers:</p>



<ul class="wp-block-list">
<li><strong>Non-contact Measurement:</strong> Pyrometers enable temperature measurement without physical contact with the object being measured. This feature is especially valuable for measuring the temperature of moving objects, fragile materials, or objects at high temperatures where contact measurement may be impractical or impossible.</li>



<li><strong>Wide Temperature Range:</strong> Pyrometers can measure temperatures ranging from low (e.g., room temperature) to extremely high temperatures (e.g., thousands of degrees Celsius). This wide temperature range makes them suitable for various industrial, scientific, and commercial applications, including metal processing, glass manufacturing, ceramics, and automotive.</li>



<li><strong>Fast Response Time:</strong> Pyrometers offer fast response times, allowing for rapid temperature measurements. This makes them ideal for applications where temperature changes need to be monitored or controlled quickly, such as industrial processes, combustion monitoring, and materials processing.</li>



<li><strong>Remote Sensing:</strong> Pyrometers can measure temperature from a distance, making them suitable for measuring objects that are difficult to access or located in hazardous environments. They are commonly used in industrial furnaces, kilns, and reactors where direct contact measurement is not feasible.</li>



<li><strong>Versatility:</strong> Pyrometers are versatile instruments that can be used in various environments and applications. They are available in different configurations, including portable handheld units, fixed-mount units, and online monitoring systems, to meet specific measurement requirements.</li>



<li><strong>Accuracy and Precision:</strong> Modern pyrometers offer high levels of accuracy and precision in temperature measurement. They employ advanced optics, detectors, and signal processing techniques to ensure accurate and reliable temperature readings across a wide range of temperatures and operating conditions.</li>



<li><strong>Durability and Reliability:</strong> Pyrometers are designed to withstand harsh industrial environments, including high temperatures, dust, humidity, and vibration. They are built with rugged enclosures, durable optics, and robust electronics to ensure long-term reliability and performance in demanding applications.</li>



<li><strong>Real-time Monitoring and Control:</strong> Pyrometers can be integrated into automated systems for real-time temperature monitoring and control. They provide valuable data for process optimization, quality control, and predictive maintenance in manufacturing and industrial processes.</li>



<li><strong>Safety:</strong> Pyrometers contribute to improved safety in industrial environments by enabling temperature measurement from a safe distance, reducing the risk of operator exposure to hazardous conditions or hot surfaces.</li>
</ul>



<p>Thus, pyrometers offer numerous advantages in temperature measurement, including non-contact measurement, wide temperature range, fast response time, versatility, accuracy, durability, and safety. These features make them indispensable tools in a wide range of industries and applications where precise and reliable temperature measurement is essential.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-15bad6bc03d560e5f388ccbe4b6d17e0"><strong>Disadvantages of Pyrometers:</strong></p>



<p>While pyrometers offer many advantages in temperature measurement, they also have some limitations and disadvantages.</p>



<ul class="wp-block-list">
<li><strong>Emissivity Variations:</strong> Pyrometers rely on the assumption of uniform emissivity, which refers to the ability of a surface to emit thermal radiation. However, the emissivity of real-world surfaces can vary based on factors such as surface finish, material composition, and surface condition. Variations in emissivity can lead to measurement errors and inaccuracies.</li>



<li><strong>Limited Accuracy at Low Temperatures:</strong> Pyrometers may have limited accuracy at low temperatures, especially below 100°C (212°F). At lower temperatures, the emitted thermal radiation is relatively weak, making it challenging to distinguish the signal from background noise accurately.</li>



<li><strong>Distance-to-Spot Ratio:</strong> Pyrometers have a specified distance-to-spot ratio, which determines the size of the measurement area at a given distance. In applications where precise targeting is required, limitations in the distance-to-spot ratio can affect the accuracy of temperature measurements.</li>



<li><strong>Reflection and Interference:</strong> Reflections from nearby surfaces and interference from ambient light sources can affect the accuracy of pyrometer measurements. Reflected radiation can lead to errors in temperature readings, particularly in environments with shiny or reflective surfaces.</li>



<li><strong>Cost:</strong> High-quality pyrometers with advanced features and capabilities can be relatively expensive compared to other temperature measurement devices, such as thermocouples and thermistors. The cost of calibration, maintenance, and training may also contribute to the overall expense of implementing pyrometry systems.</li>



<li><strong>Calibration and Maintenance:</strong> Pyrometers require regular calibration to ensure accurate and reliable temperature measurements. Calibration procedures can be complex and time-consuming, requiring specialized equipment and trained personnel. Additionally, pyrometers may require periodic maintenance to ensure proper functionality and performance.</li>



<li><strong>Limited Temperature Range for Some Types:</strong> While pyrometers can measure a wide range of temperatures, some specific types may have limited temperature ranges. Certain pyrometer technologies may not be suitable for extremely high-temperature applications or very low-temperature measurements.</li>



<li><strong>Response Time:</strong> While pyrometers generally offer fast response times, the response time can vary depending on the type of pyrometer, measurement distance, and environmental conditions. In some applications where rapid temperature changes occur, limitations in response time may impact the accuracy of temperature measurements.</li>



<li><strong>Complexity of Operation:</strong> Some types of pyrometers, particularly those with advanced features and capabilities, may be complex to operate and require specialized training and expertise. Users need to understand the principles of operation, calibration procedures, and potential sources of error to obtain accurate temperature measurements.</li>
</ul>



<p>Despite these disadvantages, pyrometers remain valuable tools for temperature measurement in various industries and applications where non-contact measurement, high-temperature sensing, and remote monitoring are required. It&#8217;s essential to consider the specific requirements of each application and weigh the advantages and disadvantages of pyrometers accordingly.</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-4415efba1f604045bd242fa87eb2ae14" id="Thermistor"><strong>Thermistors:</strong></p>



<p>A thermistor thermometer is a type of thermometer that utilizes a thermistor as its temperature sensing element. Thermistors are temperature-sensitive resistors made from semiconductor materials whose electrical resistance changes significantly with temperature variations. Thermistor thermometers find applications in various industries and applications, including HVAC (heating, ventilation, and air conditioning) systems, automotive, medical devices, food processing, and environmental monitoring. They are particularly useful for applications requiring accurate and reliable temperature measurements over a relatively narrow temperature range.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-d85ad7b5193b6feb6101c2f31129107b"><strong>Construction:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="223" height="221" src="https://thefactfactor.com/wp-content/uploads/2024/02/Thermistor.jpg" alt="" class="wp-image-21274" style="width:371px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/Thermistor.jpg 223w, https://thefactfactor.com/wp-content/uploads/2024/02/Thermistor-150x150.jpg 150w" sizes="auto, (max-width: 223px) 100vw, 223px" /></figure>
</div>


<p>The construction of a thermistor thermometer involves the integration of a thermistor, which is a temperature-sensitive resistor made from semiconductor materials, into a measurement circuit.</p>



<ul class="wp-block-list">
<li><strong>Principle of Operation:</strong> Thermistors operate based on the principle of the change in electrical resistance with temperature variations. They exhibit a negative temperature coefficient (NTC) or positive temperature coefficient (PTC) depending on the type of thermistor. NTC thermistors have decreasing resistance with increasing temperature, while PTC thermistors have increasing resistance with increasing temperature.</li>



<li><strong>Thermistor:</strong> The core component of a thermistor thermometer is the thermistor itself. Thermistors are typically made from semiconductor materials such as metal oxides (e.g., nickel, manganese, cobalt), which exhibit a predictable change in resistance with temperature variations. The choice of thermistor type (e.g., NTC or PTC) depends on the specific application requirements.</li>



<li><strong>Housing:</strong> The thermistor is housed within a protective casing or probe to shield it from environmental factors and physical damage. The housing material is selected to withstand the operating conditions of the application, including temperature, humidity, and chemical exposure.</li>



<li><strong>Wiring:</strong> The thermistor is connected to the measurement circuit using electrical wiring. The wiring should be of sufficient quality and gauge to minimize resistance and signal loss.</li>



<li><strong>Measurement Circuit:</strong> The measurement circuit comprises components such as resistors, capacitors, operational amplifiers, and possibly microcontrollers or integrated circuits (ICs) for signal processing and data display. The circuit is designed to measure the resistance of the thermistor accurately and convert it into a temperature reading.</li>



<li><strong>Voltage Source:</strong> A voltage source is typically provided to supply power to the measurement circuit and thermistor. The voltage source may be a battery, power supply, or integrated power management circuit, depending on the application requirements.</li>



<li><strong>Calibration Components:</strong> Calibration components, such as precision resistors and trim pots, may be included in the measurement circuit to calibrate the thermometer and ensure accurate temperature readings. Calibration is essential to account for variations in thermistor characteristics and circuit performance.</li>



<li><strong>Display and Output:</strong> The temperature reading obtained from the measurement circuit is displayed to the user through a digital display (e.g., LCD or LED) or analog gauge. Some thermistor thermometers may also include output options such as analog voltage output, serial communication (e.g., UART), or digital protocols (e.g., I2C, SPI) for interfacing with external devices or data logging systems.</li>



<li><strong>Enclosure:</strong> The entire thermometer assembly, including the measurement circuit, display, and wiring, may be enclosed within a protective housing or casing. The enclosure provides physical protection, electrical insulation, and mounting options for the thermometer.</li>



<li><strong>User Interface:</strong> Depending on the thermometer&#8217;s design and intended use, it may include user interface elements such as buttons, switches, or touchscreens for setting parameters, adjusting settings, or accessing additional features.</li>
</ul>



<p>The construction of a thermistor thermometer can vary depending on factors such as the thermometer&#8217;s intended application, accuracy requirements, environmental conditions, and cost considerations. However, the basic principles outlined above form the foundation of most thermistor thermometer designs.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-c0c7e4de478d97b5456be894a9b6818d"><strong>Advantages of Thermistor Thermometers:</strong></p>



<p>Thermistor thermometers offer several advantages in temperature measurement, particularly in applications where high sensitivity, accuracy, and precision are required. Here are some key advantages of thermistor thermometers:</p>



<ul class="wp-block-list">
<li><strong>High Sensitivity:</strong> Thermistors exhibit high sensitivity to temperature changes, making them capable of detecting even small variations in temperature. This high sensitivity allows for precise temperature measurements in a wide range of applications.</li>



<li><strong>Wide Temperature Range:</strong> Thermistor thermometers can measure temperatures across a broad range, from cryogenic temperatures to elevated temperatures. Different types of thermistors, such as negative temperature coefficient (NTC) and positive temperature coefficient (PTC) thermistors, offer temperature measurement capabilities over different ranges, providing versatility in various applications.</li>



<li><strong>Linearity:</strong> Thermistors often exhibit a linear relationship between resistance and temperature over a specific temperature range, simplifying calibration and temperature measurement calculations. This linearity enhances accuracy and precision in temperature measurement compared to some other temperature sensors.</li>



<li><strong>Fast Response Time:</strong> Thermistors have a fast response time, allowing for rapid temperature measurement and monitoring. This feature is particularly useful in applications where quick temperature changes need to be detected or controlled.</li>



<li><strong>Small Size:</strong> Thermistors are compact and lightweight, making them suitable for integration into small, space-constrained devices and systems. Their small size allows for easy installation and integration into various electronic devices and equipment.</li>



<li><strong>Low Cost:</strong> Thermistors are relatively inexpensive compared to some other temperature sensors, such as resistance temperature detectors (RTDs) and thermocouples. Their low cost makes them an economical choice for temperature measurement in many applications.</li>



<li><strong>Stability and Long-Term Reliability:</strong> Thermistors exhibit stable and consistent performance over time, with minimal drift in resistance and temperature measurement accuracy. This stability ensures long-term reliability and repeatability in temperature measurements, reducing the need for frequent calibration and maintenance.</li>



<li><strong>Low Power Consumption:</strong> Thermistors have low power consumption, making them energy-efficient and suitable for battery-powered applications and portable devices. Their low power requirements contribute to extended battery life and reduced operating costs.</li>



<li><strong>Ease of Interfacing:</strong> Thermistors can be easily interfaced with electronic circuits and microcontrollers for temperature measurement and control. Their simple electrical characteristics and predictable behaviour simplify circuit design and integration into electronic systems.</li>



<li><strong>Compatibility with Semiconductor Processes</strong>: Thermistors are semiconductor devices and are compatible with semiconductor manufacturing processes, allowing for cost-effective production and customization for specific application requirements.</li>
</ul>



<p>Thus, thermistor thermometers offer several advantages, including high sensitivity, wide temperature range, linearity, fast response time, small size, low cost, stability, low power consumption, ease of interfacing, and compatibility with semiconductor processes. These features make them valuable temperature sensors in various industrial, commercial, and consumer applications where accurate and reliable temperature measurement is essential.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-ef73b3adb0531bc36ad4e2b92fcc3926"><strong>Disadvantages of Thermistor Thermometer:</strong></p>



<p>Thermistors, while offering many advantages in temperature measurement, also have some limitations and disadvantages. Here are some of the key disadvantages of thermistors:</p>



<ul class="wp-block-list">
<li><strong>Non-linearity:</strong> One significant drawback of thermistors is their non-linear resistance-temperature relationship. Unlike some other temperature sensors like resistance temperature detectors (RTDs), the resistance of a thermistor does not change linearly with temperature. This non-linearity can complicate calibration and temperature measurement calculations, requiring curve fitting or lookup tables for accurate temperature readings.</li>



<li><strong>Limited Temperature Range:</strong> Thermistors have a limited temperature range compared to some other temperature sensors, such as thermocouples. While they are suitable for many applications, thermistors may not be appropriate for extremely high-temperature measurements or cryogenic temperatures.</li>



<li><strong>Self-Heating:</strong> Thermistors exhibit self-heating when current passes through them to measure temperature. This self-heating effect can lead to inaccuracies in temperature measurements, especially at low currents or when high precision is required. Careful consideration and compensation techniques may be necessary to mitigate the impact of self-heating on temperature readings.</li>



<li><strong>Stability and Drift:</strong> Thermistors may exhibit stability issues and long-term drift in resistance over time. Factors such as aging, environmental conditions (e.g., temperature, humidity), and mechanical stress can contribute to changes in thermistor characteristics and performance. Regular calibration and maintenance may be required to ensure consistent and reliable temperature measurements.</li>



<li><strong>Limited Interchangeability:</strong> Thermistors are not as interchangeable as some other temperature sensors, such as thermocouples and RTDs. Each thermistor has unique characteristics, including resistance-temperature curves and tolerances, which can vary between different thermistors even of the same type and model. This lack of interchangeability can complicate replacement and calibration processes.</li>



<li><strong>Sensitivity to Overvoltage and Transients:</strong> Thermistors are sensitive to overvoltage and transient voltage spikes, which can damage or degrade their performance. Proper voltage protection measures, such as transient voltage suppressors (TVS diodes) and voltage regulators, may be necessary to safeguard thermistors from electrical overstress.</li>



<li><strong>Limited Availability of Standardized Models:</strong> Unlike some other temperature sensors, such as thermocouples and RTDs, thermistors may have limited availability of standardized models with well-defined specifications and calibration standards. This can make it challenging to select and integrate thermistors into temperature measurement systems, especially in critical or regulated applications.</li>
</ul>



<p>Despite these disadvantages, thermistors remain widely used for temperature measurement in various industrial, commercial, and consumer applications due to their high sensitivity, low cost, compact size, and ease of integration. It&#8217;s important to consider the specific requirements and limitations of thermistors when selecting temperature sensors for different applications.</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-2a638c752a92d70d019a8f1cd491c1b7" id="LCT"><strong>Liquid Crystal Thermometer:</strong></p>



<p>Liquid crystal thermometers, also known as liquid crystal temperature strips or liquid crystal thermochromic devices, are temperature-sensitive devices that use liquid crystal materials to display temperature information. Here&#8217;s an overview of liquid crystal thermometers:</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-d85ad7b5193b6feb6101c2f31129107b"><strong>Construction:</strong></p>



<ul class="wp-block-list">
<li><strong>Liquid Crystal Material:</strong> The core component of a liquid crystal thermometer is the liquid crystal material itself. Liquid crystals are organic compounds that exhibit changes in color or opacity in response to changes in temperature. These changes occur due to alterations in the molecular arrangement of the liquid crystal material as temperature changes.</li>



<li><strong>Substrate:</strong> The liquid crystal material is typically encapsulated within a thin, transparent plastic or polyester substrate. This substrate serves as a protective layer and provides support for the liquid crystal material.</li>



<li><strong>Adhesive Backing:</strong> Many liquid crystal thermometers feature an adhesive backing on one side of the substrate, allowing them to be affixed to various surfaces, such as containers, windows, or equipment.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-ca93132374bc16d8320d1978756ef624"><strong>Working Principle:</strong></p>



<ul class="wp-block-list">
<li><strong>Temperature Sensitivity:</strong> Liquid crystal thermometers utilize the temperature sensitivity of liquid crystal materials. As the temperature changes, the liquid crystal molecules reorient themselves, causing changes in the material&#8217;s optical properties, such as color or opacity.</li>



<li><strong>Colour Change:</strong> Liquid crystal thermometers typically feature a color scale printed on the substrate adjacent to the liquid crystal material. As the temperature changes, the liquid crystal material changes colour according to the temperature scale, providing a visual indication of the current temperature.</li>



<li><strong>Visual Observation:</strong> Users can visually observe the colour changes in the liquid crystal material to determine the approximate temperature. The colours may indicate temperature ranges or specific temperature values, depending on the design of the thermometer.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-54d4a27536316c91fa01326b54f3a19b"><strong>Advantages of Liquid Crystal Thermometers:</strong></p>



<ul class="wp-block-list">
<li><strong>Non-Invasive Measurement:</strong> Liquid crystal thermometers offer non-invasive temperature measurement, requiring no direct contact with the object or surface being measured. This feature is particularly useful for applications where contact measurement methods are impractical or undesirable.</li>



<li><strong>Quick Response Time:</strong> Liquid crystal thermometers have a fast response time, allowing users to quickly assess temperature changes. The colour changes in the liquid crystal material occur almost instantly in response to temperature variations.</li>



<li><strong>Compact and Portable:</strong> Liquid crystal thermometers are lightweight, compact, and portable, making them easy to transport and use in various settings. They are particularly convenient for field measurements or mobile applications.</li>



<li><strong>Low Cost:</strong> Liquid crystal thermometers are generally inexpensive compared to some other temperature measurement devices, such as digital thermometers or infrared thermometers. They offer a cost-effective solution for temperature monitoring and measurement.</li>



<li><strong>Visual Readout:</strong> Liquid crystal thermometers provide a visual readout of temperature information, eliminating the need for power sources or electronic displays. This simplicity makes them easy to use and understand, even for individuals without technical expertise.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-873e8470ebf7b3e96691d50eccfdd66e"><strong>Disadvantages of Liquid Crystal Thermometers:</strong></p>



<ul class="wp-block-list">
<li><strong>Limited Precision:</strong> Liquid crystal thermometers may provide only approximate temperature measurements and are typically less precise than digital thermometers or thermocouples.</li>



<li><strong>Temperature Range:</strong> The temperature range of liquid crystal thermometers may be limited compared to other temperature measurement devices. They may not be suitable for extreme temperature conditions or high-precision applications.</li>



<li><strong>Subject to Environmental Factors:</strong> Liquid crystal thermometers can be affected by environmental factors such as humidity, sunlight, and ambient temperature variations, which may impact their accuracy and performance.</li>
</ul>



<p class="has-accent-color has-text-color has-link-color wp-elements-332c9d6827515f17412c819d5d983d17"><strong>Applications:</strong></p>



<p>Liquid crystal thermometers are commonly used in various applications, including home temperature monitoring, medical diagnostics, aquariums, and educational settings. They provide a simple and convenient method for assessing temperature changes in a wide range of environments</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-62f4f9702b0a7dadec7a0bf88ffb9e25"><strong>Conclusion:</strong></p>



<p>Temperature is measured using various types of temperature sensors and instruments, each with its own principles of operation, advantages, and limitations. Each temperature measurement method has its own advantages, limitations, and application-specific considerations. The choice of temperature sensor or instrument depends on factors such as the temperature range, accuracy requirements, response time, environmental conditions, and specific application needs.</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/temperature-measurement/21256/">Measurement of Temperature</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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		<title>Thermodynamic or Temperature Scales</title>
		<link>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/temperature-scales/21242/</link>
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		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Fri, 02 Feb 2024 12:23:27 +0000</pubDate>
				<category><![CDATA[Thermodynamics]]></category>
		<category><![CDATA[Absolute Scale]]></category>
		<category><![CDATA[Celsius scale]]></category>
		<category><![CDATA[Conversion of Temperature]]></category>
		<category><![CDATA[Fahrenheit scale]]></category>
		<category><![CDATA[Kelvin scale]]></category>
		<category><![CDATA[Reaumer Scale]]></category>
		<category><![CDATA[Temperature]]></category>
		<category><![CDATA[Temperature scales]]></category>
		<category><![CDATA[Thermal equilibrium]]></category>
		<category><![CDATA[Triple point of water]]></category>
		<category><![CDATA[Zeroth law of thermodynamics]]></category>
		<guid isPermaLink="false">https://thefactfactor.com/?p=21242</guid>

					<description><![CDATA[<p>Science > Physics > Thermal Properties of Matter and Thermodynamics > Thermodynamic or Temperature Scales In last article, we have studied the concept of temperature. In this article, we shall discuss different thermodynamic or temperature scales. Temperature can be defined in several ways: It is measured in °C (centigrade or Celsius) or K (Kelvin). It [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/temperature-scales/21242/">Thermodynamic or Temperature Scales</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
]]></description>
										<content:encoded><![CDATA[
<h6 class="wp-block-heading"><strong>Science > <a href="https://thefactfactor.com/physics/" target="_blank" rel="noreferrer noopener">Physics</a> > </strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/" target="_blank" rel="noreferrer noopener">Thermal Properties of Matter and Thermodynamics</a><strong> > Thermodynamic or Temperature Scales</strong></h6>



<p>In last article, we have studied the concept of temperature. In this article, we shall discuss different thermodynamic or temperature scales.</p>



<p>Temperature can be defined in several ways:</p>



<ul class="wp-block-list">
<li>The temperature may be defined as the degree of hotness or coldness of a body.</li>



<li>The temperature of a body is an indicator of the average thermal energy (Kinetic energy) of the molecules of the body.</li>



<li>It is that physical quantity which decides the flow of heat in bodies brought in contact. Heat always flow from the body at higher temperature to the body at the lower temperature.</li>
</ul>



<p>It is measured in °C (centigrade or Celsius) or K (Kelvin).  It is measured by a device called a thermometer. The common thermometer is a mercury thermometer.</p>



<p>The branch of Physics that deals with the measurement of temperature is called Thermometry.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-normal-font-size"><strong>Concept of Thermal Equilibrium:</strong></p>



<p>Two bodies are said to be in thermal equilibrium with each other if no transfer of heat takes place when they are brought in contact, clearly, the two bodies are at the same temperature.</p>



<p class="has-accent-color has-text-color has-link-color has-normal-font-size wp-elements-97f8417ba651cb8ce199425a1c6688dd"><strong>Characteristics of Thermal Equilibrium:</strong></p>



<p>When two or more bodies are kept in contact and they are at the same temperature and there is no transfer of heat taking place between them, then those bodies are said to be in thermal equilibrium with each other. If thermal equilibrium does not exist, then heat flows from a body at a higher temperature to the body at a lower temperature, till thermal equilibrium is established. &nbsp;Characteristics define thermal equilibrium are as follows:</p>



<ul class="wp-block-list">
<li><strong>Equal Temperatures:</strong> In thermal equilibrium, all objects or systems involved have the same temperature. Temperature is a measure of the average kinetic energy of the particles within a substance. When objects are in thermal equilibrium, their average kinetic energies are the same.</li>



<li><strong>No Net Heat Transfer:</strong> In thermal equilibrium, there is no net transfer of heat between the objects or systems. Thus, there is no heat transfer between the bodies due to conduction or convection. This means that while individual particles may still exchange energy through collisions, the overall transfer of thermal energy between the objects results in no net change in their temperatures.</li>



<li><strong>Stable State:</strong> Thermal equilibrium represents a stable state in which the thermal properties of the objects or systems involved remain constant over time. Any initial differences in temperature between the objects or systems will eventually lead to thermal equilibrium as heat is transferred between them.</li>



<li><strong>Zero Temperature Gradient:</strong> A temperature gradient refers to the change in temperature over a distance. In thermal equilibrium, there is no temperature gradient between the objects or systems. This means that the temperature is uniform throughout the system.</li>



<li><strong>Dynamic Equilibrium:</strong> While there is no net transfer of thermal energy in thermal equilibrium, individual particles within the system may still be in motion, exchanging energy through collisions. Thermal equilibrium represents a dynamic balance where the rates of energy transfer between particles are equal.</li>
</ul>



<p>Understanding thermal equilibrium is crucial in various fields such as thermodynamics, heat transfer, and the study of thermal properties of materials. It helps in analyzing and predicting the behaviour of systems where heat exchange is involved.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-normal-font-size"><strong>Zeroth Law of Thermodynamics:</strong></p>



<p>The Zeroth Law of Thermodynamics is one of the fundamental principles that govern thermodynamic systems. It was formulated after the First and Second Laws of Thermodynamics, but its importance in establishing temperature measurement and the concept of thermal equilibrium led to its designation as the &#8220;Zeroth&#8221; law. This law introduces the concept of hotness and coldness which leads to the concept of the temperature of a body.</p>



<p>The Zeroth Law states that &#8220;If two systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other.&#8221;</p>



<p>Thus, if two bodies P and Q are in thermal equilibrium and also P and R in thermal equilibrium then Q and R, are also in thermal equilibrium.</p>



<p>The Zeroth Law essentially establishes the concept of temperature and allows us to define and measure it. It provides a basis for the construction of thermometers and temperature scales. For instance, if two objects are in thermal equilibrium, they have the same temperature.</p>



<p>The importance of the Zeroth Law lies in its role in defining the concept of temperature and establishing the foundation for thermal equilibrium. It allows us to compare temperatures and define scales, which are fundamental for understanding and analyzing the behaviour of thermodynamic systems.</p>



<p class="has-vivid-red-color has-subtle-background-background-color has-text-color has-background has-normal-font-size"><strong>Triple Point of Water:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-large"><img loading="lazy" decoding="async" width="289" height="300" src="https://thefactfactor.com/wp-content/uploads/2020/04/Thermodynamics-03.png" alt="" class="wp-image-11608"/></figure>
</div>


<p>Phase diagram of water consists of three curves sublimation curve, evaporation curve and melting curve meeting each other at a&nbsp;point called the triple point. Due to these curves, the phase diagram has three regions</p>



<p>The region to the left of the melting curve and above the sublimation curve represents the solid phase of water i.e. ice. The region to the right of the melting curve and above the evaporation curve represents the liquid phase of water i.e. water. The region below the sublimation curve and evaporation curve represent the gaseous phase of water i.e. vapours.</p>



<p>A curve on the phase diagram represents the boundary between two phases of the two substances. Along any curve, the two phases can coexist in equilibrium.</p>



<p>Along the melting curve, ice and water can remain in equilibrium. This curve is called a fusion curve or ice line. This curve indicates that the melting point of ice decreases with an increase in pressure. Along the evaporation curve, water vapours and water can remain in equilibrium. This curve is called the vaporisation curve or steam line. This curve indicates that the boiling point of water increases with an increase in pressure. Along the sublimation curve, ice and water vapours can remain in equilibrium. This curve is called the sublimation line or hoar frost line.</p>



<p>The three curves meet each other at a single point at A. This common point is known as the triple point of water. At the triple point of water can coexist in all the three states in equilibrium. The triple point of water corresponds to a pressure of 0.006023 atmospheres and temperature (0.01 °C) 273.16 K.</p>



<p class="has-accent-color has-text-color has-medium-font-size"><strong>Significance of Triple Point of Water:</strong></p>



<ul class="wp-block-list">
<li>Triple point temperature of the water is the temperature at which water can coexist in all the three states viz. Ice (solid), water (liquid), vapours (gas) in equilibrium.</li>



<li>This triple point temperature of the water is used for defining the absolute temperature scale. In absolute or Kelvin scale 0 K is considered as the lower fixed point while the triple point temperature of the&nbsp;water is taken as the upper fixed point.</li>



<li>Thus one kelvin temperature corresponds to 1/273.16 of the triple point temperature.</li>
</ul>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-normal-font-size"><strong><strong>Various Temperature Scales</strong>:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="185" height="157" src="https://thefactfactor.com/wp-content/uploads/2024/02/Temperature-Scales.jpg" alt="Temperature Scales" class="wp-image-21247"/><figcaption class="wp-element-caption">Temperature Scales</figcaption></figure>
</div>


<p>There are several temperature scales used around the world, each with its own reference points and units of measurement. Here are the most common temperature scales:</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Celsius Scale (° C):</strong></p>



<p>In this scale, the melting point of ice at one-atmosphere pressure and at mean sea level is taken as the lower reference point and consider as 0° C. While boiling point of water at one atmosphere pressure and at mean sea level is taken as an upper reference point and consider as 100° C. The range between the two reference points is divided into 100 equal parts and each part is called 1° C (one degree Celsius). This scale is also called a centigrade scale.</p>



<p>A lower limit of 0° C is considered arbitrary, this scale can be extended to indicate negative temperatures also. A temperature below -273.15° C is not possible.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Fahrenheit Scale (° F):</strong></p>



<p>In this scale, the melting point of ice at one-atmosphere pressure and at mean sea level is taken as the lower reference point and consider as 32° F. While boiling point of water at one atmosphere pressure and at mean sea level is taken as the upper reference point and consider as 212° F. The range between the two reference points is divided into 180 equal parts and each part is called 1° F (one degree Fahrenheit). Nowadays, this scale is not in use.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Kelvin Scale (K):</strong></p>



<p>In this scale, the lowest possible temperature -273.15° C &nbsp;is taken as a lower reference point. This temperature is called absolute zero. The division of 1 K is equal to 1° C. The unit of temperature in the kelvin scale is K (kelvin) and is considered as the fundamental unit in the S.I. system of units.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Reaumer Scale:</strong></p>



<p> In this scale, the melting point of ice at one-atmosphere pressure and at mean sea level is taken as the lower reference point and consider as 0° R. While boiling point of water at one-atmosphere pressure and at mean sea level is taken as an upper reference point and consider as 80° R. The range between the two reference points is divided into 80 equal parts and each part is called 1° R (one-degree Reaumer). </p>



<p class="has-accent-color has-text-color has-large-font-size"><strong>Conversion of Temperature in Different Scales:</strong></p>



<p class="has-text-align-center">Celsius scale to Kelvin scale &nbsp;° C &nbsp;+ &nbsp;273 = K</p>



<p class="has-text-align-center">Kelvin scale to Celsius scale&nbsp; K &nbsp;&#8211; &nbsp;273 = ° C</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="484" height="94" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-13.png" alt="" class="wp-image-17541" style="width:224px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-13.png 484w, https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-13-300x58.png 300w" sizes="auto, (max-width: 484px) 100vw, 484px" /></figure>
</div>


<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-normal-font-size"><strong>Numerical Problems:</strong></p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 01:</strong></p>



<p><strong>Find the temperature at which the temperature scales in the following pairs give the same reading: (1) Celsius and Fahrenheit and (2) Fahrenheit and Kelvin</strong></p>



<p><strong>(1) Celsius and Fahrenheit</strong></p>



<p><strong>Solution:</strong></p>



<p>Let  θ  be the required temperature, such that F = C =  θ .</p>



<p>We have</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="222" height="93" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-01.png" alt="Temperature Scales" class="wp-image-17516" style="width:112px;height:auto"/></figure>
</div>


<p class="has-text-align-center">∴  (θ &#8211; 32)/180 =  θ /100</p>



<p class="has-text-align-center"> ∴   100θ – 3200 = 180 θ </p>



<p class="has-text-align-center"> ∴    &#8211; 80θ = 3200</p>



<p class="has-text-align-center"> ∴    θ = &#8211; 40<sup>o</sup>F = &#8211; 40<sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus at &#8211; 40<sup>o</sup>C or &#8211; 40<sup>o</sup>F, the temperature scales in Celsius and Fahrenheit give the same reading.</p>



<p><strong>(2) Fahrenheit and kelvin:</strong></p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">Let  θ  be the required temperature, such that F = K =  θ .</p>



<p class="has-text-align-center">We have</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="258" height="88" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-02-1.png" alt="Temperature Scales" class="wp-image-17520" style="width:128px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴     (θ &#8211; 32)/9 = ( θ  – 273)/5</p>



<p class="has-text-align-center"> ∴     5θ – 160 = 9 θ  &#8211; 2457</p>



<p class="has-text-align-center"> ∴     4θ = 2297</p>



<p class="has-text-align-center"> ∴     θ = 574.25<sup>o</sup>F = 574.25 K</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus at 574.25<sup>o</sup>F or 574.25<sup>o</sup>K, the temperature scales in Fahrenheit and Kelvin give the same reading.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 02:</strong></p>



<p><strong>Determine the temperature on the Fahrenheit scale which is indicated by double the number on the Centigrade scale.</strong></p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">Let  θ  be the required temperature in centigrade scale, such that C =  θ  and F = 2 θ .</p>



<p class="has-text-align-center">We have</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="222" height="93" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-01.png" alt="Temperature Scales" class="wp-image-17516" style="width:110px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴      (2 θ  &#8211; 32)/180 =  θ /100</p>



<p class="has-text-align-center"> ∴      200 θ  – 3200 = 180 θ </p>



<p class="has-text-align-center"> ∴      20 θ  = 3200</p>



<p class="has-text-align-center">  ∴      θ = 160<sup>o</sup>C</p>



<p class="has-text-align-center"> ∴      2 θ  = 2 x 160<sup>o</sup> = 320 <sup>o</sup>F</p>



<p class="has-text-align-center"><strong>Ans: </strong>320 <sup>o</sup>F is the temperature on the Fahrenheit scale which is indicated by double the number on the Centigrade scale (160<sup>o</sup>C).</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 03:</strong></p>



<p><strong>Convert the following temperature in centigrade into Fahrenheit</strong></p>



<ul class="wp-block-list">
<li><strong>-37<sup> o</sup>C</strong><strong></strong></li>
</ul>



<p class="has-text-align-center">Given C = -37<sup> o</sup>C</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="222" height="93" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-01.png" alt="Temperature Scales" class="wp-image-17516" style="width:106px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴      (F – 32)/180 = (-37)/100</p>



<p class="has-text-align-center"> ∴      100F – 3200 = 6660</p>



<p class="has-text-align-center"> ∴      100F = 9860</p>



<p class="has-text-align-center"> ∴      F = 98.6<sup>o</sup>F</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus equivalent of temperature -37<sup> o</sup>C is 98.6<sup> o</sup>F</p>



<ul class="wp-block-list">
<li><strong>100</strong><strong><sup>o</sup></strong><strong>C</strong><strong></strong></li>
</ul>



<p class="has-text-align-center">Given C = -100<sup> o</sup>C</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="222" height="93" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-01.png" alt="Temperature Scales" class="wp-image-17516" style="width:114px;height:auto"/></figure>
</div>


<p class="has-text-align-center">  ∴       (F – 32)/180 = 100/100</p>



<p class="has-text-align-center">  ∴       (F – 32)/180 = 1</p>



<p class="has-text-align-center">  ∴       F – 32 = 180</p>



<p class="has-text-align-center">  ∴       F = 212<sup>o</sup>F</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus equivalent of temperature 100<sup> o</sup>F is 212<sup> o</sup>F</p>



<ul class="wp-block-list">
<li><strong>-192</strong><strong><sup> o</sup></strong><strong>C</strong><strong></strong></li>
</ul>



<p class="has-text-align-center">Given C = -192<sup> o</sup>C</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="222" height="93" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-01.png" alt="Temperature Scales" class="wp-image-17516" style="width:110px;height:auto"/></figure>
</div>


<p class="has-text-align-center">  ∴       (F – 32)/180 = (-192)/100</p>



<p class="has-text-align-center">  ∴       100F – 3200 = &#8211; 34560</p>



<p class="has-text-align-center">  ∴       100F = &#8211; 31360</p>



<p class="has-text-align-center">  ∴       F = &#8211; 313.6<sup>o</sup>F</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus equivalent of temperature -192<sup> o</sup>C is &#8211; 313.6<sup> o</sup>F</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 04:</strong></p>



<p><strong>Convert the following temperature in centigrade into Fahrenheit</strong><strong></strong></p>



<ul class="wp-block-list">
<li><strong>-108</strong> <strong></strong></li>
</ul>



<p class="has-text-align-center">Given F = -108<sup> o</sup>F</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="222" height="93" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-01.png" alt="Temperature Scales" class="wp-image-17516" style="width:108px;height:auto"/></figure>
</div>


<p class="has-text-align-center">  ∴       (-108 – 32)/180 = C/100</p>



<p class="has-text-align-center">  ∴       -140/180 = C/100</p>



<p class="has-text-align-center">  ∴       C = (7/9) x 100</p>



<p class="has-text-align-center">  ∴   C = &#8211; 77.78 <sup>o</sup>C</p>



<p><strong>Ans: </strong>Thus equivalent of temperature -108<sup> o</sup>F is – 77.78<sup> o</sup>C</p>



<ul class="wp-block-list">
<li><strong>176</strong> <strong></strong></li>
</ul>



<p class="has-text-align-center">Given F = 176<sup> o</sup>F</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="222" height="93" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-01.png" alt="" class="wp-image-17516" style="width:110px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴    (176 – 32)/180 = C/100</p>



<p class="has-text-align-center"> ∴    144/180 = C/100</p>



<p class="has-text-align-center"> ∴    C = (4/5) x 100</p>



<p class="has-text-align-center"> ∴    C = 80 <sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus equivalent of temperature 176<sup> o</sup>F is 80<sup> o</sup>C</p>



<ul class="wp-block-list">
<li><strong>140</strong> <strong></strong></li>
</ul>



<p class="has-text-align-center">Given F = 140<sup> o</sup>F</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="222" height="93" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-01.png" alt="Temperature Scales" class="wp-image-17516" style="width:106px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴    (140 – 32)/180 = C/100</p>



<p class="has-text-align-center"> ∴    108/180 = C/100</p>



<p class="has-text-align-center"> ∴    C = (3/5) x 100</p>



<p class="has-text-align-center"> ∴    C = 60 <sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus equivalent of temperature 140<sup> o</sup>F is 60<sup> o</sup>C</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 05:</strong></p>



<p><strong>The fundamental interval of a thermometer is arbitrarily divided into 80 divisions. The lower fixed point of the thermometer is marked  <strong>10 <strong><sup>o</sup></strong></strong>. Find what reading this thermometer will show when the reading on a centigrade thermometer is 60<sup> o</sup>C.</strong></p>



<p><strong>Solution:</strong></p>



<p><strong>Scale 1:</strong> Number of Divisions = n = 80, the lower Fixed Point = L = 10<sup>o</sup>.</p>



<p><strong>Centigrade Scale:</strong> Number of divisions = n = 100, the lower fixed point = L = 0<sup>o</sup>.</p>



<p class="has-text-align-center">Given C = 60<sup>o</sup>C</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="251" height="192" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-03.png" alt="" class="wp-image-17521" style="width:111px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴  ( θ  – 10)/4 = 60/5</p>



<p class="has-text-align-center">  ∴   ( θ  – 10)/4 = 12</p>



<p class="has-text-align-center">  ∴   ( θ  – 10) = 48</p>



<p class="has-text-align-center">  ∴    θ  = 58<sup>o</sup> on the new scale</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus equivalent of temperature 60<sup> o</sup>C is 58<sup>o</sup> on the new scale.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 06:</strong><strong></strong></p>



<p><strong>The lower fixed point of a thermometer is marked 10<sup>o</sup> and the upper fixed point is 130<sup>o</sup>, the interval between the fixed points is divided into 120 equal divisions. What should be the reading indicated by this thermometer when a Centigrade thermometer reads 40<sup>o</sup>?</strong></p>



<p><strong>Solution:</strong></p>



<p><strong>Scale 1:</strong> Number of Divisions = n = 120, the lower Fixed Point = L = 10<sup>o</sup>., The upper fixed point = U = 130<sup>o</sup></p>



<p><strong>Centigrade Scale:</strong> Number of divisions = n = 100, the lower fixed point = L = 0<sup>o</sup>.</p>



<p class="has-text-align-center">Given C = 60<sup>o</sup>C</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="261" height="191" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-04.png" alt="" class="wp-image-17522" style="width:117px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴    ( θ  – 10)/6 = 40/5</p>



<p class="has-text-align-center"> ∴    ( θ  – 10)/6 = 8</p>



<p class="has-text-align-center"> ∴    ( θ  – 10) = 48</p>



<p class="has-text-align-center"> ∴     θ  = 58<sup>o</sup> on the new scale</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus equivalent of temperature 40<sup> o</sup>C, is = 58<sup>o</sup> on the new scale.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 07:</strong></p>



<p><strong>The fundamental interval of a thermometer <span>is divided arbitrarily into 40 equal parts and that of another thermometer 𝑦 into 80 equal parts. If the freezing point </span>is marked 20<strong><sup>o</sup></strong> and that of y is marked 10<strong><sup>o</sup></strong>, what is the temperature on when y indicates 70<strong><sup>o</sup></strong>? What is the temperature in degrees celsius?</strong></p>



<p><strong>Part I:</strong></p>



<p><strong>Solution:</strong></p>



<p><strong>Scale of thermometer x:</strong> Number of Divisions = n = 40, the lower Fixed Point = L = 20<sup>o</sup>,</p>



<p><strong>Scale of thermometer y:</strong> Number of divisions = n = 80, the lower fixed point = L = 0<sup>o</sup>.</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="221" height="184" src="https://thefactfactor.com/wp-content/uploads/2021/08/image-1.png" alt="" class="wp-image-17525" style="width:117px;height:auto"/></figure>
</div>


<p class="has-text-align-center">Given Y = 70<sup>o</sup>C</p>



<p class="has-text-align-center"> ∴      (X – 20)/40 = 70/80</p>



<p class="has-text-align-center"> ∴      X – 20 = 35</p>



<p class="has-text-align-center"> ∴      X = 55<sup>o</sup> on the scale of thermometer X.</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus equivalent of temperature 70<sup> o</sup> on scale of thermometer y, is = 55<sup>o</sup> on the scale of thermometer x.</p>



<p><strong>Part II:</strong></p>



<p><strong>Solution:</strong></p>



<p><strong>Scale on thermometer y:</strong> Number of Divisions = n = 80, the lower Fixed Point = L = 0<sup>o</sup>.</p>



<p><strong>Centigrade Scale:</strong> Number of divisions = n = 100, the lower fixed point = L = 0<sup>o</sup>.</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="205" height="184" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-06.png" alt="" class="wp-image-17526" style="width:105px;height:auto"/></figure>
</div>


<p class="has-text-align-center">Given Y = 70<sup>o</sup>C</p>



<p class="has-text-align-center">  ∴       70/4 = C/5</p>



<p class="has-text-align-center">  ∴       C = (70/4) x 5 = 87.5<sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans:</strong> Thus equivalent of temperature 70<sup> o</sup> on the scale of thermometer y, is = 87.5<sup>o</sup>C on the centigrade scale.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 08:</strong></p>



<p><strong>Two arbitrary scales A and B have triple points of water defined on 200 A and 350 B. What is the relation between</strong> <strong>T<sub>A</sub></strong> <strong>and</strong> <strong>T<sub>B</sub>?</strong></p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">The triple point of water is 373 K</p>



<p class="has-text-align-center">For Scale A, 273 K = 200 A i.e. 1 K = (273/200) T<sub>A</sub> …………… (1)</p>



<p class="has-text-align-center">For Scale B, 273 K = 350 B i.e. 1 K = (273/350) T<sub>B</sub> …………… (2)</p>



<p class="has-text-align-center">From relations (1) and (2) we have</p>



<p class="has-text-align-center">(273/200) T<sub>A</sub> = (273/350) T<sub>B</sub></p>



<p class="has-text-align-center"> ∴        350 T<sub>A</sub> = 200 T<sub>B</sub></p>



<p class="has-text-align-center"> ∴         T<sub>A</sub> / T<sub>B</sub>  = 200/350</p>



<p class="has-text-align-center"> ∴         T<sub>A</sub> / T<sub>B</sub>  = 4/7</p>



<p class="has-text-align-center"><strong>Ans: </strong> T<sub>A</sub> / T<sub>B</sub>  = 4/7</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 09:</strong></p>



<p><strong>A Centigrade thermometer has its lower and upper fixed points marked &#8211; 0.5<sup> o</sup>C and 100.5<sup> o</sup>C. What is the true temperature when this thermometer reads30<sup>o</sup>C? The bore of the thermometer is uniform.</strong></p>



<p><strong>Solution:</strong></p>



<p><strong>Scale 1:</strong> The lower Fixed Point = L = &#8211; 0.5<sup> o</sup>C., the upper fixed point = U = 100.5<sup> o</sup>C</p>



<p><strong>Centigrade scale:</strong> Number of divisions = n = 100, the lower fixed point = L = 0<sup>o</sup>.</p>



<p class="has-text-align-center">Given S = 30<sup>o</sup>C</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="318" height="199" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-07.png" alt="" class="wp-image-17528" style="width:154px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-07.png 318w, https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-07-300x188.png 300w" sizes="auto, (max-width: 318px) 100vw, 318px" /></figure>
</div>


<p class="has-text-align-center"> ∴        (30 + 0.5)/101= C/100</p>



<p class="has-text-align-center"> ∴        C = (30.5/101) x 100</p>



<p class="has-text-align-center"> ∴        C = 30.198<sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus true temperature reading is 30.198<sup>o</sup>C</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 10:</strong></p>



<p><strong>A thermometer is fixed points marked as 5 and 95. What is the correct temperature in Celsius when the thermometer reads 59?</strong></p>



<p><strong>Solution:</strong></p>



<p><strong>Scale 1:</strong> The lower Fixed Point = L = 5, the upper fixed point = U = 95</p>



<p><strong>Centigrade scale:</strong> Number of divisions = n = 100, the lower fixed point = L = 0<sup>o</sup>.</p>



<p class="has-text-align-center">Given S = 59</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="221" height="180" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-08.png" alt="" class="wp-image-17531" style="width:125px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴  (59 &#8211; 5)/90= C/100</p>



<p class="has-text-align-center"> ∴   C = (54/90) x 100</p>



<p class="has-text-align-center"> ∴   C = 60<sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus correct temperature reading is 60<sup>o</sup>C</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 11:</strong></p>



<p><strong>In an arbitrary scale of temperature, water boils a 40<sup> o</sup>C and boils at 290<sup> o</sup>C. Find the boiling point of water in this scale if it boils at 62<sup> o</sup>C.</strong></p>



<p><strong>Solution:</strong></p>



<p><strong>Scale 1:</strong> The lower Fixed Point = L = 40<sup> o</sup>C, the upper fixed point = U = 290<sup> o</sup>C</p>



<p><strong>Centigrade scale:</strong> Number of divisions = n = 100, the lower fixed point = L = 0<sup>o</sup>.</p>



<p class="has-text-align-center">Given C = 62<sup>o</sup>C</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="270" height="193" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-09.png" alt="" class="wp-image-17533" style="width:126px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴    (S &#8211; 40)/250 = 62/100</p>



<p class="has-text-align-center"> ∴    S – 40 = 0.62 x 250</p>



<p class="has-text-align-center"> ∴    S – 40 = 155</p>



<p class="has-text-align-center"> ∴    S = 195 <sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus the boiling point of water, in the new scale is 195<sup>o</sup>C</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Example 12:</strong></p>



<p><strong>The distance between the upper and lower fixed point is 80 cm. Find the temperature on the Celsius scale if the mercury level rises to a height 10.4 cm above the lower fixed point.</strong></p>



<p><strong>Scale 1:</strong> The lower Fixed Point = L = 0 cm, the upper fixed point = U = 80 cm</p>



<p><strong>Centigrade scale:</strong> Number of divisions = n = 100, the lower fixed point = L = 0<sup>o</sup>.</p>



<p class="has-text-align-center">Given S = 10.4 cm</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="209" height="186" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-10.png" alt="" class="wp-image-17534" style="width:117px;height:auto"/></figure>
</div>


<p class="has-text-align-center"> ∴    10.4/80 = C/100</p>



<p class="has-text-align-center"> ∴    80C = 1040</p>



<p class="has-text-align-center"> ∴    C = 1040/80 = 13 <sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans: </strong>Thus the temperature on the Celsius scale is 13 <sup>o</sup>C</p>



<p class="has-text-align-left has-accent-color has-text-color has-normal-font-size"><strong>Example 13:</strong></p>



<p class="has-text-align-left"><strong>The temperature of the two bodies differs by 1oC. How much do they differ on the Fahrenheit scale?</strong></p>



<p><strong>Solution:</strong></p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="237" height="366" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-11.png" alt="" class="wp-image-17535" style="width:115px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-11.png 237w, https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-11-194x300.png 194w" sizes="auto, (max-width: 237px) 100vw, 237px" /></figure>
</div>


<p class="has-text-align-center">Differentiating both sides w.r.t. temperature T</p>


<div class="wp-block-image is-resized">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="263" height="189" src="https://thefactfactor.com/wp-content/uploads/2021/08/Temperature-Scales-12.png" alt="" class="wp-image-17536" style="width:139px;height:auto"/></figure>
</div>


<p class="has-text-align-center"><strong>Ans: </strong>Thus the difference of 1<sup>o</sup>C in Celsius scale corresponds to the difference of 1.8oF on the Fahrenheit scale.</p>



<p class="has-text-align-center"><strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/">For More Topics in Thermal Properties of Matter and Thermodynamics Click Here</a></strong></p>



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<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/temperature-scales/21242/">Thermodynamic or Temperature Scales</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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		<title>Concept of Heat</title>
		<link>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/heat/21217/</link>
					<comments>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/heat/21217/#respond</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Tue, 30 Jan 2024 14:42:33 +0000</pubDate>
				<category><![CDATA[Thermodynamics]]></category>
		<category><![CDATA[Caloric Theory of Heat]]></category>
		<category><![CDATA[erg]]></category>
		<category><![CDATA[Heat]]></category>
		<category><![CDATA[Heat Energy in Transit]]></category>
		<category><![CDATA[joule]]></category>
		<category><![CDATA[Joule’s Constant]]></category>
		<category><![CDATA[Kinetic Theory of Heat]]></category>
		<category><![CDATA[Mechanical Equivalent of Heat]]></category>
		<category><![CDATA[Phlogiston theory]]></category>
		<guid isPermaLink="false">https://thefactfactor.com/?p=21217</guid>

					<description><![CDATA[<p>Science > Physics > Thermal Properties of Matter and Thermodynamics > concept of Heat &#8220;Heat&#8221; refers to the transfer of thermal energy between substances due to a temperature difference. It&#8217;s a form of energy associated with the motion of atoms and molecules in a substance. Heat always flows from regions of higher temperature to regions [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/heat/21217/">Concept of Heat</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
]]></description>
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<h6 class="wp-block-heading"><strong>Science > <a href="https://thefactfactor.com/physics/" target="_blank" rel="noreferrer noopener">Physics</a> > </strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/" target="_blank" rel="noreferrer noopener">Thermal Properties of Matter and Thermodynamics</a><strong> > concept of Heat</strong></h6>



<p>&#8220;Heat&#8221; refers to the transfer of thermal energy between substances due to a temperature difference. It&#8217;s a form of energy associated with the motion of atoms and molecules in a substance. Heat always flows from regions of higher temperature to regions of lower temperature until thermal equilibrium is reached, where the temperatures become equal. For example, if Object A and Object B are connected, and Object A has a higher temperature than Object B, heat moves from Object A to Object B, causing Object A&#8217;s temperature to decrease and Object B&#8217;s temperature to increase. This also means that Object A&#8217;s average kinetic energy is decreasing and Object B&#8217;s average kinetic energy is increasing. This process of transfer of heat will continue till both the objects acquire the same temperature.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-be857b447561d8e6a461bf4032911150"><strong>Caloric Theory of Heat:</strong></p>



<p>The caloric theory of heat was a scientific hypothesis that dominated the understanding of heat and temperature for several centuries, particularly during the 18th and early 19th centuries. It posited that heat was a fluid-like substance called &#8220;caloric&#8221; that flowed from hot objects to cold objects, thereby causing changes in temperature. Key principles of the caloric theory include:</p>



<ul class="wp-block-list">
<li><strong>Heat as a Fluid:</strong> Caloric was thought to be a weightless, invisible fluid that could be added to or removed from substances to produce changes in temperature. When caloric flowed into an object, it caused the object to become hotter, and when it flowed out, the object became colder.</li>



<li><strong>Conservation of Caloric:</strong> Similar to the conservation of mass or energy, the caloric theory proposed that caloric was a conserved substance. It could change form or location but could not be created or destroyed.</li>



<li><strong>Explanation of Heat Phenomena:</strong> The caloric theory was used to explain various heat-related phenomena, such as the expansion of materials when heated, the melting of solids into liquids, and the evaporation of liquids into gases.</li>



<li><strong>Phlogiston Theory Connection:</strong> The caloric theory was often intertwined with the phlogiston theory, which was another outdated scientific hypothesis related to combustion and the nature of fire. Both theories attempted to explain natural phenomena using concepts of invisible, weightless substances.</li>
</ul>



<p>The caloric theory faced challenges and criticisms, particularly as scientific understanding advanced and experimental evidence mounted against it. One significant challenge came from the work of James Prescott Joule and others who demonstrated that mechanical work could be converted into heat, suggesting a connection between mechanical energy and heat that couldn&#8217;t be explained by the caloric theory alone.</p>



<p>The downfall of the caloric theory began with the experiments and insights of scientists like Benjamin Thompson (Count Rumford) and Antoine Lavoisier, who demonstrated the connection between heat and mechanical work. Ultimately, the caloric theory was replaced by the kinetic theory of gases and the understanding that heat is a form of energy associated with the motion of particles (atoms and molecules) within substances. This transition paved the way for the development of modern thermodynamics and the understanding of heat transfer on a molecular level.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-8752ac62bc5bc09eacbb21a9d0d5c0d1"><strong>Kinetic Theory of Heat:</strong></p>



<p>According to this theory all substances (solids, liquids, and gases) are made up of molecules. At any given temperature above absolute zero (0 Kelvin or -273.15 degrees Celsius), molecules and atoms of substance are in constant, random motion. This motion arises from their kinetic energy, which increases with temperature.&nbsp; Depending upon the temperature and nature of the substance the molecules may possess three types of motion:</p>



<ul class="wp-block-list">
<li><strong>Translational Motion:</strong> Molecules and atoms can undergo translational motion, meaning they move from one location to another. In gases, translational motion dominates, and molecules move freely and independently, colliding with each other and the walls of their container.</li>



<li><strong>Rotational Motion:</strong> Molecules, especially those with multiple atoms, can rotate about their centre of mass. The extent of rotational motion depends on the molecule&#8217;s shape and the presence of external influences like electric or magnetic fields.</li>



<li><strong>Vibrational Motion:</strong> Atoms within molecules are connected by chemical bonds, and these bonds can act like springs, allowing atoms to vibrate relative to each other. Vibrational motion occurs at specific frequencies dictated by the strength of the bonds and the masses of the atoms involved.</li>
</ul>



<p>When a body is heated, the average kinetic energy of its molecules and atoms also increases. This leads to several observable effects on molecular motion:</p>



<ul class="wp-block-list">
<li><strong>Increased Speed:</strong> At higher temperatures, molecules and atoms move faster on average. This is because temperature is a measure of the average kinetic energy of particles in a substance. As temperature rises, particles gain kinetic energy and move more rapidly.</li>



<li><strong>Increased Frequency of Collisions:</strong> With higher molecular speeds, the frequency of collisions between molecules and atoms also increases. This results in more energetic interactions and a greater likelihood of chemical reactions occurring, especially in gases and liquids.</li>



<li><strong>Increased Vibrational and Rotational Motion:</strong> In addition to increased translational motion (movement from one place to another), higher temperatures can also increase the vibrational and rotational motion of molecules. This is particularly evident in gases and liquids where molecules have more freedom to move.</li>



<li><strong>Expansion of Solids, Liquids, and Gases:</strong> As temperature rises, the average distance between molecules or atoms increases, causing substances to expand. This expansion is observed in solids, liquids, and gases, although the extent and mechanism vary for each state of matter.</li>



<li><strong>Changes in Phase:</strong> Temperature plays a critical role in phase transitions, such as melting, freezing, boiling, and condensation. As temperature increases, substances can transition from one phase to another by overcoming intermolecular forces or bonds that hold them together in their current state.</li>
</ul>



<p>The Kinetic Theory provides a basis for understanding heat transfer processes, including conduction, convection, and radiation. Heat transfer involves the transfer of kinetic energy between particles through collisions. The Kinetic Theory of Heat played a crucial role in the development of thermodynamics and statistical mechanics, providing a molecular-level explanation for many macroscopic observations related to the behaviour of gases, liquids, and solids. It also laid the groundwork for modern understanding of heat, temperature, and energy transfer processes.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-31a1f835b0c6d87041fa50c0312fa4c9"><strong>Heat is Energy in Transit:</strong></p>



<p>&#8220;Heat is energy in transit&#8221; is a succinct and accurate statement describing the fundamental concept of heat transfer in physics. Heat refers to the transfer of thermal energy between objects or systems due to a temperature difference. It moves from regions of higher temperature to regions of lower temperature until thermal equilibrium is achieved.</p>



<p>In this context, &#8220;energy in transit&#8221; implies that heat is not a substance itself but rather a form of energy that is transferred from one object to another. When heat flows between objects, it can bring about changes in temperature, phase transitions (like melting or boiling), or other thermal effects.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-ef0acb483d270da9c0f751de986cecac"><strong>Units of Heat:</strong></p>



<p><strong>The units of heat can vary depending on the context and the system of measurement being used. CGS Unit of Heat:</strong></p>



<p>CGS unit of heat is calorie (cal). One calorie is defined as the amount of heat required to raise the temperature of one gram of water by one degree celsius (from 14.5 to 15.5 <sup>o</sup>C) at a pressure of one atmosphere.</p>



<p>Larger unit is kilocalorie (Kcal)</p>



<p>1 Kcal = 1000 cal</p>



<p><strong>Conversions:</strong></p>



<figure class="wp-block-table aligncenter is-style-stripes"><table><tbody><tr><td class="has-text-align-center" data-align="center"><strong>From</strong></td><td class="has-text-align-center" data-align="center"><strong>to</strong></td><td class="has-text-align-center" data-align="center"><strong>Multiplying Factor</strong></td></tr><tr><td class="has-text-align-center" data-align="center">cal</td><td class="has-text-align-center" data-align="center">Kcal</td><td class="has-text-align-center" data-align="center">X 10<sup>-3</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Kcal</td><td class="has-text-align-center" data-align="center">cal</td><td class="has-text-align-center" data-align="center">X 10<sup>3</sup></td></tr></tbody></table></figure>



<p><strong>SI Unit of Heat:</strong></p>



<p>SI unit of heat is joule. One joule is defined as the amount of energy transferred when a force of one newton acts over a distance of one meter in the direction of the force.</p>



<p>1 calorie = 4.186 joule</p>



<p><strong>Conversions:</strong></p>



<figure class="wp-block-table aligncenter"><table><tbody><tr><td class="has-text-align-center" data-align="center"><strong>From</strong></td><td class="has-text-align-center" data-align="center"><strong>to</strong></td><td class="has-text-align-center" data-align="center"><strong>Multiplying Factor</strong></td></tr><tr><td class="has-text-align-center" data-align="center">cal</td><td class="has-text-align-center" data-align="center">J</td><td class="has-text-align-center" data-align="center">X 4.186</td></tr><tr><td class="has-text-align-center" data-align="center">J</td><td class="has-text-align-center" data-align="center">cal</td><td class="has-text-align-center" data-align="center">÷ 4.186</td></tr></tbody></table></figure>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-277cd9ec01558e56693c979d5ae6c3ea"><strong>Joule’s Mechanical Equivalent of Heat:</strong></p>



<p>The mechanical equivalent of heat is a concept in physics that relates mechanical work to heat energy. It was experimentally determined by James Prescott Joule in the 19th century and contributed significantly to the development of the theory of energy conservation.</p>



<p>Joule&#8217;s experiments demonstrated that mechanical work could be converted into heat energy and vice versa, implying that heat and mechanical energy were interchangeable forms of energy. His most famous experiment involved stirring water with paddles inside an insulated container, thereby converting mechanical work into an increase in the temperature of the water.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="203" height="160" src="https://thefactfactor.com/wp-content/uploads/2024/01/Mechanical-Equivalent-of-Heat.jpg" alt="Heat" class="wp-image-21218" style="aspect-ratio:1;width:314px;height:auto"/></figure>
</div>


<p>The main component of this experiment is the Joule apparatus. The apparatus basically works as follows. A weight connected to a pulley system is dropped from a known height, thereby turning side pulleys in the system. A center pulley in turn rotates a paddle wheel inside a container containing liquid. The outside of the container is thermally insulated to prevent heat loss from the container. Rotating the paddle wheel causes the temperature of the liquid to rise.</p>



<p>The paddle wheel with its many fins is fitted inside the thermally insulated container. A thermometer is fitted to read change in temperature. The shaft of the paddle wheel is connected through wires to a centre pulley located directly above the paddle wheel and then to two side pulleys, one on each side of the support structure. A weight can be attached to the end of each wire using a hook. The experiment is performed by attaching a known weight to one wire, dropping it a known distance, and then removing the weight. During this event, the wire on the other side is wound up. The experiment continues by attaching another weight and then dropping the weight as before. This process is repeated many times such that a measurable increase in the liquid&#8217;s temperature is observed. In Joule&#8217;s apparatus, the gain in the paddle wheel&#8217;s energy from the energy gained in dropping the weight becomes the gain in the heat energy of the liquid.</p>



<p class="has-text-align-center">It is observed, W α H</p>



<p class="has-text-align-center">Thus, W = JH</p>



<p class="has-text-align-center">∴ J = W/H</p>



<p>The accepted value for the mechanical equivalent of heat is approximately 4.184 joules per calorie, meaning that it takes 4.184 joules of mechanical work to produce 1 calorie of heat energy.</p>



<p class="has-text-align-center">Thus Mechanical Equivalent of Heat </p>



<p class="has-text-align-center">J = 4.186 J cal<sup>-1</sup> = 4.186 x 10<sup>7</sup> erg cal<sup>-1</sup></p>



<p>This discovery provided experimental evidence for the principle of conservation of energy, which states that energy cannot be created or destroyed but can only be converted from one form to another. The mechanical equivalent of heat helped unify the concepts of heat, work, and energy, laying the foundation for the development of thermodynamics and modern physics.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-62f4f9702b0a7dadec7a0bf88ffb9e25"><strong>Conclusion:</strong></p>



<p>Heat is a form of energy that can be transferred between objects or systems as a result of a temperature difference. It is not a substance itself but rather a mode of energy transfer. Heat is commonly measured in units such as joules (J) in the International System of Units (SI) or calories (cal) in the metric system. Heat can be transferred through conduction, convection, and radiation. Heat can produce various effects on matter, including changes in temperature, phase transitions (such as melting, boiling, and condensation), expansion or contraction of materials, and chemical reactions. Heat plays a central role in the field of thermodynamics, which studies the relationships between heat, work, and energy. The laws of thermodynamics govern how heat behaves and is transferred in various systems. Understanding the principles of heat and heat transfer is crucial in fields such as physics, engineering, chemistry, and meteorology, as heat plays a fundamental role in many natural and technological processes.</p>



<p class="has-text-align-center"><strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/">For More Topics in Thermal Properties of Matter and Thermodynamics Click Here</a></strong></p>



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		<title>Concept of Temperature</title>
		<link>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/numerical-problems-on-temperature-scales/17514/</link>
					<comments>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/numerical-problems-on-temperature-scales/17514/#respond</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Thu, 12 Aug 2021 17:12:21 +0000</pubDate>
				<category><![CDATA[Thermodynamics]]></category>
		<category><![CDATA[Absolute Scale]]></category>
		<category><![CDATA[Celsius scale]]></category>
		<category><![CDATA[Fahrenheit scale]]></category>
		<category><![CDATA[Kelvin scale]]></category>
		<category><![CDATA[Reaumer Scale]]></category>
		<category><![CDATA[Temperature]]></category>
		<category><![CDATA[Temperature scales]]></category>
		<category><![CDATA[Thermal equilibrium]]></category>
		<category><![CDATA[Thermometry]]></category>
		<category><![CDATA[Thrmometer]]></category>
		<category><![CDATA[Triple point of water]]></category>
		<category><![CDATA[Zeroth law of thermodynamics]]></category>
		<guid isPermaLink="false">https://thefactfactor.com/?p=17514</guid>

					<description><![CDATA[<p>Science > Physics > Thermal Properties of Matter and Thermodynamics > Concept of Temperature In last article we have discussed concept of heat. In this article, we shall study the concept of temperature, different temperature scales, and convert temperature in different temperature scales. Defining Temperature: Temperature can be defined in several ways: It is measured [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/numerical-problems-on-temperature-scales/17514/">Concept of Temperature</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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<h6 class="wp-block-heading"><strong>Science > <a href="https://thefactfactor.com/physics/" target="_blank" rel="noreferrer noopener">Physics</a> > </strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/" target="_blank" rel="noreferrer noopener">Thermal Properties of Matter and Thermodynamics</a><strong> > Concept of Temperature</strong></h6>



<p>In last article we have discussed concept of heat. In this article, we shall study the concept of temperature, different temperature scales, and convert temperature in different temperature scales.</p>



<p class="has-vivid-red-color has-subtle-background-background-color has-text-color has-background has-normal-font-size"><strong>Defining Temperature:</strong></p>



<p>Temperature can be defined in several ways:</p>



<ul class="wp-block-list">
<li>The temperature may be defined as the degree of hotness or coldness of a body.</li>



<li>It is an indicator of the average thermal energy (Kinetic energy) of the molecules of the body.</li>



<li>It is that physical quantity which decides the flow of heat in bodies brought in contact. Heat always flow from the body at higher temperature to the body at the lower temperature.</li>
</ul>



<p>It is measured in °C (centigrade or Celsius) or K (Kelvin).  It is measured by a device called a thermometer. </p>



<p class="has-accent-color has-text-color has-link-color has-normal-font-size wp-elements-eb91536afbab56a61f917c8d18edd445"><strong>Kinetic Interpretation of Temperature:</strong></p>



<p>Temperature reflects the average kinetic energy of particles in a substance. The kinetic energy of a particle is the energy associated with its motion. According to the kinetic theory:</p>



<ul class="wp-block-list">
<li><strong>Temperature and Kinetic Energy:</strong> As the temperature of a substance increases, the average kinetic energy of its particles also increases. This means that at higher temperatures, the particles move faster on average.</li>



<li><strong>Temperature and Particle Speed:</strong> Temperature is directly related to the average speed of the particles in a substance. Higher temperatures correspond to higher average speeds, while lower temperatures correspond to lower average speeds.</li>



<li><strong>Collisions and Pressure:</strong> The kinetic theory also explains pressure in terms of particle motion. When particles collide with the walls of their container, they exert a force, resulting in pressure. The force of the collisions depends on the speed of the particles, which in turn is related to temperature.</li>



<li><strong>Absolute Zero:</strong> According to the kinetic theory, at absolute zero (0 Kelvin), particles would have minimal kinetic energy, meaning they would completely cease their motion. This is the lowest possible temperature and represents the point at which particles have minimal energy.</li>
</ul>



<p>Thus, the kinetic interpretation of temperature provides a fundamental understanding of how the motion of particles at the microscopic level influences the macroscopic properties of a substance, such as its temperature, pressure, and volume.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-normal-font-size"><strong><strong>Various Temperature Scales</strong>:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="185" height="157" src="https://thefactfactor.com/wp-content/uploads/2024/02/Temperature-Scales.jpg" alt="Temperature Scales" class="wp-image-21247"/><figcaption class="wp-element-caption">Temperature Scales</figcaption></figure>
</div>


<p>There are several temperature scales used around the world, each with its own reference points and units of measurement. Here are the most common temperature scales:</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Celsius Scale (° C):</strong></p>



<p>In this scale, the melting point of ice at one-atmosphere pressure and at mean sea level is taken as the lower reference point and consider as 0° C. While boiling point of water at one atmosphere pressure and at mean sea level is taken as an upper reference point and consider as 100° C. The range between the two reference points is divided into 100 equal parts and each part is called 1° C (one degree Celsius). This scale is also called a centigrade scale.</p>



<p>A lower limit of 0° C is considered arbitrary, this scale can be extended to indicate negative temperatures also. A temperature below -273.15° C is not possible.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Fahrenheit Scale (° F):</strong></p>



<p>In this scale, the melting point of ice at one-atmosphere pressure and at mean sea level is taken as the lower reference point and consider as 32° F. While boiling point of water at one atmosphere pressure and at mean sea level is taken as the upper reference point and consider as 212° F. The range between the two reference points is divided into 180 equal parts and each part is called 1° F (one degree Fahrenheit). Nowadays, this scale is not in use.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Kelvin Scale (K):</strong></p>



<p>In this scale, the lowest possible temperature -273.15° C  is taken as a lower reference point. This temperature is called absolute zero. The division of 1 K is equal to 1° C. The unit of temperature in the kelvin scale is K (kelvin) and is considered as the fundamental unit in the S.I. system of units.</p>



<p class="has-accent-color has-text-color has-normal-font-size"><strong>Reaumer Scale:</strong></p>



<p> In this scale, the melting point of ice at one-atmosphere pressure and at mean sea level is taken as the lower reference point and consider as 0° R. While boiling point of water at one-atmosphere pressure and at mean sea level is taken as an upper reference point and consider as 80° R. The range between the two reference points is divided into 80 equal parts and each part is called 1° R (one-degree Reaumer). </p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-8fa012e14c882ce825b53be1f709ee0e"><strong>Difference between Heat and Temperature:</strong></p>



<p>Heat and temperature are related concepts in thermodynamics, but they represent different aspects of thermal energy.</p>



<figure class="wp-block-table aligncenter is-style-stripes"><table><tbody><tr><td class="has-text-align-center" data-align="center"><strong>Heat</strong></td><td class="has-text-align-center" data-align="center"><strong>Temperature</strong></td></tr><tr><td class="has-text-align-center" data-align="center">Heat is a form of energy that is transferred between objects or systems due to a temperature difference.</td><td class="has-text-align-center" data-align="center">Temperature is a measure of the average kinetic energy of the particles in a substance. It indicates how hot or cold an object or substance is relative to a reference point.</td></tr><tr><td class="has-text-align-center" data-align="center">It represents total kinetic energy of the molecules of a body.</td><td class="has-text-align-center" data-align="center">It represents average kinetic energy possessed by the molecules of a body.</td></tr><tr><td class="has-text-align-center" data-align="center">It is the transfer of thermal energy from a region of higher temperature to a region of lower temperature.</td><td class="has-text-align-center" data-align="center">It determines the direction of heat flow, as heat flows from higher temperature regions to lower temperature regions.</td></tr><tr><td class="has-text-align-center" data-align="center">Heat is cause because when heat is supplied to a body temperature of the body increases and when heat is removed from the body temperature of the body decreases</td><td class="has-text-align-center" data-align="center">It is the effect of addition or removal of heat from the body.</td></tr><tr><td class="has-text-align-center" data-align="center">Heat is measured in units such as joules (J) or calories (cal).</td><td class="has-text-align-center" data-align="center">It is measured in units such as Celsius (°C), Fahrenheit (°F), or Kelvin (K).</td></tr></tbody></table></figure>



<p class="has-text-align-center"><strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/">For More Topics in Thermal Properties of Matter and Thermodynamics Click Here</a></strong></p>



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<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/numerical-problems-on-temperature-scales/17514/">Concept of Temperature</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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		<title>Applications of Expansion of Solids</title>
		<link>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/applications-of-linear-expansion-of-solids/7656/</link>
					<comments>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/applications-of-linear-expansion-of-solids/7656/#comments</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Sat, 25 Jan 2020 11:57:06 +0000</pubDate>
				<category><![CDATA[Thermodynamics]]></category>
		<category><![CDATA[Applications of expansion of solids]]></category>
		<category><![CDATA[Areal expansion]]></category>
		<category><![CDATA[Change in area]]></category>
		<category><![CDATA[Change in length]]></category>
		<category><![CDATA[Change in volume]]></category>
		<category><![CDATA[Coefficient of areal expansion]]></category>
		<category><![CDATA[Coefficient of cubical expansion]]></category>
		<category><![CDATA[Coefficient of linear expansion]]></category>
		<category><![CDATA[Coefficient of longitudinal expansion]]></category>
		<category><![CDATA[Coefficient of superficial expansion]]></category>
		<category><![CDATA[Coefficient of volumetric expansion]]></category>
		<category><![CDATA[Cubical expansion]]></category>
		<category><![CDATA[Expansion of solids]]></category>
		<category><![CDATA[Linear expansion]]></category>
		<category><![CDATA[Longitudinal expansion]]></category>
		<category><![CDATA[Superficial expansion]]></category>
		<category><![CDATA[Volumetric expansion]]></category>
		<guid isPermaLink="false">https://thefactfactor.com/?p=7656</guid>

					<description><![CDATA[<p>Science > Physics > Thermal Properties of Matter and Thermodynamics > Applications of Expansion of Solids Linear expansion or longitudinal expansion refers to the increase in length of a solid material when its temperature rises. This phenomenon occurs due to the increased thermal energy within the material, causing its constituent particles to vibrate more vigorously, [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/applications-of-linear-expansion-of-solids/7656/">Applications of Expansion of Solids</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
]]></description>
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<h6 class="wp-block-heading"><strong>Science > <a href="https://thefactfactor.com/physics/" target="_blank" rel="noreferrer noopener">Physics</a> > </strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/" target="_blank" rel="noreferrer noopener">Thermal Properties of Matter and Thermodynamics</a><strong> > Applications of Expansion of Solids</strong></h6>



<p>Linear expansion or longitudinal expansion refers to the increase in length of a solid material when its temperature rises. This phenomenon occurs due to the increased thermal energy within the material, causing its constituent particles to vibrate more vigorously, thereby increasing the average distance between them. Understanding the linear expansion is crucial for predicting and engineering the thermal behaviour of materials in various applications, including construction, manufacturing, and thermal management systems.</p>



<p><strong>LIST OF SUB-TOPICS:</strong></p>



<ul class="wp-block-list">
<li><strong><a href="#Linear">Applications of Linear Expansion of Solids</a></strong></li>



<li><strong><a href="#Superficial">Applications of Superficial Expansion of Solids</a></strong></li>



<li><strong><a href="#Cubical">Applications of Cubical Expansion of Solids</a></strong></li>
</ul>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-medium-font-size" id="Linear"><strong>Applications of Linear Expansion of Solids:</strong></p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>A gap is kept between two successive rails</strong></p>



<p>The rails of a railway expand in summer and contract in winter. Therefore gaps are kept between successive rails to allow for their expansion. The gap allows the rails to expand without exerting excessive force on the structure. </p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="239" height="164" src="https://thefactfactor.com/wp-content/uploads/2024/02/Rail-Gap.jpg" alt="Linear Expansion" class="wp-image-21304"/></figure>
</div>


<p>If there are no gaps, the increase in temperature will cause the rails to expand and they will overlap one another or dislodge from the position. This will be dangerous to the trains and may result in a severe accident. If the rails were tightly connected without any gap, thermal expansion could cause bending, buckling, or even structural damage. </p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="152" height="103" src="https://thefactfactor.com/wp-content/uploads/2024/02/Rail-Gap-01.jpg" alt="Linear Expansion" class="wp-image-21305" style="width:244px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/Rail-Gap-01.jpg 152w, https://thefactfactor.com/wp-content/uploads/2024/02/Rail-Gap-01-150x103.jpg 150w" sizes="auto, (max-width: 152px) 100vw, 152px" /></figure>
</div>


<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>To put an iron tyre on a wooden wheel of bullock cart, the iron tyre is heated first</strong></p>



<p>Putting an iron tyre on a wooden wheel of a bullock cart involves a process known as &#8220;shrinking&#8221; or &#8220;setting&#8221; the tyre onto the wheel. </p>



<p>The diameter of the iron tyre is always slightly less than the wooden wheel of the bullock cart. Heating the iron tyre causes it to expand due to thermal expansion. As the temperature increases, the diameter of iron tyre. This expansion makes the iron tire slightly larger in diameter. Hence the tyre easily slides over the wooden wheel of the bullock cart. Then water is poured on the red-hot tyre. It contracts and grips the wheel firmly.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="179" height="158" src="https://thefactfactor.com/wp-content/uploads/2024/02/Iron-Tyre.jpg" alt="Linear Expansion" class="wp-image-21310" style="width:309px;height:auto"/></figure>
</div>


<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>The clocks regulated with pendulum
require adjustment during summer and winter.</strong></p>



<p>The
pendulums of clocks expand in summer and contract in winter, therefore, they
lose time in summer and gain time in winter. In order that the clocks should
give correct time, the pendulums are made from invar which is an alloy having a
very small coefficient of linear expansion in some clocks, compensating
pendulums are used.</p>



<p>A compensating pendulum is made of a number of iron and brass rods joined in such a way that the length of the pendulums remains constant even if there is a change in temperature. Such clocks show accurate time. If this is not possible the clocks require the adjustment in summer and winter.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Bimetallic strips are used as temperature
controlling devices.</strong></p>



<p>The bending of the bimetallic strip is due to the difference in the coefficient of linear expansion of two different metals used in the bimetallic strip.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="300" height="202" src="https://thefactfactor.com/wp-content/uploads/2024/02/Bimetallic-Strip.jpg" alt="Linear Expansion" class="wp-image-21314"/></figure>
</div>


<p>A bimetallic strip consists two strips of different metals fixed to each other lengthwise An increase in temperature causes bending of the strip in such a way that the metal of greater linear coefficient of expansion lies on the outer side. A lowering of temperature again bends the strip, but with the metal of smaller linear coefficient of expansion on the outer side. Such strips can be used in electric iron, electric oven, refrigerators to control the temperature.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>When the hot glass of a lamp is touched
with a cold knife, it sometimes cracks. </strong></p>



<p>When the hot glass of a lamp is touched with a cold knife,  the part of the glass, which is in contact with the knife contracts. Due to this local contraction, While remaining portion remains in the expanded condition. Due to uneven expansion in the glass, the glass cracks. This phenomenon is known as thermal shock.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>When hot milk is poured into a thick-walled glass vessel it cracks.</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="305" height="131" src="https://thefactfactor.com/wp-content/uploads/2024/02/Thermal-Shock.jpg" alt="" class="wp-image-21316" style="width:387px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/Thermal-Shock.jpg 305w, https://thefactfactor.com/wp-content/uploads/2024/02/Thermal-Shock-300x129.jpg 300w" sizes="auto, (max-width: 305px) 100vw, 305px" /></figure>
</div>


<p>When milk is poured into a thick-walled glass vessel at room temperature, the inner surface of the vessel gets expanded, while the outer surface remains at room temperature. Thus there is no expansion on the outer surface. Due to uneven expansion in the vessel, the glass cracks. This phenomenon is known as thermal shock.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>The unit of the coefficient of expansion the same for linear, superficial as well as a cubical expansion:</strong></p>



<p>The
coefficient of expansion is the ratio of two similar quantities divided by
temperature. Therefore, its unit is the same as the reciprocal of the unit of
temperature for any kind of expansion.</p>



<p>If the temperature is measured on the Celsius scale the unit is per degree Celsius and if the temperature is measured on the Kelvin scale, the unit is per degree Kelvin.</p>



<p class="has-accent-color has-text-color has-link-color wp-elements-f1f32205c8c4785920dd2a5dcdc5e950"><strong>Other Applications:</strong></p>



<ul class="wp-block-list">
<li>Telephone and electric wires are arranged little bit loosely between any of the two poles. It is simply because with the decrease in temperature in winter season, the wire contracts and if they were arranged tightly that will become further tight and they may break. To avoid this problem, they were arranged loosely.</li>
</ul>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="299" height="139" src="https://thefactfactor.com/wp-content/uploads/2024/02/Telephone-Wires.jpg" alt="" class="wp-image-21322"/></figure>
</div>


<ul class="wp-block-list">
<li>Iron or steel girders are used in the construction of a bridge. One end of the girder is rigidly fixed with bricks and concrete. The other end is not fixed. Instead, the end is set on a roller over the support. When there is rise or fall in temperature due to seasonal changes, girders may expand or contract, without developing any thermal stress.</li>
</ul>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="238" height="96" src="https://thefactfactor.com/wp-content/uploads/2024/02/Roller-Bridge.jpg" alt="" class="wp-image-21323" style="width:422px;height:auto"/></figure>
</div>


<ul class="wp-block-list">
<li>In construction and engineering, materials like concrete, steel, and asphalt expand and contract with temperature changes. Expansion joints are used to allow for these movements without causing damage to structures. For example, bridges, buildings, and pipelines incorporate expansion joints to accommodate thermal expansion and contraction.</li>
</ul>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="227" height="134" src="https://thefactfactor.com/wp-content/uploads/2024/02/Expansion-Joint.jpg" alt="" class="wp-image-21328" style="width:307px;height:auto"/></figure>
</div>


<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-medium-font-size" id="Superficial"><strong>Applications of Superficial Expansion of Solids:</strong></p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Removing Tight Lids of Glass Jar:</strong></p>



<p>To open
the lid of a glass jar that is tight enough, it is immersed in hot water for a
minute or so. Metal cap expands and becomes loose. It would now be easy to turn
it to open.</p>



<p>The
high-temperature water causes the metal lid and glass jar to expand. But the
glass has a low coefficient of expansion than the material of the lid. Hence
the lid expands more than the glass jar and the lid can be easily removed.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>To Pass a Nail Through Hole in Metal Plate:</strong></p>



<p>To pass nail through a metal plate having a hole of a diameter slightly less than that of the nail, the plate is heated. so that the diameter of hole increases and the nail can easily pass through it.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-medium-font-size" id="Cubical"><strong>Applications of Volumetric Expansion of Solids:</strong></p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Use of Mercury or Alcohol in Thermometer:</strong></p>



<p>A thermometer measures temperature by measuring a temperature-dependent property. Expansion of liquid is the temperature-dependent property and they are in direct proportion. Thus measuring the change in volume of mercury we can find the change in temperature.</p>



<p>Mercury has a high boiling point, and a highly predictable and shows a uniform response to changes in temperature. Mercury has a very high coefficient of volumetric expansion than the glass. Hence expands at a faster rate than glass. The expansion of the glass is negligible.</p>



<p>In a
typical mercury thermometer, mercury is placed in a long, narrow sealed tube
called a capillary. Because it expands at a much faster rate than the glass
capillary, the mercury rises and falls with the temperature. A thermometer is
calibrated with one of the temperature scales.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Riveting of two Metal Plates:</strong></p>



<p>Two steel
plates can be jointly tightly together by a process called riveting. Rivets are
heated to red hot condition and are forced through coaxial holes in the two
plates. The end of hot rivets is then hammered and shaped. On cooling, the
rivets contract and bring the plates tightly gripped to each other.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="471" height="154" src="https://thefactfactor.com/wp-content/uploads/2024/02/Rivetting.jpg" alt="" class="wp-image-21319" srcset="https://thefactfactor.com/wp-content/uploads/2024/02/Rivetting.jpg 471w, https://thefactfactor.com/wp-content/uploads/2024/02/Rivetting-300x98.jpg 300w" sizes="auto, (max-width: 471px) 100vw, 471px" /></figure>
</div>


<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Design of Air Craft:</strong></p>



<p>The aircraft expands by 15-25centimetress during its flight due to the increase in temperature on account of heat created by friction with the air. Designers used rollers (separators) to isolate the cabin and passenger area from the body of the aircraft so that the expansion does not rip the plane apart.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Overflow Tanks of Coolant in Automobiles:</strong></p>



<p>The efficiency of an internal combustion engine depends on heat rejected to the surroundings. Thus efficient cooling of the engine ensures the efficiency of the engine. Coolants are used to cool the engine. But during the process coolant itself undergoes volumetric expansion. If overflow tanks are not provided, there is a possibility of the bursting of coolant line. Hence&nbsp;automobiles have coolant overflow tanks.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Use of Thick Bottles for Soft Drinks:</strong></p>



<p>To avoid bursting of soft drink bottles containing gas, due to thermal expansion, their walls are made very thick.</p>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-62f4f9702b0a7dadec7a0bf88ffb9e25"><strong>Conclusion:</strong></p>



<p><br>The expansion of solids, which refers to the increase in size or volume of a material in response to changes in temperature, has several practical applications across various fields. Understanding the principles of thermal expansion allows engineers and designers to develop systems and structures that can accommodate temperature changes and operate reliably in various environments.</p>



<p class="has-text-align-center"><strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/">For More Topics in Thermal Properties of Matter and Thermodynamics Click Here</a></strong></p>



<p class="has-text-align-center"><strong><a href="https://thefactfactor.com/physics/">For More Topics in Physics Click Here</a></strong></p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/applications-of-linear-expansion-of-solids/7656/">Applications of Expansion of Solids</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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		<title>Numerical Problems on Linear Expansion of Solids</title>
		<link>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/coefficient-of-linear-expansion-numericals/7649/</link>
					<comments>https://thefactfactor.com/facts/pure_science/physics/thermodynamics/coefficient-of-linear-expansion-numericals/7649/#comments</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Sat, 25 Jan 2020 11:27:37 +0000</pubDate>
				<category><![CDATA[Thermodynamics]]></category>
		<category><![CDATA[Areal expansion]]></category>
		<category><![CDATA[Change in area]]></category>
		<category><![CDATA[Change in length]]></category>
		<category><![CDATA[Change in volume]]></category>
		<category><![CDATA[Coefficient of areal expansion]]></category>
		<category><![CDATA[Coefficient of cubical expansion]]></category>
		<category><![CDATA[Coefficient of linear expansion]]></category>
		<category><![CDATA[Coefficient of longitudinal expansion]]></category>
		<category><![CDATA[Coefficient of superficial expansion]]></category>
		<category><![CDATA[Coefficient of volumetric expansion]]></category>
		<category><![CDATA[Cubical expansion]]></category>
		<category><![CDATA[Expansion of solids]]></category>
		<category><![CDATA[Linear expansion]]></category>
		<category><![CDATA[Longitudinal expansion]]></category>
		<category><![CDATA[Superficial expansion]]></category>
		<category><![CDATA[Volumetric expansion]]></category>
		<guid isPermaLink="false">https://thefactfactor.com/?p=7649</guid>

					<description><![CDATA[<p>Science > Physics > Expansion of Solids > Numerical Problems on Linear Expansion of Solids In this article, we shall study to solve problems to calculate the coefficient of linear expansion of solid, final length and the change in temperature. Example – 01: A metal scale is graduated at 0 oC. What would be the [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/coefficient-of-linear-expansion-numericals/7649/">Numerical Problems on Linear Expansion of Solids</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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										<content:encoded><![CDATA[
<h5 class="wp-block-heading"><strong>Science > <a rel="noreferrer noopener" href="https://thefactfactor.com/physics/" target="_blank">Physics</a> > <a href="https://thefactfactor.com/physics/expansion-of-solids/">Expansion of Solids</a> > Numerical Problems on Linear Expansion of Solids</strong></h5>



<p>In this article, we shall study to solve problems to calculate the coefficient of linear expansion of solid, final length and the change in temperature.</p>



<p class="has-medium-font-size"><strong>Example – 01:</strong></p>



<p><strong>A metal scale is graduated at 0 <sup>o</sup>C. What would be
the true length of an object which when measured with the scale at 25 <sup>o</sup>C,
reads 50 cm? α for metal is 18 x 10<sup>-6</sup> /<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 0 <sup>o</sup>C,
final temperature = t<sub>2</sub> = 25 <sup>o</sup>C, measured length = <em>l</em><sub>1</sub> = 50 cm, coefficient of
linear expansion = α = 18 x 10<sup>-6</sup> /<sup>o</sup>C.</p>



<p><strong>To
Find:</strong> Actual length = <em>l</em><sub>2</sub> =?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center"><em>l</em><sub> 2</sub> = <em>l</em><sub> 1</sub> (1 + α (t<sub>2</sub> – t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 50 x (1 + 18 x 10<sup>-6</sup>&nbsp; (25 – 0))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 50 x (1 + 18 x 10<sup>-6</sup>&nbsp; x 25)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 50 x (1 + 450 x 10<sup>-6</sup>)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 50 x (1 + 0. 000450)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 50 x 1. 000450</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 50.225 cm</p>



<p class="has-text-align-center"><strong>Ans:</strong> the true length of object is 50.225 cm</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 02:</strong></p>



<p><strong>A metal rod is 64.522 cm long at 12 <sup>o</sup>C and 64.576
cm at 90 <sup>o</sup>C. Find the coefficient of linear expansion of its
material.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 12 <sup>o</sup>C,
final temperature = t<sub>2</sub> = 90 <sup>o</sup>C, initial length = <em>l</em><sub>1</sub> = 64.522 cm, final length
= <em>l</em><sub> 2</sub> = 64.576 cm.</p>



<p><strong>To
Find:</strong> coefficient of linear expansion = α
=?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center"><em>l</em><sub> 2</sub> = <em>l</em><sub> 1</sub> (1 + α (t<sub>2</sub> – t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= <em>l</em><sub> 1</sub> + α l<sub>1</sub> (t<sub>2</sub>
– t<sub>1</sub>)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
&#8211; <em>l</em><sub> 1</sub> = α l<sub>1</sub> (t<sub>2</sub>
– t<sub>1</sub>)</p>



<p class="has-text-align-center">∴&nbsp; 64.576&nbsp; &#8211; 64.522&nbsp; = α x 64.522 x&nbsp; (90
– 12)</p>



<p class="has-text-align-center">∴&nbsp; 0.054&nbsp; = α x 64.522 x&nbsp; 78</p>



<p class="has-text-align-center">∴&nbsp; α = (0.054)/(64.522 x&nbsp; 78) = 1.073 x 10<sup>-5</sup>
/<sup>o</sup>C.</p>



<p class="has-text-align-center"><strong>Ans:</strong> The coefficient of linear expansion is 1.073 x 10<sup>-5</sup> /<sup>o</sup>C.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 03:</strong></p>



<p><strong>A metal bar measures 60 cm at 10 <sup>o</sup>C. What would
be its length at 110 <sup>o</sup>C, α = 1.5 x 10<sup>-5</sup> /<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 10 <sup>o</sup>C,
final temperature = t<sub>2</sub> = 110 <sup>o</sup>C, initial length = <em>l</em><sub>1</sub> = 60 cm, coefficient of
linear expansion = α = 1.5 x 10<sup>-5</sup> /<sup>o</sup>C.</p>



<p><strong>To
Find:</strong> final length = l<sub>2</sub> =?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center"><em>l</em><sub> 2</sub> = <em>l</em><sub> 1</sub> (1 + α (t<sub>2</sub> – t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 60 x (1 + 1.5 x 10<sup>-5</sup>&nbsp; (110 – 10))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 60 x (1 + 1.5 x 10<sup>-5</sup>&nbsp; x 100)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 60 x (1 + 1.5 x 10<sup>-3</sup>)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 60 x (1 + 0. 0015)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 60 x 1. 0015</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= 60.09 cm</p>



<p class="has-text-align-center"><strong>Ans:</strong> the length at 110 <sup>o</sup>C will be 60.09 cm</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 04:</strong></p>



<p><strong>A rod is found to be 0.04 cm longer at 30 <sup>o</sup>C than
it is at 10 <sup>o</sup>C. Calculate its length at 0 <sup>o</sup>C if
coefficient of linear expansion = α = 2 x 10<sup>-5</sup> /<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Difference in lengths = <em>l</em><sub>2</sub>
– <em>l</em><sub> 1</sub> = 0.04 cm, Initial
temperature = t<sub>1</sub> = 10 <sup>o</sup>C, final temperature = t<sub>2</sub>
= 30 <sup>o</sup>C, coefficient of linear expansion = α = 2 x 10<sup>-5</sup> /<sup>o</sup>C.</p>



<p><strong>To
find:</strong> Initial length = <em>l</em><sub> o</sub> = ?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center"><em>l</em><sub> 1</sub> = <em>l</em><sub> o</sub> (1 + αt<sub>1</sub>)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 1</sub>
= <em>l</em><sub> o</sub> (1 + 2 x 10<sup>-5</sup>
x 10)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 1</sub>
= <em>l</em><sub> o</sub> (1 + 2 x 10<sup>-5</sup>)&nbsp;&nbsp;
……….&nbsp; (1)</p>



<p class="has-text-align-center">Now, <em>l</em><sub> 2</sub>
= <em>l</em><sub> o</sub> (1 + αt<sub>2</sub>)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= <em>l</em><sub> o</sub> (1 + 2 x 10<sup>-5</sup>
x 30)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= <em>l</em><em>l</em><sub> o</sub> (1 + 60 x 10<sup>-5</sup>)&nbsp;&nbsp; ……….&nbsp;
(2)</p>



<p class="has-text-align-center">From equations (1) and (2)</p>



<p class="has-text-align-center"><em>l</em><sub> 2</sub> – <em>l</em><sub> 1</sub> = <em>l</em><sub> o</sub> (1 + 60 x 10<sup>-5</sup>) &#8211; <em>l</em><sub> o</sub> (1 + 20 x 10<sup>-5</sup>)</p>



<p class="has-text-align-center">∴&nbsp; 0.04&nbsp; = <em>l</em><sub>
o</sub> (1 + 60 x 10<sup>-5</sup> &#8211; 1 &#8211; 20 x 10<sup>-5</sup>)</p>



<p class="has-text-align-center">∴&nbsp; 0.04&nbsp; = l<sub>o</sub> x&nbsp; 40 x 10<sup>-5</sup></p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> o</sub>
= 0.04 / (40 x 10<sup>-5</sup>) = 100 cm</p>



<p class="has-text-align-center"><strong>Ans:</strong> The length of rod at 0 <sup>o</sup>C is 100 cm</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 05:</strong></p>



<p><strong>The length of iron rod at 100 <sup>o</sup>C is 300.36 cm and
at 150 <sup>o</sup>C is 300.54 cm. Calculate its length at 0 <sup>o</sup>C and
coefficient of linear expansion of iron.</strong></p>



<p><strong>Given:</strong> initial length = <em>l</em><sub>1</sub>
= 300.36 cm, final length = <em>l</em><sub> 2</sub>
= 300.54 cm, Initial temperature = t<sub>1</sub> = 100 <sup>o</sup>C, final
temperature = t<sub>2</sub> = 150 <sup>o</sup>C,</p>



<p><strong>To
find:</strong> Initial length = <em>l</em><sub> o</sub> = ? and coefficient of
linear expansion = α =?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center"><em>l</em><sub> 1</sub> = <em>l</em><sub> o</sub> (1 + αt<sub>1</sub>)</p>



<p class="has-text-align-center">∴&nbsp; 300.36 = <em>l</em><sub>
o</sub> (1 + 100α)&nbsp;&nbsp; ……….&nbsp; (1)</p>



<p class="has-text-align-center"><em>l</em><sub> 2</sub> = <em>l</em><sub> o</sub> (1 + αt<sub>2</sub>)</p>



<p class="has-text-align-center">∴&nbsp; 300.54 = <em>l</em><sub>
o</sub> (1 + 150α)&nbsp;&nbsp; ……….&nbsp; (2)</p>



<p class="has-text-align-center">Dividing equation (2) by (1)</p>



<p class="has-text-align-center">∴&nbsp; 300.54/300.36 = <em>l</em><sub>
o</sub> (1 + 150α)/<em> l</em><sub> o</sub> (1
+ 100α)</p>



<p class="has-text-align-center">∴&nbsp; 1.0006 = (1 + 150α)/(1 + 100α)</p>



<p class="has-text-align-center">∴&nbsp; 1.0006(1 + 100α) = (1 + 150α)</p>



<p class="has-text-align-center">∴&nbsp; 1.0006 + 100.06α =&nbsp; 1 + 150α</p>



<p class="has-text-align-center">∴&nbsp; 1.0006 &#8211; 1 =&nbsp; 150α &#8211; 100.06α</p>



<p class="has-text-align-center">∴&nbsp; 0.0006 &nbsp;=&nbsp; 49.94α</p>



<p class="has-text-align-center">∴&nbsp; α = 0.0006/49.94</p>



<p class="has-text-align-center">∴&nbsp; α = 1.2 x 10<sup>-5</sup> /<sup>o</sup>C</p>



<p class="has-text-align-center">From equation (1)</p>



<p class="has-text-align-center">300.36 = <em>l</em><sub> o</sub>
(1 + 100α)</p>



<p class="has-text-align-center">∴&nbsp; 300.36 = <em>l</em><sub>
o</sub> (1 + 100 x 1.2 x 10<sup>-5</sup>)</p>



<p class="has-text-align-center">∴&nbsp; 300.36 = <em>l</em><sub>
o</sub> (1 + 1.2 x 10<sup>-3</sup>)</p>



<p class="has-text-align-center">∴&nbsp; 300.36 = <em>l</em><sub>
o</sub> (1 + 0.0012)</p>



<p class="has-text-align-center">∴&nbsp; 300.36 = <em>l</em><sub>
o</sub> (1 .0012)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> o</sub>
= 300.36/1 .0012 = 300 cm</p>



<p class="has-text-align-center"><strong>Ans:</strong> The length of rod at 0 <sup>o</sup>C is 300 cm and coefficient of linear expansion is 1.2 x 10<sup>-5</sup> /<sup>o</sup>C</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 06:</strong></p>



<p><strong>By how much will a steel rod 1 m long expand when heated
from 25 <sup>o</sup>C to 55 <sup>o</sup>C? The coefficient of volume expansion
of steel is 3 x 10<sup>-5</sup> /<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 25 <sup>o</sup>C,
final temperature = t<sub>2</sub> = 55 <sup>o</sup>C, initial length = <em>l</em><sub>1</sub> =&nbsp; 1m, coefficient of
volume expansion = γ = 3 x 10<sup>-5</sup> /<sup>o</sup>C.</p>



<p><strong>To
Find:</strong> Increase in length = <em>l</em><sub> 2</sub> &#8211; <em>l</em><sub> 1</sub> =?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">coefficient of volume expansion (γ) = 3 x coefficient of
linear expansion (α)</p>



<p class="has-text-align-center">3 x 10<sup>-5</sup>&nbsp; = 3 x α</p>



<p class="has-text-align-center">∴&nbsp; α = 1 x 10<sup>-5</sup> /<sup>o</sup>C</p>



<p class="has-text-align-center"><em>l</em><sub> 2</sub> = <em>l</em><sub> 1</sub> (1 + α (t<sub>2</sub> – t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
= <em>l</em><sub> 1</sub> + α <em>l</em><sub> 1</sub> (t<sub>2</sub> – t<sub>1</sub>)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
&#8211; <em>l</em><sub> 1</sub> = α <em>l</em><sub> 1</sub> (t<sub>2</sub> – t<sub>1</sub>)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
&#8211; <em>l</em><sub> 1</sub> = 1 x 10<sup>-5</sup>&nbsp;
x 1 x&nbsp; (55 – 25)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
&#8211; <em>l</em><sub> 1</sub> = 10<sup>-5</sup>
x&nbsp; 30</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
&#8211; <em>l</em><sub> 1</sub> = 3 x 10<sup>-4</sup>
m</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> 2</sub>
&#8211; <em>l</em><sub> 1</sub> = 0.3 x 10<sup>-3</sup>
m = 0.3 mm</p>



<p class="has-text-align-center"><strong>Ans:</strong> The rod will expand by 0.3 mm.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 07:</strong></p>



<p><strong>A brass rod and an iron rod are each 1m in length at 0 <sup>o</sup>C.
Find the difference in their lengths at 110 <sup>o</sup>C. α for brass is 19 x
10<sup>-6</sup> /<sup>o</sup>C and α for iron is 10 x 10<sup>-6</sup> /<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 0 <sup>o</sup>C,
final temperature = t<sub>2</sub> = 110 <sup>o</sup>C, initial length = <em>l</em><sub>Br1</sub> = <em>l</em><sub>Fe1</sub> =1m, coefficient of linear expansion for brass = α<sub>Br</sub>
= 19 x 10<sup>-6</sup> /<sup>o</sup>C. Coefficient of linear expansion for iron
= α<sub>Fe</sub> = 10 x 10<sup>-6</sup> /<sup>o</sup>C.</p>



<p><strong>To
Find:</strong> Difference in length = l<sub>Br2</sub>
– l<sub>Fe2</sub> =?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">For brass rod</p>



<p class="has-text-align-center"><em>l</em><sub>Br2</sub> = <em>l</em><sub> Br1</sub> (1 + α<sub>&nbsp;Br</sub>
(t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">For iron rod</p>



<p class="has-text-align-center"><em>l</em><sub>Fe2</sub> = <em>l</em><sub> Fe1</sub> (1 + α<sub>&nbsp;Fe</sub>
(t<sub>2</sub> -t<sub>1</sub>))&nbsp; ……….&nbsp; (2)</p>



<p class="has-text-align-center">Subtracting equation (2) from (1)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>Br2</sub>
&#8211; <em>l</em><sub>Fe2 </sub>= <em>l</em><sub> Br1</sub> (1 + α<sub>&nbsp;Br</sub>
(t<sub>2</sub> -t<sub>1</sub>)) &#8211; <em>l</em><sub>
Fe1</sub> (1 + α<sub>&nbsp;Fe</sub> (t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>Br2</sub>
&#8211; <em>l</em><sub>Fe2&nbsp;&nbsp;</sub>= 1 (1 +
19 x 10<sup>-6</sup> (110 &#8211; 10)) &#8211; 1 (1 + 19 x 10<sup>-6</sup> (110 &#8211; 10))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>Br2</sub>
&#8211; <em>l</em><sub>Fe2&nbsp;&nbsp;</sub>= 1 + 19
x 10<sup>-6</sup> x 100 &#8211; 1 &#8211; 10 x 10<sup>-6</sup> x 100</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>Br2</sub>
&#8211; <em>l</em><sub>Fe2&nbsp;&nbsp;</sub>= 9
&nbsp;x 10<sup>-6</sup> x 100 = 900 x 10<sup>-6</sup> m</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>Br2</sub>
&#8211; <em>l</em><sub>Fe2&nbsp;&nbsp;</sub>= 0.9 x
10<sup>-3</sup> m = 0.9 mm</p>



<p class="has-text-align-center"><strong>Ans:</strong> The difference in their lengths is 0.9 mm</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 08:</strong></p>



<p><strong>A brass rod and an iron rod are each 1m in length at 20 <sup>o</sup>C.
At what temperature the difference in their lengths is 1.4 mm. α for brass is
18.92 x 10<sup>-6</sup> /<sup>o</sup>C and α for iron is 11.92 x 10<sup>-6</sup>
/<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 20 <sup>o</sup>C,
initial length = <em>l</em><sub>Br1</sub> = <em>l</em><sub>Fe1</sub> =1m, coefficient of
linear expansion for brass = α<sub>Br</sub> = 18.92 x 10<sup>-6</sup> /<sup>o</sup>C,
coefficient of linear expansion for iron = α<sub>Fe</sub> = 11.92 x 10<sup>-6</sup>
/<sup>o</sup>C. Difference in length = <em>l</em><sub>Br2</sub>
– <em>l</em><sub>Fe2</sub> = 1.4 mm = 1.4 x 10<sup>-3</sup>
m.</p>



<p><strong>To
Find:</strong> final temperature = t<sub>2</sub>
=?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">For brass rod</p>



<p class="has-text-align-center"><em>l</em><sub>Br2</sub> = <em>l</em><sub> Br1</sub> (1 + α<sub>&nbsp;Br</sub>
(t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">For iron rod</p>



<p class="has-text-align-center"><em>l</em><sub>Fe2</sub> = <em>l</em><sub> Fe1</sub> (1 + α<sub>&nbsp;Fe</sub>
(t<sub>2</sub> -t<sub>1</sub>))&nbsp; ……….&nbsp; (2)</p>



<p class="has-text-align-center">Subtracting equation (2) from (1)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>Br2</sub>
&#8211; <em>l</em><sub>Fe2&nbsp;</sub>= <em>l</em><sub> Br1</sub> (1 + α<sub>&nbsp;Br</sub>
(t<sub>2</sub> -t<sub>1</sub>)) &#8211; <em>l</em><sub>
Fe1</sub> (1 + α<sub>Fe</sub> (t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; 1.4 x 10<sup>-3</sup> = 1 (1 + 18.92 x 10<sup>-6</sup>
(t<sub>2</sub> -20)) &#8211; 1 (1 + 11.92 x 10<sup>-6</sup> (t<sub>2</sub> -20))</p>



<p class="has-text-align-center">∴&nbsp; 1.4 x 10<sup>-3</sup> = 1 + 18.92 x 10<sup>-6</sup>
(t<sub>2</sub> -20) &#8211; 1 &#8211; 11.92 x 10<sup>-6</sup> (t<sub>2</sub> -20)</p>



<p class="has-text-align-center">∴&nbsp; 1.4 x 10<sup>-3</sup> = 7 x 10<sup>-6</sup> (t<sub>2</sub>
-20)</p>



<p class="has-text-align-center">∴&nbsp; (t<sub>2</sub> -20) =1.4 x 10<sup>-3</sup>/7 x 10<sup>-6</sup>
= 200</p>



<p class="has-text-align-center">∴&nbsp; t<sub>2</sub> = 200 + 20 = 220 <sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans:</strong> At 220&nbsp;<sup>o</sup>C&nbsp;the difference in their lengths is 1.4 mm.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 09:</strong></p>



<p>A rod A and
a rod B are of equal length at 0 <sup>o</sup>C. If at 100 <sup>o</sup>C they
differ by 1mm find their lengths at 0 <sup>o</sup>c,&nbsp;α<sub>A</sub> = 8 x
10<sup>-6</sup> /<sup>o</sup>C,&nbsp;α<sub>B</sub> = 12 x 10<sup>-6</sup> /<sup>o</sup>C.</p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 0 <sup>o</sup>C,&nbsp;final
temperature = t<sub>2</sub> =&nbsp;100 <sup>o</sup>C,&nbsp;initial length = <em>l</em><sub>A1</sub> = <em>l</em><sub>B1</sub>, coefficient of linear expansion for rod A = α<sub>A</sub>
= 8 x 10<sup>-6</sup> /<sup>o</sup>C, coefficient of linear expansion for rod B
= α<sub>B</sub> = 12 x 10<sup>-6</sup> /<sup>o</sup>C. Difference in length = <em>l</em><sub>B2</sub> – <em>l</em><sub>A2</sub> = 1 mm = 1 x 10<sup>-3</sup> m.</p>



<p><strong>To
Find:</strong> Initial lengths of rod at&nbsp;0 <sup>o</sup>C</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">For rod A</p>



<p class="has-text-align-center"><em>l</em><sub>A2</sub> = <em>l</em><sub> A1</sub> (1 + α<sub>&nbsp;A</sub>
(t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">For rod B</p>



<p class="has-text-align-center"><em>l</em><sub>B2</sub> = <em>l</em><sub>&nbsp;B1</sub> (1 + α<sub>&nbsp;B</sub>
(t<sub>2</sub> -t<sub>1</sub>))&nbsp; ……….&nbsp; (2)</p>



<p class="has-text-align-center">Subtracting equation (2) from (1)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>B2</sub>
&#8211; <em>l</em><sub>A2&nbsp;</sub>= <em>l</em><sub> B1</sub> (1 + α<sub>&nbsp;B</sub>&nbsp;(t<sub>2</sub>
-t<sub>1</sub>)) &#8211; <em>l</em><sub>&nbsp;A1</sub>
(1 + α<sub>A</sub> (t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; 1 x 10<sup>-3</sup> = <em>l</em><sub> B1</sub> (1 + 12 x 10<sup>-6</sup> (100&nbsp;&#8211; 0)) &#8211; <em>l</em><sub> A1</sub> (1 + 8 x 10<sup>-6</sup>
(100&nbsp;&#8211; 0))</p>



<p class="has-text-align-center">∴&nbsp; 1 x 10<sup>-3</sup> = <em>l</em><sub> B1</sub> (1 + 12 x 10<sup>-6</sup> (100)) &#8211; <em>l</em><sub> A1</sub> (1 + 8 x 10<sup>-6</sup> (100))</p>



<p class="has-text-align-center">Now, given  <em>l</em><sub>A1</sub> = <em>l</em><sub>B1</sub> </p>



<p class="has-text-align-center">∴&nbsp; 1 x 10<sup>-3</sup> = <em>l</em><sub> A1</sub>&nbsp;(1 + 12 x 10<sup>-4</sup>&nbsp; &#8211; <em>l</em><sub> A1</sub> (1 + 8 x 10<sup>-4</sup>)</p>



<p class="has-text-align-center">∴&nbsp; 1 x 10<sup>-3</sup> = <em>l</em><sub> A1</sub>&nbsp;(1 + 12 x 10<sup>-4</sup>&nbsp; &#8211; 1 &#8211; 8 x 10<sup>-4</sup>)</p>



<p class="has-text-align-center">∴&nbsp; 1 x 10<sup>-3</sup> = <em>l</em><sub> A1</sub>&nbsp;x 4 x 10<sup>-4</sup></p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> A1</sub>&nbsp;
= 1 x 10<sup>-3</sup> / &nbsp;4 x 10<sup>-4</sup>= 2.5 m</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>A1</sub>&nbsp;
= l<sub>B1&nbsp;</sub>= 2.5 m</p>



<p class="has-text-align-center"><strong>Ans:</strong> At 0&nbsp;<sup>o</sup>C&nbsp;the lengths of the two rods is 2.5 m.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 10:</strong></p>



<p><strong>A brass rod and an iron rod are 4 m and 4.01 m respectively&nbsp;at 20 <sup>o</sup>C. At what temperature the two rods have the same length. α for brass is 18.92 x 10<sup>-6</sup> /<sup>o</sup>C and α for iron is 11.92 x 10<sup>-6</sup> /<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 20 <sup>o</sup>C,
initial length = <em>l</em><sub>Br1</sub> = <em>l</em><sub>Fe1</sub> =1m, coefficient of
linear expansion for brass = α<sub>Br</sub> = 18 x 10<sup>-6</sup> /<sup>o</sup>C,
coefficient of linear expansion for iron = α<sub>Fe</sub> = 12 x 10<sup>-6</sup>
/<sup>o</sup>C, <em>l</em><sub>Br2</sub> = <em>l</em><sub>Fe2</sub></p>



<p><strong>To
Find:</strong> final temperature = t<sub>2</sub>
=?</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">For brass rod</p>



<p class="has-text-align-center"><em>l</em><sub>Br2</sub> = <em>l</em><sub> Br1</sub> (1 + α<sub>&nbsp;Br</sub>
(t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">For iron rod</p>



<p class="has-text-align-center"><em>l</em><sub>Fe2</sub> = <em>l</em><sub> Fe1</sub> (1 + α<sub>&nbsp;Fe</sub>
(t<sub>2</sub> -t<sub>1</sub>))&nbsp; ……….&nbsp; (2)</p>



<p class="has-text-align-center">Given <em>l</em><sub>Br2</sub>
= <em>l</em><sub>Fe2</sub></p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub> Br1</sub>
(1 + α<sub>&nbsp;Br</sub> (t<sub>2</sub> -t<sub>1</sub>)) = <em>l</em><sub> Fe1</sub> (1 + α<sub>Fe</sub> (t<sub>2</sub>
-t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; 4 (1 + 18 x 10<sup>-6</sup> (t<sub>2</sub> -20))
=&nbsp; 4.01(1 + 12 x 10<sup>-6</sup> (t<sub>2</sub> -20))</p>



<p class="has-text-align-center">∴&nbsp; 4 + 72 x 10<sup>-6</sup> (t<sub>2</sub> -20) =&nbsp;
4.01 + 48.12 x 10<sup>-6</sup> (t<sub>2</sub> -20)</p>



<p class="has-text-align-center">∴&nbsp; &nbsp;72 x 10<sup>-6</sup> (t<sub>2</sub> -20)
&#8211;&nbsp; 48.12 x 10<sup>-6</sup> (t<sub>2</sub> -20) =&nbsp; 4.01 &#8211; 4</p>



<p class="has-text-align-center">∴&nbsp; 23.88 x 10<sup>-6</sup>(t<sub>2</sub> -20) = 0.01</p>



<p class="has-text-align-center">∴&nbsp; (t<sub>2</sub> -20) = 0.01/(23.88 x 10<sup>-6</sup>)</p>



<p class="has-text-align-center">∴&nbsp; t<sub>2</sub>&nbsp; &#8211; 20 = 418.8</p>



<p class="has-text-align-center">t<sub>2</sub>&nbsp;= 418.8 + 20 = 438.8&nbsp;<sup>o</sup>C</p>



<p class="has-text-align-center"><strong>Ans:</strong> At 438.8&nbsp;<sup>o</sup>C&nbsp;the rods will have the same length</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 11:</strong></p>



<p><strong>The difference in lengths of rod A and a rod B is 60 cm at
all temperatures. Find their lengths at 0 <sup>o</sup>C,&nbsp;α<sub>A</sub> =
18 x 10<sup>-6</sup> /<sup>o</sup>C,&nbsp;α<sub>B</sub> = 27 x 10<sup>-6</sup>
/<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 0 <sup>o</sup>C,&nbsp;final
temperature = t<sub>2</sub> <sup>o</sup>C,&nbsp;coefficient of linear expansion
for rod A = α<sub>A</sub> = 18 x 10<sup>-6</sup> /<sup>o</sup>C, coefficient of
linear expansion for rod B = α<sub>B</sub> = 27 x 10<sup>-6</sup> /<sup>o</sup>C.
Difference in length = <em>l</em><sub>B2</sub>
– <em>l</em><sub>A2</sub> = 60 cm = 60 x 10<sup>-2</sup>
m,&nbsp;(t<sub>2</sub> -t<sub>1</sub>) is same for both rod.</p>



<p><strong>To
Find:</strong>Initial lengths of rod at&nbsp;0 <sup>o</sup>C</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">For rod A</p>



<p class="has-text-align-center"><em>l</em><sub>A2</sub> = <em>l</em><sub> A1</sub> (1 + α<sub>&nbsp;A</sub>
(t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center"><em>l</em><sub>A2</sub> = <em>l</em><sub> A1</sub> +&nbsp; <em>l</em><sub>A1</sub>α<sub>&nbsp;A</sub> (t<sub>2</sub>
-t<sub>1</sub>))</p>



<p class="has-text-align-center"><em>l</em><sub>A2</sub> &#8211; <em>l</em><sub> A1</sub> =&nbsp; <em>l</em><sub> A1</sub>α<sub>&nbsp;A</sub> (t<sub>2</sub>
-t<sub>1</sub>))&nbsp; ……….&nbsp; (1)</p>



<p class="has-text-align-center">For rod B</p>



<p class="has-text-align-center"><em>l</em><sub>B2</sub> &#8211; <em>l</em><sub> B1</sub> =&nbsp; <em>l</em><sub> B1</sub>α<sub>&nbsp;A</sub> (t<sub>2</sub>
-t<sub>1</sub>))&nbsp; ……….&nbsp; (1)</p>



<p class="has-text-align-center">As the difference between the two rods is always 60 cm their
expansion should be equal</p>



<p class="has-text-align-center"><em>l</em><sub>A2</sub> &#8211; <em>l</em><sub> A1</sub> =&nbsp;<em>l</em><sub>B2</sub> &#8211; <em>l</em><sub> B1</sub></p>



<p class="has-text-align-center"><em>l</em><sub> A1</sub>α<sub>&nbsp;A</sub>
(t<sub>2</sub> -t<sub>1</sub>)) = <em>l</em><sub>
B1</sub>α<sub>&nbsp;A</sub> (t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">∴ <em>l</em><sub>&nbsp;A1</sub>
α<sub>A</sub>=&nbsp; <em>l</em><sub> B1</sub>α<sub>&nbsp;B</sub></p>



<p class="has-text-align-center">∴ <em>l</em><sub>&nbsp;A1</sub>&nbsp;/<em>l</em><sub> B1</sub> =&nbsp; α<sub>&nbsp;B</sub>/
α<sub>A&nbsp;</sub>= 27 x 10<sup>-6</sup>/18 x 10<sup>-6</sup>&nbsp; = 3/2</p>



<p class="has-text-align-center">∴ <em>l</em><sub>&nbsp;A1</sub>&nbsp;
= (3/2)<em> l</em><sub> B1</sub></p>



<p class="has-text-align-center">Length of rod A is greater than rod B</p>



<p class="has-text-align-center">Now&nbsp;(<em>l</em><sub>
A1</sub>&nbsp;&#8211; <em>l</em><sub>&nbsp;B1</sub>)
= 60</p>



<p class="has-text-align-center">∴ ( (3/2)<em> l</em><sub> B1</sub>&nbsp;&#8211;
<em>l</em><sub>&nbsp;B1</sub>) = 60</p>



<p class="has-text-align-center">∴ (1/2)<em> l</em><sub> B1</sub>&nbsp;=
60</p>



<p class="has-text-align-center">∴ <em>l</em><sub>B1</sub>&nbsp;=
120 cm</p>



<p class="has-text-align-center"><em>l</em><sub>&nbsp;A1</sub>&nbsp;
= (3/2)l x 120 = 180 cm</p>



<p class="has-text-align-center"><strong>Ans:</strong> At 0&nbsp;<sup>o</sup>C&nbsp;the
length of rod A is 180 cm and that of rod B is 120 cm</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Example – 12:</strong></p>



<p><strong>The difference in lengths of rod A and a rod B is 5 cm at all temperatures. Find their lengths at 0 <sup>o</sup>C,&nbsp;α<sub>A</sub> = 12 x 10<sup>-6</sup> /<sup>o</sup>C,&nbsp;α<sub>B</sub> = 18 x 10<sup>-6</sup> /<sup>o</sup>C.</strong></p>



<p><strong>Given:</strong> Initial temperature = t<sub>1</sub> = 0 <sup>o</sup>C,&nbsp;final
temperature = t<sub>2</sub> <sup>o</sup>C,&nbsp;coefficient of linear expansion
for rod A = α<sub>A</sub> = 12 x 10<sup>-6</sup> /<sup>o</sup>C, coefficient of
linear expansion for rod B = α<sub>B</sub> = 18 x 10<sup>-6</sup> /<sup>o</sup>C.
Difference in length = <em>l</em><sub>B2</sub>
– <em>l</em><sub>A2</sub> = 5 cm = 5 x 10<sup>-2</sup>
m,&nbsp;(t<sub>2</sub> -t<sub>1</sub>) is same for both rod.</p>



<p><strong>To
Find:</strong>Initial lengths of rod at&nbsp;0 <sup>o</sup>C</p>



<p><strong>Solution:</strong></p>



<p class="has-text-align-center">Assuming length of rod B is greater than rod B</p>



<p class="has-text-align-center">For rod A</p>



<p class="has-text-align-center"><em>l</em><sub>A2</sub> = <em>l</em><sub> A1</sub> (1 + α<sub>&nbsp;A</sub>
(t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">For rod B</p>



<p class="has-text-align-center"><em>l</em><sub>B2</sub> = <em>l</em><sub>&nbsp;B1</sub> (1 + α<sub>&nbsp;B</sub>
(t<sub>2</sub> -t<sub>1</sub>))&nbsp; ……….&nbsp; (2)</p>



<p class="has-text-align-center">Subtracting equation (2) from (1)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>B2</sub>
&#8211; <em>l</em><sub>A2&nbsp;</sub>= <em>l</em><sub> B1</sub> (1 + α<sub>&nbsp;B</sub>&nbsp;(t<sub>2</sub>
-t<sub>1</sub>)) &#8211; <em>l</em><sub>&nbsp;A1</sub>
(1 + α<sub>A</sub> (t<sub>2</sub> -t<sub>1</sub>))</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>B2</sub>
&#8211; <em>l</em><sub>A2&nbsp;</sub>= <em>l</em><sub> B1</sub> + <em>l</em><sub> B1</sub>α<sub>&nbsp;B</sub>&nbsp;(t<sub>2</sub> -t<sub>1</sub>)
&#8211; <em>l</em><sub>&nbsp;A1</sub> &nbsp;&#8211; <em>l</em><sub>&nbsp;A1</sub> α<sub>A</sub> (t<sub>2</sub>
-t<sub>1</sub>)</p>



<p class="has-text-align-center">∴&nbsp; <em>l</em><sub>B2</sub>
&#8211; <em>l</em><sub>A2&nbsp;</sub>= (<em>l</em><sub> B1</sub>&nbsp;&#8211; <em>l</em><sub>A1</sub>) + (<em>l</em><sub> B1</sub>α<sub>&nbsp;B</sub>&nbsp;&nbsp;&#8211; <em>l</em><sub>&nbsp;A1</sub> α<sub>A</sub>)(t<sub>2</sub>
-t<sub>1</sub>)</p>



<p class="has-text-align-center">∴ 60 x 10<sup>-2</sup>= 60 x 10<sup>-2</sup>&nbsp;+
(<em>l</em><sub> B1</sub>α<sub>&nbsp;B</sub>&nbsp;&nbsp;&#8211;
<em>l</em><sub>&nbsp;A1</sub> α<sub>A</sub>)(t<sub>2</sub>
-t<sub>1</sub>)</p>



<p class="has-text-align-center">∴ 0= &nbsp;(<em>l</em><sub> B1</sub>α<sub>&nbsp;B</sub>&nbsp;&nbsp;&#8211; <em>l</em><sub>&nbsp;A1</sub> α<sub>A</sub>)(t<sub>2</sub>
-t<sub>1</sub>)</p>



<p class="has-text-align-center">∴ 0= &nbsp;(<em>l</em><sub> B1</sub>α<sub>&nbsp;B</sub>&nbsp;&nbsp;&#8211; <em>l</em><sub>&nbsp;A1</sub> α<sub>A</sub>)</p>



<p class="has-text-align-center">∴ <em>l</em><sub>A1</sub> α<sub>A</sub>=&nbsp;
<em>l</em><sub>B1</sub>α<sub>&nbsp;B</sub></p>



<p class="has-text-align-center">∴ <em>l</em><sub>A1</sub>&nbsp;/<em>l</em><sub> B1</sub> =&nbsp; α<sub>&nbsp;B</sub>/
α<sub>A&nbsp;</sub>= 18 x 10<sup>-6</sup>/12 x 10<sup>-6</sup>&nbsp; = 3/2</p>



<p class="has-text-align-center">∴ <em>l</em><sub>A1</sub>&nbsp;
= (3/2)l<sub> B1</sub></p>



<p class="has-text-align-center">Length of rod A is greater than rod B</p>



<p class="has-text-align-center">Now&nbsp;(<em>l</em><sub>
A1</sub>&nbsp;&#8211; <em>l</em><sub>&nbsp;B1</sub>)
= 5</p>



<p class="has-text-align-center">∴ ((3/2)<em> l</em><sub> B1</sub>&nbsp;&#8211;
<em>l</em><sub>&nbsp;B1</sub>) = 5</p>



<p class="has-text-align-center">∴ (1/2)<em> l</em><sub> B1</sub>&nbsp;=
5</p>



<p class="has-text-align-center">∴ <em>l</em><sub>B1</sub>&nbsp;=
10 cm</p>



<p class="has-text-align-center"><em>l</em><sub>A1</sub>&nbsp; =
(3/2)l x 10 = 15 cm</p>



<p class="has-text-align-center"><strong>Ans:</strong> At 0 <sup>o</sup>C the length of rod A is 15 cm and that of rod B is 10 cm</p>



<h5 class="wp-block-heading"><strong>Science > <a rel="noreferrer noopener" href="https://thefactfactor.com/physics/" target="_blank">Physics</a> > <a href="https://thefactfactor.com/physics/expansion-of-solids/">Expansion of Solids</a> > Numerical Problems on Linear Expansion of Solids</strong></h5>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/coefficient-of-linear-expansion-numericals/7649/">Numerical Problems on Linear Expansion of Solids</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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		<title>Expansion of Solids</title>
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		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Sat, 25 Jan 2020 10:30:41 +0000</pubDate>
				<category><![CDATA[Thermodynamics]]></category>
		<category><![CDATA[Areal expansion]]></category>
		<category><![CDATA[Change in area]]></category>
		<category><![CDATA[Change in length]]></category>
		<category><![CDATA[Change in volume]]></category>
		<category><![CDATA[Coefficient of areal expansion]]></category>
		<category><![CDATA[Coefficient of cubical expansion]]></category>
		<category><![CDATA[Coefficient of linear expansion]]></category>
		<category><![CDATA[Coefficient of longitudinal expansion]]></category>
		<category><![CDATA[Coefficient of superficial expansion]]></category>
		<category><![CDATA[Coefficient of volumetric expansion]]></category>
		<category><![CDATA[Cubical expansion]]></category>
		<category><![CDATA[Expansion of solids]]></category>
		<category><![CDATA[Linear expansion]]></category>
		<category><![CDATA[Longitudinal expansion]]></category>
		<category><![CDATA[Superficial expansion]]></category>
		<category><![CDATA[Volumetric expansion]]></category>
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					<description><![CDATA[<p>Science &#62; Physics &#62; Thermal Properties of Matter and Thermodynamics &#62; Expansion of Solids Whenever there is an increase in the dimensions of a body due to heating, then the body is said to be expanded and the phenomenon is known as expansion of solids. Solids undergo three types of expansions a) Linear (Longitudinal) expansions, [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/expansion-of-solids/7638/">Expansion of Solids</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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<h6 class="wp-block-heading"><strong>Science &gt; <a href="https://thefactfactor.com/physics/" target="_blank" rel="noreferrer noopener">Physics</a> &gt; </strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/" target="_blank" rel="noreferrer noopener">Thermal Properties of Matter and Thermodynamics</a><strong> &gt; Expansion of Solids</strong></h6>



<p>Whenever there is an increase in the dimensions of a body due to heating, then the body is said to be expanded and the phenomenon is known as expansion of solids. Solids undergo three types of expansions a) Linear (Longitudinal) expansions, b) Superficial expansions (Arial) and&nbsp;c) Cubical expansions (Volumetric)</p>



<p id="Back"><strong>LIST OF SUB-TOPICS:</strong></p>



<ul class="wp-block-list">
<li><strong><a href="#Linear">Linear Expansion of Solids</a></strong></li>



<li><strong><a href="#Characteristics">Characteristics of Coefficient of Linear Expansion</a></strong></li>



<li><strong><a href="#Factors">Factors Influencing the Coefficient of Linear Expansion</a></strong></li>



<li><strong><a href="#Materials">Coefficient of Linear Expansion for Different Materials</a></strong></li>



<li><strong><a href="#Superficial">Superficial Expansion of Solids</a></strong></li>



<li><strong><a href="#Cubical">Cubical Expansion of Solids</a></strong></li>



<li><strong><a href="#Beta">Relation Between&nbsp;α&nbsp;and β</a></strong></li>



<li><strong><a href="#Gama">Relation Between α and γ</a></strong></li>



<li><strong><a href="#Alpha">Relation Between α, <strong>β</strong> and γ</a></strong></li>



<li><strong><a href="#Molecular">Molecular Explanation of Expansion of Solids:</a></strong></li>
</ul>



<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-medium-font-size" id="Linear"><strong>Linear Expansion of Solid:</strong></p>



<p>Linear expansion or longitudinal expansion refers to the increase in length of a solid material when its temperature rises. This phenomenon occurs due to the increased thermal energy within the material, causing its constituent particles to vibrate more vigorously, thereby increasing the average distance between them.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Expression for the Coefficient of Linear Expansion of Solids:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="246" height="130" src="https://thefactfactor.com/wp-content/uploads/2024/02/Linear-Expansion.jpg" alt="" class="wp-image-21287" style="width:254px;height:auto"/></figure>
</div>


<p>Consider a
metal rod of length ‘<em>l</em><sub>0</sub>’ at
temperature 0 °C. Let the rod be heated to some higher temperature say t °C.
Let ‘<em>l</em>’&nbsp;be the length of the rod at
temperature t °C.</p>



<p class="has-text-align-center">∴&nbsp;Change
in temperature = t<sub>2</sub> &#8211; t<sub>1</sub> = t &#8211; 0 = t</p>



<p class="has-text-align-center">and Change in
length = <em>l&nbsp;</em>&#8211; <em>l</em><sub>0</sub></p>



<p class="has-text-align-center">Experimentally it is found that the change in length ( <em>l&nbsp;</em>&#8211; <em>l</em><sub>0</sub>) is</p>



<p class="has-text-align-center">Directly
proportional to the original length (<em>l</em><sub>0</sub>)</p>



<p class="has-text-align-center"><em>l&nbsp;</em>&#8211; <em>l</em><sub>0</sub>
&nbsp; ∝&nbsp;&nbsp;<em>l</em><sub>0&nbsp;
&nbsp;</sub>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;. (1)</p>



<p class="has-text-align-center">Directly
proportional to the change in temperature (t)</p>



<p class="has-text-align-center"><em>l&nbsp;</em>&#8211; <em>l</em><sub>0</sub> &nbsp; ∝&nbsp; t   &#8230;&#8230;&#8230;&#8230;&#8230; (1)</p>



<p class="has-text-align-center">Dependent upon the
material of the rod.</p>



<p class="has-text-align-center">From equation (1) and (2)</p>



<p class="has-text-align-center"><em>l&nbsp;</em>&#8211; <em>l</em><sub>0</sub>
&nbsp; ∝&nbsp;&nbsp;<em>l</em><sub>0&nbsp;</sub>t</p>



<p class="has-text-align-center"><em>∴&nbsp;
&nbsp;l&nbsp;</em>&#8211; <em>l</em><sub>0</sub> &nbsp; =&nbsp;&nbsp;α&nbsp;<em>l</em><sub>0&nbsp;</sub>t&nbsp;
&nbsp; &#8230;&#8230;&#8230;&#8230;&#8230; (3)</p>



<p class="has-text-align-center">Where ‘α’ is
a&nbsp;constant called a coefficient of linear expansion</p>


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" width="64" height="45" src="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-01.png" alt="Expansion of Solids" class="wp-image-7640" style="width:106px;height:auto"/></figure>
</div>


<p class="has-text-align-center">This is an
expression for the coefficient of linear expansion of a solid.</p>



<p>The
coefficient of linear-expansion is defined as the increase in length per unit
original length at 0<sup>0</sup>c per unit rise in temperature.</p>



<p class="has-text-align-center">From equation (3)
we get</p>



<p class="has-text-align-center"><em>∴&nbsp;
&nbsp;l&nbsp;&nbsp;</em>&nbsp;= <em>l</em><sub>0&nbsp;</sub>+&nbsp;α&nbsp;<em>l</em><sub>0&nbsp;</sub>t</p>



<p class="has-text-align-center"><em>∴&nbsp;
&nbsp;l&nbsp;&nbsp;</em>&nbsp;= <em>l</em><sub>0&nbsp;</sub>(1 + α&nbsp;t)
&#8230;&#8230;&#8230;&#8230;.. (4)</p>



<p class="has-text-align-center">This is an expression for the length of rod at t °C</p>



<p class="has-normal-font-size"><strong>Note:</strong> The magnitude of the coefficient of linear expansion is so&nbsp;small that it is not necessary to take the initial temperature at&nbsp;0 °C.</p>



<p>Consider a metal rod of length ‘<em>l</em><sub>1</sub>’ at temperature t<sub>1</sub>0 °C. Let the rod be heated to some higher temperature say t °C. Let ‘<em>l<sub>2</sub></em>’&nbsp;be the length of the rod at temperature t<sub>2</sub> °C. Let&nbsp;<em>l</em><sub>0</sub>’ be the&nbsp;length of the rod at the temperature of 0 °C. Let&nbsp;α be the coefficient of linear expansion, then we have</p>



<p class="has-text-align-center"><em>l<sub>1</sub> </em>=
<em>l</em><sub>0&nbsp;</sub>(1 + α t<sub>1</sub>) &#8230;&#8230;&#8230;&#8230;.. (2)</p>



<p class="has-text-align-center"><em>l<sub>2</sub> </em>=
<em>l</em><sub>0&nbsp;</sub>(1 + α t<sub>2</sub>) &#8230;&#8230;&#8230;&#8230;.. (2)</p>



<p class="has-text-align-center">Dividing equation
(2) by (1) we get</p>


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" width="358" height="453" src="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-02.png" alt="" class="wp-image-7641" style="width:408px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-02.png 358w, https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-02-237x300.png 237w" sizes="auto, (max-width: 358px) 100vw, 358px" /></figure>
</div>


<p class="has-text-align-center">The coefficient of linear expansion is different for different material</p>



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<p class="has-accent-color has-text-color has-link-color wp-elements-f65489f05a0eaf24d619e5f378c1127c" id="Characteristics"><strong>Characteristics of Coefficient of Linear Expansion:</strong></p>



<p>The coefficient of linear expansion is a material property that describes how much a material will expand or contract in length for a given change in temperature. The change in length of the material is directly proportional to the original length, the change in temperature, and the coefficient of linear expansion. Key characteristics of the coefficient of linear expansion are as follows:</p>



<ul class="wp-block-list">
<li><strong>Material Specific:</strong> The coefficient of linear expansion varies from one material to another. Different materials have different rates of expansion or contraction for the same change in temperature.</li>



<li><strong>Temperature Dependence:</strong> While the coefficient of linear expansion is often treated as a constant over a small temperature range, it can vary slightly with temperature. However, for most materials and within normal temperature ranges, this variation is negligible for practical purposes. Coefficient of linear expansion generally decreases with the increase in temperature.</li>



<li><strong>Directionality:</strong> The coefficient of linear expansion is directional and applies along a specific axis of the material. For instance, in an anisotropic material like wood, the coefficient of linear expansion can be different along different axes.</li>



<li><strong>Units:</strong> The coefficient of linear expansion is typically expressed in units of per degree Celsius or per Kelvin</li>



<li><strong>Thermal Stress Inducer:</strong> Differences in the coefficients of linear expansion between materials can lead to thermal stresses when they are bonded together. These stresses can cause mechanical failure or deformation in structures or devices.</li>



<li><strong>Measurement:</strong> Coefficients of linear expansion can be determined experimentally through techniques such as dilatometry, which involves measuring the change in length of a material for known changes in temperature.</li>
</ul>



<p>Understanding the coefficient of linear expansion is crucial in engineering and construction to design structures that can accommodate thermal expansion and contraction without causing damage or failure. The coefficient of linear expansion is an essential parameter for understanding how materials respond to temperature changes and for designing systems that can withstand such thermal effects.</p>



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<p class="has-accent-color has-text-color has-link-color wp-elements-fd8d3c55acb6290f75202821a4918a2d" id="Factors"><strong>Factors Influencing the Coefficient of Linear Expansion:</strong></p>



<p>The coefficient of linear expansion of a material is influenced by several factors, including:</p>



<ul class="wp-block-list">
<li><strong>Chemical Composition:</strong> The chemical composition of a material significantly affects its coefficient of linear expansion. Different materials have different atomic and molecular structures, which lead to variations in their expansion behaviour.</li>



<li><strong>Crystal Structure:</strong> The crystal structure of a material can influence its coefficient of linear expansion. For example, crystalline materials may have different expansion characteristics along different crystallographic directions.</li>



<li><strong>Temperature Range:</strong> The coefficient of linear expansion can vary depending on the temperature range over which it is measured. In some materials, the coefficient of linear expansion may change with temperature, especially at extreme temperatures.</li>



<li><strong>Impurities and Alloying Elements:</strong> The presence of impurities or alloying elements in a material can alter its coefficient of linear expansion. Alloying elements may introduce lattice distortions or changes in the bonding behaviour, affecting the material&#8217;s expansion properties.</li>



<li><strong>Phase Transitions:</strong> Phase transitions, such as melting or solid-state transformations, can affect the coefficient of linear expansion. Different phases of a material may exhibit different expansion behaviours.</li>



<li><strong>Anisotropy:</strong> Some materials exhibit anisotropic behaviour, meaning their properties vary depending on the direction of measurement. Anisotropy can result from the material&#8217;s crystal structure or processing methods and can lead to different coefficients of linear expansion along different axes.</li>



<li><strong>Microstructure:</strong> The microstructure of a material, including factors such as grain size, grain boundaries, and defects, can influence its coefficient of linear expansion. Grain boundaries and defects may act as obstacles to atomic movement and affect the material&#8217;s expansion behaviour.</li>



<li><strong>External Stress and Strain:</strong> The coefficient of linear expansion may change under the influence of external stress or strain. Mechanical deformation or stress can alter the material&#8217;s atomic arrangement and affect its expansion properties.</li>



<li><strong>Environmental Conditions:</strong> Environmental factors such as humidity, pressure, and the presence of reactive gases can influence the coefficient of linear expansion. Changes in these environmental conditions may affect the material&#8217;s structure and expansion behaviour.</li>
</ul>



<p>Understanding the factors that influence the coefficient of linear expansion is crucial for predicting and engineering the thermal behaviour of materials in various applications, including construction, manufacturing, and thermal management systems.</p>



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<p class="has-accent-color has-text-color has-link-color wp-elements-996faffdcdae53b0d0b7c77b773ec502" id="Materials"><strong>Coefficient of Linear Expansion for Different Materials:</strong></p>



<figure class="wp-block-table aligncenter"><table><tbody><tr><td class="has-text-align-center" data-align="center"><strong>Metals</strong></td><td class="has-text-align-center" data-align="center"><strong>Coefficient of linear expansion  at 20 °C ()</strong></td></tr><tr><td class="has-text-align-center" data-align="center">Aluminium</td><td class="has-text-align-center" data-align="center">23.1 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Benzocyclobutene</td><td class="has-text-align-center" data-align="center">42 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Brass</td><td class="has-text-align-center" data-align="center">19 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Carbon steel</td><td class="has-text-align-center" data-align="center">10.8 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Concrete</td><td class="has-text-align-center" data-align="center">12 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Copper</td><td class="has-text-align-center" data-align="center">17 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Diamond</td><td class="has-text-align-center" data-align="center">1 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Ethanol</td><td class="has-text-align-center" data-align="center">250 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Gallium(III) Arsenide</td><td class="has-text-align-center" data-align="center">5.8 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Gasoline</td><td class="has-text-align-center" data-align="center">317 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Gold</td><td class="has-text-align-center" data-align="center">14 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Ice</td><td class="has-text-align-center" data-align="center">51 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Iron</td><td class="has-text-align-center" data-align="center">11.8 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Lead</td><td class="has-text-align-center" data-align="center">29 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Magnesium</td><td class="has-text-align-center" data-align="center">26 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Mercury</td><td class="has-text-align-center" data-align="center">61 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Nickel</td><td class="has-text-align-center" data-align="center">13 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Platinum</td><td class="has-text-align-center" data-align="center">9 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Water</td><td class="has-text-align-center" data-align="center">69 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Silicon</td><td class="has-text-align-center" data-align="center">2.56 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr><tr><td class="has-text-align-center" data-align="center">Silver</td><td class="has-text-align-center" data-align="center">18 x 10<sup>-6</sup>&nbsp;K<sup>-1</sup></td></tr></tbody></table></figure>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-medium-font-size" id="Superficial"><strong>Superficial Expansion of Solids:</strong></p>



<p>Whenever there is an increase in the area of a solid body due to heating then the expansion is called superficial or Arial expansion.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Expression for the Coefficient of Superficial Expansion of Solids:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="257" height="124" src="https://thefactfactor.com/wp-content/uploads/2024/02/Superficial-Expansion.jpg" alt="" class="wp-image-21289" style="width:317px;height:auto"/></figure>
</div>


<p>Consider a
thin metal plate of area ‘A<sub>0</sub>’ at temperature 0 °C. Let the plate be
heated to some higher temperature say t °C. Let ‘A’&nbsp;be the area of the
plate at temperature t °C.</p>



<p class="has-text-align-center">∴&nbsp;Change
in temperature = t<sub>2</sub> &#8211; t<sub>1</sub> = t &#8211; 0 = t</p>



<p class="has-text-align-center">and Change in area
= A- A<sub>0</sub></p>



<p class="has-text-align-center">Experimentally it is found that the change in the area (A- A<sub>0</sub>) is</p>



<p class="has-text-align-center">Directly
proportional to the original area (A<sub>0</sub>)</p>



<p class="has-text-align-center"><em>A </em>&#8211; A<sub>0</sub>
&nbsp; ∝&nbsp;A<sub>0&nbsp;
&nbsp;</sub>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;. (1)</p>



<p class="has-text-align-center">Directly
proportional to the change in temperature (t)</p>



<p class="has-text-align-center"><em>A </em>&#8211; <em>A</em><sub>0</sub> &nbsp; ∝ t   &#8230;&#8230;&#8230;&#8230;.. (1)</p>



<p class="has-text-align-center">Dependent upon the
material of the plate</p>



<p class="has-text-align-center">From equation (1) and (2)</p>



<p class="has-text-align-center">A &#8211;&nbsp;A<sub>0</sub>
&nbsp; ∝&nbsp;A<sub>0&nbsp;</sub>t</p>



<p class="has-text-align-center"><em>∴&nbsp;
&nbsp;A </em>&#8211; A<sub>0</sub> &nbsp; =&nbsp;β A<sub>0&nbsp;</sub>t&nbsp; &nbsp;
&#8230;&#8230;&#8230;&#8230;&#8230; (3)</p>



<p class="has-text-align-center">Where ‘β’ is
a&nbsp;constant called a coefficient of superficial expansion</p>


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" width="81" height="47" src="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-03.png" alt="Expansion of Solids" class="wp-image-7642" style="width:115px;height:auto"/></figure>
</div>


<p class="has-text-align-center">This is an
expression for the coefficient of superficial expansion of a solid.</p>



<p>The
coefficient of superficial expansion is defined as the increase in area per
unit original area at 0<sup>0</sup>c per unit rise in temperature.</p>



<p class="has-text-align-center">From equation (3)
we get</p>



<p class="has-text-align-center"><em>∴&nbsp;A
&nbsp;</em>&nbsp;= A<sub>0&nbsp;</sub>+ β A<sub>0&nbsp;</sub>t</p>



<p class="has-text-align-center"><em>∴&nbsp;A &nbsp;</em>&nbsp;= A<sub>0&nbsp;</sub>(1 +  β t) &#8230;&#8230;&#8230;&#8230;.. (4)</p>



<p class="has-text-align-center">This is an
expression for the&nbsp;area of the plate at t °C</p>



<p><strong>Note:</strong> The magnitude of the coefficient of superficial expansion is so&nbsp;small that it is not necessary to take the initial temperature as&nbsp;0 °C.</p>



<p>Consider a thin metal plate of area ‘A<sub>1</sub>’ at temperature t<sub>1</sub>0 °C. Let the plate be heated to some higher temperature say t °C. Let ‘A<em><sub>2</sub></em>’&nbsp;be the area of the plate at temperature t<sub>2</sub> °C. Let &#8216;A<sub>0</sub>’ be the&nbsp;area of the plate at a temperature of 0 °C. Let β be the coefficient of superficial expansion, then we have</p>



<p class="has-text-align-center"><em>A<sub>1</sub> </em>=
<em>A</em><sub>0&nbsp;</sub>(1 +&nbsp; &nbsp; β t<sub>1</sub>) &#8230;&#8230;&#8230;&#8230;..
(2)</p>



<p class="has-text-align-center"><em>A<sub>2</sub> </em>=
<em>A</em><sub>0&nbsp;</sub>(1 +&nbsp; &nbsp; β t<sub>2</sub>) &#8230;&#8230;&#8230;&#8230;.. (2)</p>



<p class="has-text-align-center">Dividing equation
(2) by (1) we get</p>


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" width="367" height="459" src="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-04.png" alt="" class="wp-image-7644" style="width:415px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-04.png 367w, https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-04-240x300.png 240w" sizes="auto, (max-width: 367px) 100vw, 367px" /></figure>
</div>


<p class="has-text-align-center">The coefficient of superficial expansion is different for different material</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-medium-font-size" id="Cubical"><strong>Cubical Expansion of Solids:</strong></p>



<p>Whenever there is an increase in the volume of the body due to heating the expansion is called cubical or volumetric expansion.</p>



<p class="has-vivid-red-color has-text-color has-medium-font-size"><strong>Expression for the Coefficient of Cubical Expansion of  Solids:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="301" height="170" src="https://thefactfactor.com/wp-content/uploads/2024/02/Cubical-Expansion.jpg" alt="" class="wp-image-21290" style="width:399px;height:auto"/></figure>
</div>


<p>Consider a
solid body of volume ‘V<sub>0</sub>’ at temperature 0 °C. Let the body be
heated to some higher temperature say t °C. Let ‘V’&nbsp;be the volume of the
body at temperature t °C.</p>



<p class="has-text-align-center">∴&nbsp;Change
in temperature = t<sub>2</sub> &#8211; t<sub>1</sub> = t &#8211; 0 = t</p>



<p class="has-text-align-center">and Change in
volume = V &#8211; V<sub>0</sub></p>



<p class="has-text-align-center">Experimentally it is found that the change in the volume (V &#8211; V<sub>0</sub>) is</p>



<p class="has-text-align-center">Directly
proportional to the original volume (V<sub>0</sub>)</p>



<p class="has-text-align-center">V &#8211; V<sub>0</sub>
&nbsp;∝&nbsp;
V<sub>0&nbsp; &nbsp;</sub>&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;. (1)</p>



<p class="has-text-align-center">Directly
proportional to the change in temperature (t)</p>



<p class="has-text-align-center">V &#8211; V<sub>0</sub>
&nbsp;∝&nbsp;
t&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;. (1)</p>



<p class="has-text-align-center">Dependent upon the
material of the body.</p>



<p class="has-text-align-center">From equation (1) and (2)</p>



<p class="has-text-align-center">V &#8211; V<sub>0</sub>
&nbsp;∝&nbsp;
V<sub>0&nbsp;</sub>t</p>



<p class="has-text-align-center"><em>∴&nbsp;V
&#8211; V<sub>0</sub></em>&nbsp; &nbsp;=&nbsp; γ V<sub>0&nbsp;</sub>t&nbsp; &nbsp;
&#8230;&#8230;&#8230;&#8230;&#8230; (3)</p>



<p class="has-text-align-center">Where ‘γ’ is
a&nbsp;constant called a coefficient of cubical expansion</p>


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" width="86" height="45" src="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-05.png" alt="Expansion of Solids cubical 01" class="wp-image-7645" style="width:134px;height:auto"/></figure>
</div>


<p class="has-text-align-center">This is an
expression for the coefficient of cubical expansion of a solid.</p>



<p>The
coefficient cubical expansion is defined as an increase in volume per unit
original volume at 0<sup>0</sup>c per unit rise in temperature.</p>



<p class="has-text-align-center">From equation (3)
we get</p>



<p class="has-text-align-center"><em>∴&nbsp;
&nbsp;</em>V&nbsp;= V<sub>0&nbsp;&nbsp;</sub>+&nbsp; γ V<sub>0&nbsp;</sub>t</p>



<p class="has-text-align-center"><em>∴&nbsp;
&nbsp;V&nbsp;&nbsp;</em>&nbsp;= V<sub>0&nbsp;</sub>(1 +&nbsp; &nbsp; γ t)
&#8230;&#8230;&#8230;&#8230;.. (4)</p>



<p class="has-text-align-center">This is an expression for the volume of the body at t °C</p>



<p><strong>Note:</strong> The magnitude of the coefficient of cubical expansion is so&nbsp;small that it is not necessary to take the initial temperature as&nbsp;0 °C.</p>



<p>Consider a solid body of volume ‘V<sub>1</sub>’ at temperature t<sub>1</sub>0 °C. Let the body be heated to some higher temperature say t °C. Let ‘V<em><sub>2</sub></em>’&nbsp;be the volume of the body at temperature t<sub>2</sub> °C. Let &#8216;V0’ be the&nbsp;volume of the body at the temperature of 0 °C. Let γ be the coefficient of cubical-expansion, then we have</p>



<p class="has-text-align-center"><em>V<sub>1</sub> </em>&nbsp;=
V<sub>0&nbsp;</sub>(1 +&nbsp; &nbsp;γ t<sub>1</sub>) &#8230;&#8230;&#8230;&#8230;.. (2)</p>



<p class="has-text-align-center"><em>V<sub>2</sub> </em>&nbsp;=
V<sub>0&nbsp;</sub>(1 +&nbsp; γ t<sub>2</sub>) &#8230;&#8230;&#8230;&#8230;.. (2)</p>



<p class="has-text-align-center">Dividing equation
(2) by (1) we get</p>


<div class="wp-block-image">
<figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" width="331" height="417" src="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-06.png" alt="Expansion of Solids cubical 02" class="wp-image-7646" style="width:391px;height:auto" srcset="https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-06.png 331w, https://thefactfactor.com/wp-content/uploads/2020/01/Expansion-of-Solids-06-238x300.png 238w" sizes="auto, (max-width: 331px) 100vw, 331px" /></figure>
</div>


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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-medium-font-size" id="Beta"><strong>Relation Between&nbsp;α&nbsp;and β:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="214" height="131" src="https://thefactfactor.com/wp-content/uploads/2024/02/Beta.jpg" alt="" class="wp-image-21294" style="width:316px;height:auto"/></figure>
</div>


<p>Consider a
thin metal plate of length, breadth, and area&nbsp;<em>l</em><sub>0</sub>,
b<sub>0</sub>, and A<sub>0&nbsp;</sub>at temperature 0 °C. Let the plate be
heated to some higher temperature say t °C. Let <em>l</em>,
b and A&nbsp;be the length, breadth, and area of the plate at temperature t °C.</p>



<p class="has-text-align-center">Then original
area&nbsp;&nbsp; =&nbsp;&nbsp; A<sub>0</sub> =&nbsp;&nbsp; l<sub>0</sub> b<sub>0</sub>&nbsp;……………..&nbsp;
(1)</p>



<p class="has-text-align-center">Consider linear
expansion</p>



<p class="has-text-align-center">Length,&nbsp;&nbsp; <em>l</em> =&nbsp;&nbsp; l<sub>0</sub> (1+ αt)</p>



<p class="has-text-align-center">Breadth, b = b<sub>0</sub>
(1 + αt)</p>



<p class="has-text-align-center">where α =
coefficient of linear expansion</p>



<p>Final
area&nbsp;&nbsp; =&nbsp;&nbsp;&nbsp; A&nbsp;&nbsp;&nbsp; =&nbsp;l&nbsp; b&nbsp;
=&nbsp; l<sub>0</sub> (1+ αt)&nbsp;×&nbsp;b<sub>0</sub> (1 + αt)</p>



<p class="has-text-align-center">∴&nbsp; &nbsp;A&nbsp; &nbsp; =<em>&nbsp;l</em><sub>0</sub> b<sub>0</sub>&nbsp; (1+ 2 αt + α²t²)</p>



<p class="has-text-align-center">Now α is very small hence α<sup>2</sup>&nbsp;is still small,&nbsp;hence quantity α²t² can be neglected</p>



<p class="has-text-align-center">∴&nbsp;
&nbsp;A&nbsp;&nbsp;&nbsp; =&nbsp;A<sub>0&nbsp;</sub>(1+ 2 αt)&nbsp; …………&nbsp;
(2)</p>



<p class="has-text-align-center">Consider
superficial expansion of the plate area.</p>



<p class="has-text-align-center">A = A<sub>0</sub>(
1+ βt) …………&nbsp; (3)</p>



<p class="has-text-align-center">From (2) and (3)</p>



<p class="has-text-align-center">β = 2α</p>



<p class="has-text-align-center">Thus the coefficient of superficial expansion is twice the coefficient of linear expansion.</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-medium-font-size" id="Gama"><strong>Relation Between α and γ:</strong></p>


<div class="wp-block-image">
<figure class="aligncenter size-full is-resized"><img loading="lazy" decoding="async" width="298" height="202" src="https://thefactfactor.com/wp-content/uploads/2024/02/Gama-01.jpg" alt="" class="wp-image-21295" style="width:342px;height:auto"/></figure>
</div>


<p>Consider a
thin rectangular parallelopiped solid of length, breadth, height, and
volume&nbsp;<em>l</em><sub>0</sub>, b<sub>0</sub>, h<sub>0</sub>,
and V<sub>0&nbsp;</sub>at temperature 0 °C. Let the solid be heated to some
higher temperature say t °C. Let <em>l</em>, b, h and
V&nbsp;be the length, breadth, height, and volume of the solid at temperature t
°C.</p>



<p class="has-text-align-center">Then original
volume&nbsp; &nbsp; =&nbsp;&nbsp; V<sub>0</sub> =&nbsp;&nbsp; l<sub>0</sub> b<sub>0</sub>&nbsp;h<sub>0&nbsp;
&nbsp;</sub>………… (1)</p>



<p class="has-text-align-center">Consider linear
expansion</p>



<p class="has-text-align-center">Length,&nbsp;&nbsp; <em>l </em>=&nbsp;&nbsp; <em>l</em><sub>0</sub> (1+ αt)</p>



<p class="has-text-align-center">Breadth, b = b<sub>0</sub>
(1 + αt)</p>



<p class="has-text-align-center">Height&nbsp;
&nbsp;h&nbsp; = h<sub>0</sub> (1 + αt)</p>



<p class="has-text-align-center">where α =
coefficient of linear expansion</p>



<p class="has-text-align-center">Final volume&nbsp; &nbsp; =&nbsp;&nbsp;&nbsp; V&nbsp;&nbsp;&nbsp; =&nbsp;<em> l</em>&nbsp; b h&nbsp; =&nbsp; <em>l</em><sub>0</sub> (1+ αt)&nbsp;×&nbsp;b<sub>0</sub> (1 + αt)×&nbsp;h<sub>0</sub> (1 + αt)</p>



<p>∴&nbsp; &nbsp;V&nbsp; &nbsp; =&nbsp; <em>l</em><sub>0</sub> b<sub>0</sub>&nbsp; h<sub>0&nbsp;</sub>(1+ 3 αt + 3 α²t² +&nbsp;α³t³ )</p>



<p class="has-text-align-center">Now α is very small hence α<sup>2</sup>&nbsp;is still small,&nbsp;hence quantity α²t²,&nbsp;α³t³ can be neglected</p>



<p class="has-text-align-center">∴&nbsp;
&nbsp;V&nbsp;&nbsp;&nbsp; =&nbsp; V<sub>0&nbsp;</sub>(1+ 3 αt)&nbsp;
,,,,,,,,,,,,,,,,,,&nbsp; (2)</p>



<p class="has-text-align-center">Consider cubical
expansion of the solid.</p>



<p class="has-text-align-center">V = V<sub>0</sub>(
1+ γt) ,,,,,,,,,,,,,,,,,&nbsp; (3)</p>



<p class="has-text-align-center">From (2) and (3)</p>



<p class="has-text-align-center">γ = 3α</p>



<p class="has-text-align-center">Thus the coefficient of cubical expansion is the thrice coefficient of linear expansion.</p>



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<h4 class="wp-block-heading has-normal-font-size" id="Alpha">Notes:&nbsp;</h4>



<p class="has-text-align-center">We have&nbsp;β =
2α&nbsp; &nbsp;hence&nbsp;α =&nbsp;β/2&nbsp; &nbsp;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230; (1)</p>



<p class="has-text-align-center">We have γ = 3α
&nbsp; hence&nbsp;α = γ/3&nbsp; &nbsp;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230; (2)</p>



<p class="has-text-align-center">From relations (1)
and (2) we get</p>



<p class="has-text-align-center">α =&nbsp;β/2&nbsp;=&nbsp;γ/3</p>



<p class="has-text-align-center">Hence 6 α = 3 β   = 2γ</p>



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<p class="has-accent-color has-subtle-background-background-color has-text-color has-background has-link-color wp-elements-8e0cef23127ca9f2e310729ccf8fe06f" id="Molecular"><strong>Molecular Explanation of Expansion of Solids:</strong></p>



<p>The expansion of solids at the molecular level can be understood through the principles of thermal expansion and the behaviour of atoms and molecules within the solid lattice structure.</p>



<ul class="wp-block-list">
<li><strong>Vibrational Motion:</strong> Atoms and molecules within a solid are constantly in motion due to thermal energy. As the temperature of the solid increases, the average kinetic energy of the atoms and molecules also increases. This increased thermal energy causes the atoms and molecules to vibrate more vigorously about their equilibrium positions within the solid lattice.</li>



<li><strong>Increased Average Distance:</strong> The increased vibrational motion of atoms and molecules leads to an increase in the average distance between them. This phenomenon occurs because the atoms and molecules push against each other as they vibrate, causing the overall dimensions of the solid to expand.</li>



<li><strong>Interatomic Forces:</strong> The expansion of solids is influenced by the strength and nature of the interatomic or intermolecular forces within the material. In solids held together by stronger bonds, such as metallic bonds or covalent bonds, the expansion may be less pronounced compared to materials with weaker bonds, such as those held together by van der Waals forces.</li>



<li><strong>Anisotropic Expansion:</strong> Some solids exhibit anisotropic expansion, meaning they expand unequally along different crystallographic directions. This behaviour arises from the anisotropic arrangement of atoms or molecules within the crystal lattice structure. For example, in materials with layered or fibrous structures, expansion may be greater along certain directions than others.</li>



<li><strong>Phase Transitions:</strong> Phase transitions, such as melting or solid-state transformations, can also affect the expansion behaviour of solids. During phase transitions, the arrangement of atoms or molecules within the solid lattice undergoes significant changes, leading to alterations in the material&#8217;s expansion properties.</li>



<li><strong>Coefficient of Thermal Expansion:</strong> The coefficient of thermal expansion (CTE) quantifies the extent to which a material expands or contracts in response to changes in temperature. The CTE is a material-specific property that depends on factors such as the material&#8217;s composition, crystal structure, and bonding characteristics.</li>
</ul>



<p>Thus, the expansion of solids at the molecular level is a result of the increased vibrational motion of atoms and molecules within the solid lattice structure as the temperature rises. Understanding the molecular mechanisms underlying thermal expansion is essential for various applications in materials science, engineering, and thermal management.</p>



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<p class="has-text-align-center"><strong><a href="https://thefactfactor.com/physics/thermal-properties-of-matter-and-thermodynamics/">For More Topics in Thermal Properties of Matter and Thermodynamics Click Here</a></strong></p>



<p class="has-text-align-center"><strong><a href="https://thefactfactor.com/physics/">For More Topics in Physics Click Here</a></strong></p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/physics/thermodynamics/expansion-of-solids/7638/">Expansion of Solids</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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