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		<title>Applications of Le-Chatelier&#8217;s Principle</title>
		<link>https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/application-of-lechateliars-principle/11168/</link>
					<comments>https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/application-of-lechateliars-principle/11168/#comments</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Thu, 02 Apr 2020 15:02:20 +0000</pubDate>
				<category><![CDATA[Physical Chemistry]]></category>
		<category><![CDATA[Chemical equilibrium]]></category>
		<category><![CDATA[Chemical reaction]]></category>
		<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Contact process]]></category>
		<category><![CDATA[Endothermic reaction]]></category>
		<category><![CDATA[Equilibrium]]></category>
		<category><![CDATA[Equilibrium constant.]]></category>
		<category><![CDATA[Exothermic reaction]]></category>
		<category><![CDATA[Haber's process]]></category>
		<category><![CDATA[Heterogeneous reaction]]></category>
		<category><![CDATA[Homogeneous reaction]]></category>
		<category><![CDATA[Irreversible reaction]]></category>
		<category><![CDATA[Le-Chatelier's principle]]></category>
		<category><![CDATA[Manufacturing of ammonia]]></category>
		<category><![CDATA[Manufacturing of nitric oxide]]></category>
		<category><![CDATA[Manufacturing of ozone]]></category>
		<category><![CDATA[Manufacturing of sulphur trioxide]]></category>
		<category><![CDATA[Physical equilibrium]]></category>
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		<category><![CDATA[Reactants]]></category>
		<category><![CDATA[Reversible reaction]]></category>
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					<description><![CDATA[<p>Science > Chemistry > Chemical Equilibrium > Applications of Le-Chatelier&#8217;s Principle In this article we shall study the application of Le-Chatelier&#8217;s principle in Haber&#8217;s process, contact proces, etc. Statement of Le-Chatelier’s Principle: This principle is given by, a French chemist Le-Chatelier in 1888. It states that &#8220;If an external stress is applied to a reacting [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/application-of-lechateliars-principle/11168/">Applications of Le-Chatelier&#8217;s Principle</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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<h4 class="wp-block-heading"><strong>Science > <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/" target="_blank">Chemistry</a> > <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/chemical-equilibrium/" target="_blank">Chemical Equilibrium</a> > Applications of Le-Chatelier&#8217;s Principle</strong></h4>



<p>In this article we shall study the application of Le-Chatelier&#8217;s principle in Haber&#8217;s process, contact proces, etc.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Statement of Le-Chatelier’s Principle:</strong></p>



<p>This principle is given by, a French chemist Le-Chatelier in 1888. It states that &#8220;If an external stress is applied to a reacting system at equilibrium, the system will adjust itself in such a way that the effect of the stress is nullified&#8221;.</p>



<div class="wp-block-image"><figure class="aligncenter size-large"><img fetchpriority="high" decoding="async" width="191" height="263" src="https://thefactfactor.com/wp-content/uploads/2020/04/Le-Chatelier.png" alt="Application of Le-Chatelier’s Principle" class="wp-image-11169"/></figure></div>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Application of&nbsp;Le-Chatelier’s Principle to&nbsp;Haber’s process (Synthesis of Ammonia):</strong></p>



<p>Ammonia is manufactured by using Haber’s process. In this reaction Nitrogen and Hydrogen in ratio 1:3 by volume are made to react at 773 K and 200 atm. Pressure.</p>



<p class="has-text-align-center">The chemical reaction is</p>



<p class="has-text-align-center">N<sub>2(g)</sub> &nbsp;+&nbsp;&nbsp; 3H<sub>2(g)</sub> &nbsp; ⇌&nbsp; &nbsp;2 NH<sub>3(g)&nbsp;&nbsp;</sub>+ 96.3 kJ</p>



<p class="has-text-align-center">1 Vol&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp; 3 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2 Vol</p>



<p class="has-text-align-center">4 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2 Vol</p>



<p>From this reaction it is clear that, the reaction is exothermic and accompanied by the decrease in volume.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Concentration:</strong></p>



<p>By the law of mass action; the increase in concentration of one of the reactant will shift equilibrium towards right.&nbsp; And here increase in concentration of hydrogen (as more moles of it are used) in preference to Nitrogen has more effect.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Pressure:</strong></p>



<p>Above reaction indicate that formation of ammonia takes place with decrease in volume.&nbsp; Hence increase in pressure will favour forward reaction. Optimum pressure for maximum yield of ammonia is about 200 atm.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Temperature:</strong></p>



<p>The reaction is exothermic, so lowering the temperature will favour forward reaction. But decrease in temperature results in the decrease in the rate of reaction. Hence temperature of 773K is maintained and iron is used as catalyst.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Application of&nbsp;Le-Chatelier’s Principle to&nbsp;Contact process (Synthesis of Sulphur Trioxide):</strong></p>



<p>H<sub>2</sub>SO<sub>4</sub> is manufactured by contact process. In this reaction SO<sub>2</sub> is oxidized to SO<sub>3</sub>. Sulphur trioxide is further used for manufacturing of sulphuric acid.</p>



<p class="has-text-align-center">2SO<sub>2(g)</sub> + O<sub>2(g)</sub> &nbsp; ⇌ &nbsp; 2 SO<sub>3(g)</sub> +&nbsp; 189 kJ</p>



<p class="has-text-align-center">2 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;1 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2 Vol</p>



<p>From this reaction it is clear that, the reaction is exothermic and accompanied by the decrease in volume.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Concentration:</strong></p>



<p>By the law of mass action; increase in concentration of one of the reactant will shift equilibrium towards right.&nbsp; And here increase in concentration of sulphur dioxide in preference to oxygen has more effect.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Pressure:</strong></p>



<p>Above reaction indicate that formation of sulphur trioxide takes place with decrease in volume.&nbsp; Hence increase in pressure will favour forward reaction. Optimum pressure for maximum yield of sulphur trioxide is about 1.5 atm to 1.7 atm</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Temperature:</strong></p>



<p>The reaction is exothermic, so lowering the temperature will favour forward reaction. But decrease in temperature results in the decrease in the rate of reaction. Hence temperature of 723 K is maintained and vanadium pentoxide is used as catalyst.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Application of&nbsp;Le-Chatelier’s Principle to&nbsp;&nbsp;Manufacture of Ozone:</strong></p>



<p>Ozone is manufactured by passing silent electric discharge through pure oxygen.</p>



<p class="has-text-align-center">3O<sub>2(g)</sub> &nbsp; ⇌ &nbsp;2 O<sub>3(g)</sub> &#8211;&nbsp; 288.56 kJ</p>



<p class="has-text-align-center">3 Vol&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 2 Vol</p>



<p>From this reaction it is clear that, the reaction is endothermic and accompanied by the decrease in volume.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Concentration:</strong></p>



<p>By the law of mass action; increase in concentration of one of the reactant will shift equilibrium towards right.&nbsp; And here increase in concentration of oxygen increases the rate of forward reaction.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Pressure:</strong></p>



<p>Above reaction indicate that formation of ozone takes place with decrease in volume.&nbsp; Hence increase in pressure will favour forward reaction.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Temperature:</strong></p>



<p>The reaction is endothermic, so increasing the temperature will favour forward reaction. Due to increase in temperature heat will be absorbed by the reaction.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Application of&nbsp;Le-Chatelier’s Principle to&nbsp;&nbsp;Manufacture of Nitric oxide:</strong></p>



<p class="has-text-align-center">The reaction is</p>



<p class="has-text-align-center">N<sub>2(g)&nbsp;</sub>+&nbsp; O<sub>2(g)</sub> &nbsp; ⇌ &nbsp;2 NO<sub>(g)</sub> &#8211;&nbsp; 181 kJ</p>



<p class="has-text-align-center">1Vol&nbsp; + 1 Vol&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;→&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 2 Vol</p>



<p>From this reaction it is clear that, the reaction is endothermic and accompanied by no change in volume.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Concentration:</strong></p>



<p>By the law of mass action; increase in concentration of one of the reactant will shift equilibrium towards right.&nbsp; And here increase in concentration of nitrogen or oxygen increases the rate of forward reaction.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Pressure:</strong></p>



<p>Above reaction indicate that formation of nitric oxide takes place with no change in volume.&nbsp; Hence pressure has no effect on the equilibrium.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Temperature:</strong></p>



<p>The reaction is endothermic, so increasing the temperature will favour forward reaction. Due to increase in temperature heat will be absorbed by the reaction.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Application of&nbsp;Le-Chatelier’s Principle to&nbsp;Manufacture of Nitrogen dioxide:</strong></p>



<p class="has-text-align-center">The reaction is</p>



<p class="has-text-align-center">2NO<sub>(g)&nbsp;</sub>+&nbsp; O<sub>2(g)</sub> &nbsp; ⇌ &nbsp;2 NO<sub>2(g)</sub> +&nbsp; 116.4 kJ</p>



<p class="has-text-align-center">2Vol&nbsp; + 1 Vol&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;→&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 2 Vol</p>



<p>From this reaction it is clear that, the reaction is exothermic and accompanied by decrease in volume.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Concentration:</strong></p>



<p>By the law of mass action; increase in concentration of one of the reactant will shift equilibrium towards right.&nbsp; And here increase in concentration of nitrogen or oxygen increases the rate of forward reaction. Due to use of more number of moles, the increase in concentration of nitrogen oxide has a prominent effect.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Pressure:</strong></p>



<p>Above reaction indicate that formation of nitrogen dioxide takes place with decrease in volume.&nbsp; Hence increase in pressure favour forward reaction.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Temperature:</strong></p>



<p>The reaction is exothermic, so decreasing the temperature will favour forward reaction. Due to the decrease in temperature heat will be removed from the reaction.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Application of&nbsp;Le-Chatelier’s Principle to&nbsp;Dissociation of Phosphorous Pentachloride:</strong></p>



<p class="has-text-align-center">The reaction is</p>



<p class="has-text-align-center">PCL<sub>5(g)&nbsp; &nbsp;</sub>⇌ &nbsp;PCl<sub>3(g)</sub>&nbsp;&nbsp;+&nbsp; Cl<sub>2(g)</sub>&nbsp; &nbsp; &#8211;&nbsp; 62.8kJ</p>



<p class="has-text-align-center">1Vol&nbsp; → 1 Vol&nbsp; &nbsp; &nbsp; +&nbsp; &nbsp; 1 Vol</p>



<p>From this reaction it is clear that, the reaction is endothermic and accompanied by increase in volume.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Concentration:</strong></p>



<p>By the law of mass action; increase in concentration of one of the reactant will shift equilibrium towards right.&nbsp; And here increase in concentration of phosphorous pentachloride increases the rate of forward reaction.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Pressure:</strong></p>



<p>Above reaction indicate that formation of nitrogen dioxide takes place with increase in volume.&nbsp; Hence decrease in pressure favour forward reaction.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of temperature:</strong></p>



<p>The reaction is endothermic, so increasing the temperature will favour forward reaction. Due to the increase in temperature heat will be absorbed by the reaction.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Applications of&nbsp;Le-Chatelier’s Principle to Physical Equilibria:</strong></p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Melting of Ice:</strong></p>



<p class="has-text-align-center">The reaction is</p>



<p class="has-text-align-center"><sub>Ice(s)&nbsp; &nbsp;</sub>⇌&nbsp; Water<sub>(l)</sub>&nbsp;&nbsp;&nbsp; &nbsp;&#8211;&nbsp; 6.01 kJ</p>



<p class="has-text-align-center">more vol&nbsp; → less vol</p>



<p>From this reaction, it is clear that the reaction is endothermic and accompanied by decrease in volume.</p>



<h4 class="wp-block-heading"><strong>Effect of Pressure:</strong></h4>



<p>Above reaction indicate that formation of liquid water takes place with decrease in volume.&nbsp; Hence increase in pressure favour forward reaction.</p>



<h4 class="wp-block-heading"><strong>Effect of Temperature:</strong></h4>



<p>The reaction is endothermic, so increasing the temperature will favour forward reaction. Due to the increase in temperature heat will be absorbed by the reaction.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Boiling of Water:</strong></p>



<p class="has-text-align-center">The reaction is</p>



<p class="has-text-align-center"><sub>Water(l)&nbsp; &nbsp;</sub>⇌&nbsp; Water vapours<sub>(g)</sub>&nbsp;&nbsp;&nbsp; &nbsp;&#8211;&nbsp; 40.84 kJ</p>



<p class="has-text-align-center">less vol&nbsp; → more vol</p>



<p>From this reaction, it is clear that the reaction is endothermic and accompanied by increase in volume.</p>



<h4 class="wp-block-heading"><strong>Effect of Pressure:</strong></h4>



<p>Above reaction indicate that formation of liquid water takes place with increase in volume.&nbsp; Hence increase in pressure favour forward reaction. (Principle of pressure cooker).</p>



<h4 class="wp-block-heading"><strong>Effect of Temperature:</strong></h4>



<p>The reaction is endothermic, so increasing the temperature will favour forward reaction. Due to the increase in temperature heat will be absorbed by the reaction.</p>



<h4 class="wp-block-heading"><strong>Science > <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/" target="_blank">Chemistry</a> > <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/chemical-equilibrium/" target="_blank">Chemical Equilibrium</a> > Applications of Le-Chatelier&#8217;s Principle</strong></h4>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/application-of-lechateliars-principle/11168/">Applications of Le-Chatelier&#8217;s Principle</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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		<title>Le-Chatelier&#8217;s Principle</title>
		<link>https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/le-chateliers-principle/11161/</link>
					<comments>https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/le-chateliers-principle/11161/#respond</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Thu, 02 Apr 2020 14:32:02 +0000</pubDate>
				<category><![CDATA[Physical Chemistry]]></category>
		<category><![CDATA[Chemical equilibrium]]></category>
		<category><![CDATA[Chemical reaction]]></category>
		<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Endothermic reaction]]></category>
		<category><![CDATA[Equilibrium]]></category>
		<category><![CDATA[Equilibrium constant.]]></category>
		<category><![CDATA[Exothermic reaction]]></category>
		<category><![CDATA[Heterogeneous reaction]]></category>
		<category><![CDATA[Homogeneous reaction]]></category>
		<category><![CDATA[Irreversible reaction]]></category>
		<category><![CDATA[Le-Chatelier's principle]]></category>
		<category><![CDATA[Physical equilibrium]]></category>
		<category><![CDATA[Products]]></category>
		<category><![CDATA[Reactants]]></category>
		<category><![CDATA[Reversible reaction]]></category>
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					<description><![CDATA[<p>Science &#62; Chemistry &#62; Chemical Equilibrium &#62; Le-Chatelier&#8217;s Principle In this article, we shall study Le-Chatelier&#8217;s principle with examples. Statement: This principle is given by, a French chemist Le-Chatelier in 1888. It states that &#8220;If an external stress is applied to a reacting system at equilibrium, the system will adjust itself in such a way [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/le-chateliers-principle/11161/">Le-Chatelier&#8217;s Principle</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
]]></description>
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<h4 class="wp-block-heading"><strong>Science &gt; <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/" target="_blank">Chemistry</a> &gt; <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/chemical-equilibrium/" target="_blank">Chemical Equilibrium</a> &gt; Le-Chatelier&#8217;s Principle</strong></h4>



<p>In this article, we shall study Le-Chatelier&#8217;s principle with examples.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Statement:</strong></p>



<p>This principle is given by, a French chemist Le-Chatelier in 1888. It states that &#8220;If an external stress is applied to a reacting system at equilibrium, the system will adjust itself in such a way that the effect of the stress is nullified&#8221;.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Explanation:</strong></p>



<p class="has-text-align-center">Let us consider a general reversible reaction.</p>



<p class="has-text-align-center">A&nbsp; +&nbsp; B&nbsp;&nbsp;⇌ &nbsp; C + D</p>



<p class="has-text-align-center">The equilibrium constant for the reaction is given by</p>



<div class="wp-block-image"><figure class="aligncenter size-large"><img decoding="async" width="88" height="51" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-54.png" alt="" class="wp-image-11163"/></figure></div>



<p>If the concentration of any one reactant say A is increased then by Le-Chatelier’s Principle the forward reaction should be favoured so that the increase in the concentration of A is nullified. It can be explained as follows.&nbsp;As the concentration of reactant, A increases the denominator of mass equation increases. To keep the value of the equilibrium constant the same the value of K<sub>c</sub> constant the numerator should increase. This is possible only if the concentration of C and D is increased. It is possible if more and more C and D are formed thus the reaction proceeds in the forward direction. i.e. forward reaction is favoured.</p>



<p>If the concentration of any one product, say C is increased then by Le-Chatelier’s Principle the backward reaction should be favoured so that the increase in the concentration of C is nullified. It can be explained as follows. As the concentration of product C increases the numerator of mass equation increases. To keep the value of K<sub>c</sub>, the denominator should increase. This is possible only if the concentration of A and B is increased. It is possible if more and more A and B are formed thus the reaction proceeds in the backward direction. i.e. backward reaction is favoured.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Effect of the Change of Concentration on the chemical Equilibrium:</strong></p>



<p>According to Le-Chatelier’s principle, when the concentration of one of the substance in a system in equilibrium is increased, then the equilibrium will shift so as to use up the substance added.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Explanation Using Le-Chatelier’s Principle:</strong></p>



<p class="has-text-align-center">Let us consider a general reversible reaction.</p>



<p class="has-text-align-center">A&nbsp; +&nbsp; B&nbsp; &nbsp;⇌ &nbsp; C + D</p>



<p class="has-text-align-center">The equilibrium constant for the reaction is given by</p>



<div class="wp-block-image"><figure class="aligncenter size-large"><img decoding="async" width="88" height="51" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-54.png" alt="" class="wp-image-11163"/></figure></div>



<p>If the concentration of any one reactant say A is increased then by Le-Chatelier’s Principle the forward reaction should be favoured so that the increase in the concentration of A is nullified. It can be explained as follows.&nbsp;As the concentration of reactant, A increases the denominator of mass equation increases. To keep the value of the equilibrium constant the same the value of K<sub>c</sub> constant the numerator should increase. This is possible only if the concentration of C and D is increased. It is possible if more and more C and D are formed thus the reaction proceeds in the forward direction. i.e. forward reaction is favoured.</p>



<p>If the concentration of any one product say C is increased then by Le-Chatelier’s Principle the backward reaction should be favoured so that the increase in the concentration of C is nullified. It can be explained as follows. As the concentration of product C increases the numerator of mass equation increases. To keep the value of K<sub>c</sub>, the denominator should increase. This is possible only if the concentration of A and B is increased. It is possible if more and more A and B are formed thus the reaction proceeds in the backward direction. i.e. backward reaction is favoured.</p>



<p>The following graph shows the variation in concentration of the species on increasing the concentration of hydrogen in a reaction to produce ammonia from nitrogen and hydrogen.</p>



<div class="wp-block-image"><figure class="aligncenter size-large"><img decoding="async" width="264" height="300" src="https://thefactfactor.com/wp-content/uploads/2020/04/Chemical-Equilibrium-55.png" alt="" class="wp-image-11164"/></figure></div>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Everyday Life Examples to Explain the Effect of the Change of Concentration on the Equilibrium:</strong></p>



<h4 class="wp-block-heading">Clothes dry quicker when there is a breeze.</h4>



<p>Due to breeze or by shaking clothes in the air, the water vapours in the nearby air are removed or carried away. To establish the equilibrium the water from wet clothes starts evaporating. Thus they get dried fast.</p>



<h4 class="wp-block-heading">On a humid day, we sweat more</h4>



<p>Our body is losing water continuously by forming sweat. On a normal day, this sweat gets evaporated as soon as it is formed on the surface of the body. On a humid day the surrounding air contains a large amount of water vapours. Hence our body cannot lose water in the form of vapours. Thus the water remains on our body as sweat.</p>



<h4 class="wp-block-heading">Transfer of oxygen by haemoglobin in the blood.</h4>



<p>Haemoglobin is a protein present in red blood corpuscles which act as an oxygen carrier. The equilibrium is represented as</p>



<p class="has-text-align-center">Hb<sub>(s)</sub> +&nbsp; O<sub>2(g)</sub> &nbsp;⇌&nbsp;&nbsp;&nbsp; HbO<sub>2(s)</sub></p>



<p>In lungs, there is an equilibrium of this reaction, when&nbsp; HbO<sub>2</sub> (oxyhaemoglobin) reaches the site of tissues where the partial pressure is low. Now the equilibrium adjusts itself by shifting towards the right by releasing oxygen from oxyhaemoglobin. When the blood returns back to the lungs, where the partial pressure is higher, more oxyhaemoglobin is formed.</p>



<h4 class="wp-block-heading">Removal of CO<sub>2</sub> from tissues</h4>



<p>At the site of the tissues, the partial pressure of carbon dioxide is high. It dissolves into the blood and carried to lungs. In lungs partial pressure of carbon dioxide is low and it gets released from the blood.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Effect of the Pressure on the Chemical Equilibrium:</strong></p>



<p>Change in pressure plays an important role in gaseous reactions.&nbsp; The change of pressure has effect only on those equilibria which involves gaseous substances. There can be three types of gaseous reactions:</p>



<ul class="wp-block-list"><li>Chemical reactions accompanied by an increase in volume</li><li>Chemical reactions accompanied by a decrease in volume.</li><li>Chemical reactions accompanied by no change in volume.</li></ul>



<p>By Le-Chatelier&#8217;s principle, at a constant temperature, increase in pressure will favour a reaction which is accompanied by a decrease in volume and decrease in pressure will favour a reaction which is accompanied by the increase in volume.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Chemical reactions accompanied by an increase in volume:</strong></p>



<p class="has-text-align-center">Consider following reaction.</p>



<p class="has-text-align-center">PCl<sub>5(g)</sub> &nbsp;⇌ PCl<sub>3(g)</sub> &nbsp; +&nbsp;&nbsp;&nbsp; Cl<sub>2(g)</sub></p>



<p class="has-text-align-center">1 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;1 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;1 Vol</p>



<p class="has-text-align-center">1 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;2 Vol</p>



<p>In this reaction, 1 volume of reactants gives 2 volumes of products.&nbsp; Thus in this reaction volume is increased.</p>



<p>Chemical reactions involving gases and accompanied by an increase in volume are favoured by a reduction in pressure. Thus by decreasing the pressure at equilibrium, equilibrium is shifted towards the right.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Chemical reactions accompanied by a decrease in volume:</strong></p>



<p class="has-text-align-center">Consider following reaction.</p>



<p class="has-text-align-center">N<sub>2(g)</sub> &nbsp;+&nbsp;&nbsp; 3H<sub>2(g)</sub> &nbsp; ⇌&nbsp; &nbsp;2 NH<sub>3(g)</sub></p>



<p class="has-text-align-center">1 Vol&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp; 3 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2 Vol</p>



<p class="has-text-align-center">4 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2 Vol</p>



<p>In this reaction, 4 volumes of reactants give 2 volumes of products.&nbsp; Thus in this reaction volume is decreased.</p>



<p>Chemical reactions involving gases and accompanied by a decrease in the volume are favoured by an increase in pressure. Thus by increasing the pressure at equilibrium, equilibrium is shifted towards the right.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Chemical reactions accompanied by no change in volume:</strong></p>



<p class="has-text-align-center">Consider following reaction.</p>



<p class="has-text-align-center">H<sub>2(g)</sub> &nbsp; &nbsp;+&nbsp;&nbsp; I<sub>2(g)</sub> ⇌ &nbsp; 2 HI<sub>(g)</sub></p>



<p class="has-text-align-center">1 Vol&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp; 1 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2 Vol</p>



<p class="has-text-align-center">2 Vol&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 2 Vol</p>



<p>In this reaction, 2 volumes of reactants give 2 volumes of products.&nbsp; Thus in this reaction volume is not changed.</p>



<p>Chemical reactions involving gases and accompanied by no change in volume are not affected by the change in pressure.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Effect of Temperature on the Chemical Equilibrium:</strong></p>



<p>If the temperature of the exothermic chemical reaction is increased,&nbsp;then the concentration of products reduces and thus the equilibrium is shifted towards left.&nbsp; Hence the reduction in temperature favours exothermic reaction at equilibrium. and increase in temperature favours endothermic reaction.</p>



<p>It is to be noted that in a reversible reaction if one reaction is exothermic then another reaction is endothermic. Thus the effect of change of temperature on the two reactions is different.</p>



<p>By Le-Chatelier&#8217;s principle. for an exothermic reaction at equilibrium lowering of temperature will favour the forward reaction And for an endothermic reaction, an increase in temperature will favour the forward reaction.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of the Catalyst on the Chemical Equilibrium:</strong></p>



<p>The catalyst is a substance which increases or decreases the rate of a reaction without taking part in the chemical reaction. In a reversible reaction at equilibrium, catalyst affects the rate of both forward reaction and backward reaction by the same extent.&nbsp;&nbsp;&nbsp; Hence catalyst at equilibrium does not affect chemical equilibrium.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of Inert Gas Addition:</strong></p>



<p>If the volume is kept constant and an inert gas such as argon is added which does not take part in the reaction, the equilibrium remains undisturbed. It is due to the fact that the addition of an inert gas at constant volume does not change the partial pressure or the molar concentration of substances involved in the reaction. The change will take place if and only if the added gas is a reactant or product involved in the reaction.</p>



<h4 class="wp-block-heading"><strong>Science &gt; <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/" target="_blank">Chemistry</a> &gt; <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/chemical-equilibrium/" target="_blank">Chemical Equilibrium</a> &gt; Le-Chatelier&#8217;s Principle</strong></h4>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/le-chateliers-principle/11161/">Le-Chatelier&#8217;s Principle</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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