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		<title>Solubility Product</title>
		<link>https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/solubility-product/9080/</link>
					<comments>https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/solubility-product/9080/#respond</comments>
		
		<dc:creator><![CDATA[Hemant More]]></dc:creator>
		<pubDate>Thu, 27 Feb 2020 07:37:54 +0000</pubDate>
				<category><![CDATA[Physical Chemistry]]></category>
		<category><![CDATA[Acid]]></category>
		<category><![CDATA[Acidic nature]]></category>
		<category><![CDATA[Arrhenius theory]]></category>
		<category><![CDATA[Base]]></category>
		<category><![CDATA[Basic nature]]></category>
		<category><![CDATA[Degree of dissociation]]></category>
		<category><![CDATA[Dissociation]]></category>
		<category><![CDATA[Dissociation constant]]></category>
		<category><![CDATA[Electrolytes]]></category>
		<category><![CDATA[Ionic equilibria]]></category>
		<category><![CDATA[Ionisation]]></category>
		<category><![CDATA[Ionization]]></category>
		<category><![CDATA[Ions]]></category>
		<category><![CDATA[Neutralization]]></category>
		<category><![CDATA[Non-electrolytes]]></category>
		<category><![CDATA[Precipitation]]></category>
		<category><![CDATA[Saturation]]></category>
		<category><![CDATA[Solubility]]></category>
		<category><![CDATA[Solubility product]]></category>
		<category><![CDATA[Sparingly soluble salt]]></category>
		<category><![CDATA[Strength of acid]]></category>
		<category><![CDATA[Strength of base]]></category>
		<category><![CDATA[Strong acid]]></category>
		<category><![CDATA[Strong base]]></category>
		<category><![CDATA[Strong electrolytes]]></category>
		<category><![CDATA[Unsaturation]]></category>
		<category><![CDATA[Weak acid]]></category>
		<category><![CDATA[Weak base]]></category>
		<category><![CDATA[Weak electrolytes]]></category>
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					<description><![CDATA[<p>Science > Chemistry > Physical Chemistry > Ionic Equilibria > Solubility Product In this article, we shall study the concept of solubility, solubility product, and its applications. Some ionic solids are highly soluble in water while others are almost insoluble in it. The solubility of ionic solid depends on lattice enthalpy of the salt and [&#8230;]</p>
<p>The post <a href="https://thefactfactor.com/facts/pure_science/chemistry/physical-chemistry/solubility-product/9080/">Solubility Product</a> appeared first on <a href="https://thefactfactor.com">The Fact Factor</a>.</p>
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<h4 class="wp-block-heading"><strong>Science > <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/" target="_blank">Chemistry</a> > Physical Chemistry > <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/ionic-equilibria/" target="_blank">Ionic Equilibria</a> > Solubility Product</strong></h4>



<p>In this article, we shall study the concept of solubility, solubility product, and its applications.</p>



<p>Some ionic solids are highly soluble in water while others are almost insoluble in it. The solubility of ionic solid depends on lattice enthalpy of the salt and hydration enthalpy of ions in solution. The lattice enthalpy of salt is defined as the energy required to overcome the attractive forces between the ions. It is always positive. The hydration enthalpy or solvation enthalpy is the energy released during the interaction between the ions and solvent molecules. It is always negative. If salt is to be dissolved then its solvation enthalpy should be greater than its lattice enthalpy.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Solubility:</strong></p>



<p>The concentration of a substance in its saturated
solution is called as its solubility at a given temperature. It is denoted by
letter ‘S’ It is expressed as grams per litre or as moles per litre at a given
temperature.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Classification of Solids on the Basis of Solubility:</strong></p>



<ul class="wp-block-list"><li>The
solids having a solubility greater than 0.1 M are classified as soluble solids
e.g. NaCl, Sugar, etc.</li><li>The
solids having a solubility between 0.01 M and 0.1 M are classified as slightly
soluble solids e.g. calcium phosphate.</li><li>The
solids having a solubility less than&nbsp;0.01 M are classified as sparingly
soluble solids e.g. barium sulphate, silver chloride, etc.</li></ul>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Sparingly Soluble Salt:</strong></p>



<p>A certain substance like AgCl, PbSO<sub>4</sub>, BaSO<sub>4</sub> etc. have negligible solubility in water at ordinary tempera­ture.  Such substances which are practically insoluble in water are called as sparingly soluble electrolytes. The amount of such salts getting dissolved is so small that their saturated solution may be regarded as extremely dilute and hence dissolved part can be considered as completely ionized.</p>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>Solubility Product:</strong></p>



<p>In a saturated solution of a sparingly soluble elec­trolyte, the product of molar concentration of ions is constant at a given temperature. This constant ‘ K<sub>sp</sub> ’ is called a solubility product.</p>



<p><strong>Explanation:</strong></p>



<p>Suppose ‘BA’ is a sparingly soluble electrolyte.&nbsp;
In aqueous solution, it dissociates to a very little extent there exist two
equilibria.</p>



<p class="has-text-align-center">BA<sub>(s)</sub> →
BA<sub>(aq)</sub> ⇌ B<sup>+</sup><sub>(aq)</sub> + A<sup>&#8211;</sup><sub>(aq)</sub></p>



<p class="has-text-align-center">The mass law equation of the equilibrium is</p>



<div class="wp-block-image"><figure class="aligncenter size-large"><img decoding="async" width="118" height="50" src="https://thefactfactor.com/wp-content/uploads/2020/02/Solubility-Product-01.png" alt="https://hemantmore.org.in/wp-content/uploads/2018/03/Solubility-01.png" class="wp-image-9084"/></figure></div>



<p class="has-text-align-center">But [BA] = constant</p>



<p class="has-text-align-center">∴&nbsp;
K . constant = [B<sup>+</sup>][A<sup>&#8211;</sup>]</p>



<p class="has-text-align-center">∴&nbsp;
K<sub>sp</sub> = [B<sup>+</sup>][A<sup>&#8211;</sup>]</p>



<p>Where K<sub>sp</sub>
is solubility product. If ‘S’ moles/dm<sup>3</sup> is solubility of electrolyte
‘BA’ then [B<sup>+</sup>] = S and [A<sup>&#8211;</sup>] = S</p>



<p class="has-text-align-center">K<sub>sp</sub> =
[S] [S]</p>



<p class="has-text-align-center">K<sub>sp</sub> = S<sup>2</sup></p>



<figure class="wp-block-table aligncenter"><table class=""><tbody><tr><td class="has-text-align-center" data-align="center">
  Salt
  Type
  </td><td class="has-text-align-center" data-align="center">
  Relation
  with Ksp
  </td><td class="has-text-align-center" data-align="center">
  Examples
  of salt
  </td></tr><tr><td class="has-text-align-center" data-align="center">
  AB
  </td><td class="has-text-align-center" data-align="center">
  K<sub>sp</sub>
  = (s)(s) = s<sup>2</sup>
  </td><td class="has-text-align-center" data-align="center">
  AlPO<sub>4</sub>,
  AgCl, BaSO<sub>4</sub>, ZnS
  </td></tr><tr><td class="has-text-align-center" data-align="center">
  AB<sub>2</sub>
  </td><td class="has-text-align-center" data-align="center">
  K<sub>sp</sub>
  = (s)(2s)<sup>2</sup> = 4s<sup>3</sup>
  </td><td class="has-text-align-center" data-align="center">
  PbCl<sub>2</sub>,
  HgCl<sub>2</sub>
  </td></tr><tr><td class="has-text-align-center" data-align="center">
  A<sub>2</sub>B
  </td><td class="has-text-align-center" data-align="center">
  K<sub>sp</sub>
  = (s)<sup> 2</sup> (2s) = 4s<sup>3</sup>
  </td><td class="has-text-align-center" data-align="center">
  Ag<sub>2</sub>CrO<sub>4</sub>,
  Ag<sub>2</sub>C<sub>2</sub>O<sub>4</sub>, Ag<sub>2</sub>SO<sub>4</sub>
  </td></tr><tr><td class="has-text-align-center" data-align="center">
  AB<sub>3</sub>
  </td><td class="has-text-align-center" data-align="center">
  K<sub>sp</sub>
  = (s) (3s)<sup>3</sup> = 27s<sup>4</sup>
  </td><td class="has-text-align-center" data-align="center">
  Fe(OH)<sub>
  3</sub>, Al(OH)<sub> 3</sub>, Cr(OH)<sub> 3</sub>
  </td></tr><tr><td class="has-text-align-center" data-align="center">
  A<sub>3</sub>B<sub>2</sub>
  </td><td class="has-text-align-center" data-align="center">
  K<sub>sp</sub>
  = (3s)<sup> 3 </sup>(2s)<sup>2</sup> = 108 s<sup>5</sup>
  </td><td class="has-text-align-center" data-align="center">
  Ca<sub>3</sub>(PO<sub>4</sub>)2,
  Zn<sub>3</sub>(PO<sub>4</sub>)2
  </td></tr><tr><td class="has-text-align-center" data-align="center">
  A<sub>3</sub>B<sub>4</sub>
  </td><td class="has-text-align-center" data-align="center">
  K<sub>sp</sub>
  = (3s)<sup> 3 </sup>(2s)<sup>4</sup> = 6912 s<sup>7</sup>
  </td><td class="has-text-align-center" data-align="center">
  Zn<sub>3</sub>(PO<sub>4</sub>)<sub>
  4</sub>
  </td></tr><tr><td class="has-text-align-center" data-align="center">
  A<sub>x</sub>B<sub>y</sub>
  </td><td class="has-text-align-center" data-align="center">
  K<sub>sp</sub>
  = (xs)<sup> x </sup>(ys)<sup>y</sup> = x<sup>x</sup>y<sup>y</sup>
  s<sup>x+y</sup>
  </td><td class="has-text-align-center" data-align="center"></td></tr></tbody></table></figure>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Effect of pH on Solubility:</strong></p>



<p>The solubility of salt of weak acids increases in more
acidic solutions e.g. ZnS, CuS, NiS, etc. Marble (CaCO<sub>3</sub>) statues and
monuments corrode by the effect of acid rain.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>Saturation, Unsaturation and
Precipitation:</strong></p>



<ul class="wp-block-list"><li>In
a solution, when the ionic product is equal to the solubility product.&nbsp;
Then the solution is just saturated and precipitation doesn’t occur.</li><li>In
a solution, when the&nbsp;ionic product is less than the solubility product
then the solution is unsaturated and precipitation doesn’t occur.</li><li>In
a solution, when the ionic product exceeds the solubility product then the
solution is supersaturated and precipitation of electrolyte takes place.</li><li>Thus
precipitation is possible only when the ionic product is greater than the
solubility product.</li></ul>



<p class="has-text-color has-background has-medium-font-size has-luminous-vivid-orange-color has-very-light-gray-background-color"><strong>App</strong><strong>lications of Solubility Product:</strong></p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>In the precipitation of II group cations:</strong></p>



<p>Group II cations like Cu<sup>++</sup>, Cd<sup>++</sup>,
Pb<sup>++</sup> etc. are precipitated as their sulphides.</p>



<p>Precipitation is carried out by adding dil. HCI
followed by passage of H<sub>2</sub>S gas through the solution.&nbsp; Being
weak acid, H<sub>2</sub>S ionizes as,</p>



<p class="has-text-align-center">H<sub>2</sub>S<sub>(aq)</sub>
⇌&nbsp;
2 H<sup>+</sup> (aq.) + S<sup>&#8211;&nbsp;&#8211;</sup><sub>(aq)</sub></p>



<p class="has-text-align-center">HCI being strong
acid dissociate almost completely as,</p>



<p class="has-text-align-center">HCl<sub>(aq)</sub>
→ H<sup>+</sup><sub>(aq)</sub> &nbsp;+ Cl<sup>&#8211;</sup><sub>(aq)</sub></p>



<p>The concentration of&nbsp;H<sup>+</sup> is increased.
Since H<sup>+</sup> ions are common ions, due to common ion effect dissociation
of H<sub>2</sub>S is suppressed so that S<sup>&#8211;&nbsp;&#8211;</sup> ion concentration
is decreased to such an extent that only group II cations get precipitated.
Ionic product of sulphides of II group cations exceeds solubility product, so
only II group cations form a precipitate and other cations belonging to further
groups remain as it is in the solution.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>In the precipitation of III A group cations:</strong></p>



<p>III A group cations like AI<sup>3+</sup>, Fe<sup>3+</sup>,
Cr<sup>3+</sup>, etc. are precipitated as their hydroxides by adding NH<sub>4</sub>CI
followed by adding NH<sub>4</sub>OH.</p>



<p class="has-text-align-center">Being weak base NH<sub>4</sub>OH dissociate as</p>



<p class="has-text-align-center">NH<sub>4</sub>OH<sub>(aq)</sub>
⇌
NH<sub>4</sub><sup>+</sup><sub>(aq)</sub> + OH<sup>&#8211;</sup><sub>(aq)</sub></p>



<p class="has-text-align-center">Being strong
electrolyte NH<sub>4</sub>CI dissociate as,</p>



<p class="has-text-align-center">NH<sub>4</sub>Cl<sub>(aq)</sub>
⇌
NH<sub>4</sub><sup>+</sup><sub>(aq)</sub> + Cl<sup>&#8211;</sup><sub>(aq)</sub></p>



<p>Since NH<sub>4</sub><sup>+</sup> ions are common,
their concentration increases and due to common ion effect dissociation of NH<sub>4</sub>OH
is suppressed so that concen­tration of OH<sup>&#8211;</sup> ion decreases to such an
extent that only IIIA group cations are precipitated. Ionic product of
hydroxides of IIIA group cation exceeds solubility product while the ionic
product of hydroxides of IIIB group is lower than solubility product hence only
IIIA group cations are precipitated.</p>



<p class="has-text-color has-medium-font-size has-vivid-red-color"><strong>In Prediction of Precipitation:</strong></p>



<p>Solubility product is the highest limit of ionic
product at a particular temperature. When ionic product exceeds the solubility
product, excess ions combine with each other to form the precipitate of the
salt. Hence to find whether a precipitation can take place or not, ionic product
of salt is calculated and it is then compared with the solubility product of
the salt at the same temperature.</p>



<p>By knowing the molar concentration of ions in a solution and solubility product, it can be predicted whether precipitation would occur or not.  Precipitation is an ionic reaction.  According to the solubility product concept, precipitation occurs only when the ionic product exceeds solubility product. If K<sub>sp</sub> = ionic product or K<sub>sp</sub> > ionic product, then precipitation doesn’t occur.</p>



<p>In general</p>



<ul class="wp-block-list"><li>Ionic product = K<sub>sp</sub>, the solution is
saturated&nbsp;(No precipitation)</li><li>Ionic product &lt; K<sub>sp</sub>, the solution
is unsaturated(No precipitation)</li><li>Ionic product &gt; K<sub>sp</sub>, the solution
is supersaturated (precipitation)</li></ul>



<p><strong>Example:</strong></p>



<p>K<sub>sp</sub> of
BaSO<sub>4</sub> at 298 K is 1 x 10<sup>-10</sup> then for the precipita­tion
of BaSO<sub>4</sub> in the solution,</p>



<p class="has-text-align-center">ionic product [Ba<sup>++</sup>&nbsp;]
[SO4<sup>&#8211;&nbsp;&#8211;</sup>]&nbsp;&nbsp; &gt;&nbsp; K<sub>sp</sub> of BaSO<sub>4</sub></p>



<p class="has-text-align-center">[Ba<sup>++</sup> ] [SO<sub>4</sub><sup>&#8211; &#8211;</sup>]   >  1 x 10<sup>-10</sup></p>



<h4 class="wp-block-heading"><strong>Science > <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/" target="_blank">Chemistry</a> > Physical Chemistry > <a rel="noreferrer noopener" href="https://thefactfactor.com/chemistry/ionic-equilibria/" target="_blank">Ionic Equilibria</a> > Solubility Product</strong></h4>
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