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		<title>Equilibrium Constant</title>
		<link>https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/equilibrium-constant/11136/</link>
					<comments>https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/equilibrium-constant/11136/#respond</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Thu, 02 Apr 2020 13:06:59 +0000</pubDate>
				<category><![CDATA[Physical Chemistry]]></category>
		<category><![CDATA[Active mass]]></category>
		<category><![CDATA[Chemical equilibrium]]></category>
		<category><![CDATA[Chemical reaction]]></category>
		<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Concentration quotient]]></category>
		<category><![CDATA[Direction of reaction]]></category>
		<category><![CDATA[Dynamic equilibrium]]></category>
		<category><![CDATA[Endothermic reaction]]></category>
		<category><![CDATA[Equilibrium]]></category>
		<category><![CDATA[Equilibrium concentration]]></category>
		<category><![CDATA[Equilibrium constant.]]></category>
		<category><![CDATA[Equilibrium mixture]]></category>
		<category><![CDATA[Exothermic reaction]]></category>
		<category><![CDATA[Extent of reaction]]></category>
		<category><![CDATA[Heterogeneous equilibrium]]></category>
		<category><![CDATA[Heterogeneous reaction]]></category>
		<category><![CDATA[Homogeneous equilibrium]]></category>
		<category><![CDATA[Homogeneous reaction]]></category>
		<category><![CDATA[Irreversible reaction]]></category>
		<category><![CDATA[Law of chemical equilibrium]]></category>
		<category><![CDATA[Law of mass action]]></category>
		<category><![CDATA[Partial pressure]]></category>
		<category><![CDATA[Physical equilibrium]]></category>
		<category><![CDATA[Products]]></category>
		<category><![CDATA[Rate of chemical reaction]]></category>
		<category><![CDATA[Reactants]]></category>
		<category><![CDATA[Reversible reaction]]></category>
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					<description><![CDATA[<p>Science &#62; Chemistry &#62; Chemical Equilibrium &#62; Equilibrium Constant Characteristics of Equilibrium Constant: It has a definite value for every chemical reaction at a particular temperature. It is independent of the initial concentrations of the reacting species. It changes with the change in the temperature. It depends on the nature of the reaction. It is [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/equilibrium-constant/11136/">Equilibrium Constant</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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<h4 class="wp-block-heading"><strong>Science &gt; <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/" target="_blank">Chemistry</a> &gt; <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/chemical-equilibrium/" target="_blank">Chemical Equilibrium</a> &gt; Equilibrium Constant</strong></h4>



<p><strong>Characteristics of Equilibrium Constant:</strong></p>



<ul class="wp-block-list"><li>It has a definite value for every chemical reaction at a particular temperature.</li><li>It is independent of the initial concentrations of the reacting species.</li><li>It changes with the change in the temperature.</li><li>It depends on the nature of the reaction.</li><li>It is independent of the change of pressure, volume and concentrations of the reactants and products.</li><li>It is not affected by the introduction of the catalyst.</li><li>The expression for it may contain the concentrations of gases or molecules and ions in solution but not of pure solids or pure liquids.</li><li>The expression for it and its magnitude depends on the stoichiometric form of the balanced chemical equation.</li><li>When the equation for equilibrium is multiplied by a factor, then the equilibrium constant must be raised to the power equal to the factor.</li></ul>



<p class="has-text-align-center">If K<sub>c</sub> is equilibrium constant for reaction&nbsp;aA + bB&nbsp;<strong>⇌</strong>&nbsp; cC + dD</p>



<p class="has-text-align-center">Then its value for reaction naA + nbB&nbsp;<strong>⇌</strong>&nbsp; ncC + ndD is given by</p>



<p class="has-text-align-center">K&#8217;<sub>c</sub>&nbsp;= (K<sub>c</sub>)<sup>n</sup></p>



<ul class="wp-block-list"><li>When the addition of two equilibria leads to another equilibrium then the product of their equilibrium constants gives the value of K<sub>C</sub> of the resultant equilibrium.</li></ul>



<p class="has-text-align-center">K<sub>(resultant)</sub> = K<sub>(Reaction 1)&nbsp;&nbsp;</sub>x K<sub>(Reaction 2)</sub></p>



<ul class="wp-block-list"><li>If K<sub>1</sub>, k<sub>2</sub>, K<sub>3</sub>, &#8230;. are equilibrium constant for recation<sub>1</sub>, reaction<sub>2</sub>, reaction<sub>3</sub>, &#8230;&#8230;. Then the value of K<sub>C</sub> for reaction, a x recation<sub>1</sub>+ b x reaction<sub>2</sub>, c x reaction<sub>3</sub>, &#8230;&#8230;.&nbsp;is given by</li></ul>



<p class="has-text-align-center">K<sub>C</sub> = (K<sub>1</sub>)<sup>a</sup>(K<sub>2</sub>)<sup>b</sup>(K<sub>3</sub>)<sup>c</sup>&#8230;&#8230;..</p>



<ul class="wp-block-list"><li>For a reversible reaction, the value of K<sub>C</sub> for the backward reaction is inverse of the equilibrium constant for the forward reaction</li></ul>



<p class="has-text-align-center">K<sub>(backward)</sub> = 1 / K<sub>(forward)</sub></p>



<ul class="wp-block-list"><li>If it is expressed in terms of concentration, it has different units for different reactions.</li></ul>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>K<sub>C</sub> is Dimensionless Unitless Quantity:</strong></p>



<p>Depending upon the stoichiometric coefficients of a chemical reaction, the equilibrium constant should have a unit. Its unit should be </p>



<p class="has-text-align-center">(mol dm<sup>-3</sup>)<sup>(∑n products &#8211;&nbsp;∑n reactants)</sup></p>



<p>Note that 1 dm<sup>3</sup> = 1 L. Hence concentration can be expressed as (mol L<sup>-1</sup>)</p>



<p>These days we specify equilibrium constant in terms of dimensionless quantities by specifying the standard state of reactants and products. The standard state pressure for pure gas is 1 bar and the partial pressures of the gases are measured with respect to this standard state.</p>



<p>If a gas has a partial pressure of 1.5 bar, then in terms of standard state its pressure would be equal to 1.5 bar/1bar = 1.5, a dimensionless number. Similarly, for concentrations, the standard state is 1 M ( 1mol dm<sup>-3</sup>). If the concentration of the substance is 2.0 M. Then in terms of standard state it will be expressed as 2.0 M/1 M = 2. Thus using partial pressures and concentrations K<sub>P</sub> and K<sub>C</sub> obtained are dimensionless. Hence equilibrium constant is considered as dimensionless, unitless quantity.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>K<sub>C</sub> of a General Reaction and its Multiple:</strong></p>



<p>Consider a hypothetical reversible reaction</p>



<p class="has-text-align-center">aA + bB&nbsp;<strong>⇌</strong>&nbsp; cC + dD</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-45.png" alt="" class="wp-image-11141" width="96" height="50"/></figure></div>



<p class="has-text-align-center">The equilibrium constant of the reaction given by</p>



<p class="has-text-align-center">Consider a multiple of above reaction</p>



<p class="has-text-align-center">naA + nbB&nbsp;<strong>⇌</strong>&nbsp; ncC + ndD</p>



<p class="has-text-align-center">The equilibrium constant of the reaction given by</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-46.png" alt="" class="wp-image-11143" width="227" height="93"/></figure></div>



<p>Thus when the equation for an equilibrium is multiplied by a factor, then the equilibrium constant must be raised to the power equal to the factor.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong><strong>K<sub>C</sub></strong> for the addition of Two Chemical Equilibria:</strong></p>



<p>Consider following equilibria</p>



<p>1) N<sub>2(g)</sub> +&nbsp; &nbsp;O<sub>2(g)</sub> &nbsp;⇌&nbsp; &nbsp; &nbsp;2NO<sub>(g)</sub></p>



<p class="has-text-align-center">The equilibrium constant for the reaction is</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-47.png" alt="" class="wp-image-11145" width="227" height="50"/></figure></div>



<p>2)&nbsp; &nbsp;2NO<sub>(g)</sub> +&nbsp; &nbsp;O<sub>2(g)</sub> &nbsp;⇌&nbsp; &nbsp; &nbsp;2NO<sub>2(g)&nbsp;</sub></p>



<p class="has-text-align-center">The equilibrium constant for the reaction is</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-48.png" alt="" class="wp-image-11147" width="227" height="51"/></figure></div>



<p>3)&nbsp; N<sub>2(g)</sub> +&nbsp; 2O<sub>2(g)</sub> &nbsp; ⇌&nbsp; &nbsp;2NO<sub>2(g)</sub></p>



<p class="has-text-align-center">The equilibrium constant for the reaction is</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-49.png" alt="" class="wp-image-11149" width="231" height="50"/></figure></div>



<p class="has-text-align-center">Multiplying equation (1) by (2) we get</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-50.png" alt="" class="wp-image-11151" width="227" height="121"/></figure></div>



<p>Thus When the addition of two equilibria leads to another equilibrium then the product of their equilibrium constants gives the equilibrium constant of the resultant equilibrium.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Temperature Dependence of Equilibrium&nbsp;Constant:</strong></p>



<p>At chemical equilibrium, the rate of the forward reaction is equal to the rate of backward reaction. When the temperature is increased, in general, the rate of both the forward reaction and the backward reaction increases. As the energy of activation of the&nbsp;forward reaction and the backward reaction are different, the extent of the increase of the&nbsp;forward reaction and the backward reaction is different. Thus the value of K<sub>f</sub> (rate constant for the&nbsp;forward reaction) and K<sub>b</sub> (rate constant for the backward reaction) changes to a different extent. Thus the ratio K<sub>f</sub> / K<sub>b</sub> changes. i.e. the value of equilibrium constant changes with the change in temperature.</p>



<p>The value of the equilibrium constant for endothermic reaction increases with an increase in temperature, while the value of the equilibrium constant for exothermic reaction decreases with an increase in temperature. The temperature dependence of equilibrium constant can be written mathematically as</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-51.png" alt="" class="wp-image-11153" width="210" height="43"/></figure></div>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Uses of K<sub>C</sub>:</strong></p>



<h4 class="wp-block-heading"><strong>It helps in the prediction of the extent of reaction:</strong></h4>



<p>The magnitude of the K<sub>C</sub> tells us about the extent in which the reactants are converted into the products before the equilibrium is attained. Larger values of K indicates that the extent of reactants converting into products is greater. The generalization is</p>



<ul class="wp-block-list"><li>If K<sub>C</sub> &gt; 10<sup>3</sup> Products predominates the reactants. i.e. the concentration of products is very high compared to that of reactants t equilibrium and the reaction proceeds nearly to completion</li><li>If K<sub>C</sub> &lt; 10<sup>-3</sup> Reactants predominates the products. i.e. the concentration of products is very less compared to that of reactants t equilibrium and the reaction hardly proceeds.</li><li>10<sup>-3</sup> &lt; K<sub>C</sub> &lt; 10<sup>-3</sup>&nbsp;, appreciable concentrations of both the reactants and products are present at equilibrium</li></ul>



<div class="wp-block-image"><figure class="aligncenter size-large"><img loading="lazy" decoding="async" width="300" height="72" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-52.png" alt="" class="wp-image-11155"/></figure></div>



<p>It gives us an idea of relative stabilities of reactants and products:</p>



<p>If the K<sub>C</sub> is large products are more stable than the reactants. Whereas, If the value of the equilibrium constant is small reactants are more stable than the products.&nbsp; The generalisation is</p>



<p>If K<sub>C</sub> &gt; 10<sup>3</sup> Products are stable than reactants.</p>



<p>If K<sub>C</sub> &lt; 10<sup>-3</sup> Reactants are stable than products.</p>



<h4 class="wp-block-heading"><strong>It helps in the prediction of the direction of a net reaction.</strong></h4>



<p>The value of K<sub>C</sub> helps in the prediction of the direction in which the net reaction is proceeding at given concentrations or partial pressures of reactants and products. If Q<sub>c</sub> is the concentration quotient and K<sub>c</sub> be the equilibrium constant of a chemical reaction.</p>



<p class="has-text-align-center">For reaction aA + bB&nbsp;<strong>⇌</strong>&nbsp; cC + dD</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-53.png" alt="" class="wp-image-11157" width="106" height="50"/></figure></div>



<p class="has-text-align-center">When computing Q<sub>C</sub> the concentration at that instant are used</p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><img loading="lazy" decoding="async" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-45.png" alt="" class="wp-image-11141" width="109" height="57"/></figure></div>



<p class="has-text-align-center">When computing K<sub>C</sub> the concentration at equilibrium are used. The generalization is</p>



<ul class="wp-block-list"><li>If Q<sub>C</sub> &gt; K<sub>C</sub> , the reaction is taking place in a backward direction i.e. in the direction of reactants</li><li>If Q<sub>C</sub> &lt; &nbsp;K<sub>C</sub> , the reaction is taking place in a forward direction i.e. in the direction of products.</li><li>If Q<sub>C</sub> = &nbsp;K<sub>C</sub> The reaction is in the equilibrium state and hence no net reaction is taking place.</li></ul>



<h4 class="wp-block-heading"><strong>It helps in the calculation of equilibrium constants and equilibrium pressures.&nbsp;</strong></h4>



<p>If the equilibrium concentrations of various reactants and products are known for a reaction, the equilibrium constant can be calculated. On the other hand, if the equilibrium constant is known, the equilibrium concentrations can be calculated.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Steps Involved in the Calculation of K<sub>C</sub> and Equilibrium Pressures:</strong></p>



<ol class="wp-block-list" type="1"><li>Write the chemical equation for the equilibrium</li><li>Write expression for K<sub>C</sub> or K<sub>P</sub> for the reaction.</li><li>Express all unknown concentrations or partial pressures in terms of a single variable x.</li><li>Substitute equilibrium concentrations or partial pressures in terms of x in the expression for K<sub>C</sub> or K<sub>P</sub>.</li><li>Solve the equation for x</li><li>Substitute the value obtained for x in the expression in step 3 to calculate equilibrium concentrations or equilibrium partial pressures</li></ol>



<h4 class="wp-block-heading"><strong>Science &gt; <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/" target="_blank">Chemistry</a> &gt; <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/chemical-equilibrium/" target="_blank">Chemical Equilibrium</a> &gt; Equilibrium Constant</strong></h4>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/equilibrium-constant/11136/">Equilibrium Constant</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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